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iop360Best ResponseYou've already chosen the best response.0
\[\frac{ f(x)  (33) }{ x  0 }\]
 one year ago

iop360Best ResponseYou've already chosen the best response.0
f(x) = \[f(x) = 36xsin(17x) + 306\sqrt{3}x^2 33\]
 one year ago

iop360Best ResponseYou've already chosen the best response.0
\[\frac{ f(x)  (33)}{ x0 } = f'(x)\]
 one year ago

josiahhBest ResponseYou've already chosen the best response.1
that is the derivative formula at x=0; X=0 is your answer
 one year ago

iop360Best ResponseYou've already chosen the best response.0
is it? the answers says that x = 5Pi/102 and 7Pi/102
 one year ago

josiahhBest ResponseYou've already chosen the best response.1
alright Plug in either 5pi/102 or 7pi/102 in f(x) and see if you get 33.
 one year ago

iop360Best ResponseYou've already chosen the best response.0
the original question was find the x coordinates of all points on the curve \[y = 36xsin(17x) + 306\sqrt{3}x^2 33\] with a domain of \[\frac{ \Pi }{ 34 } < x < \frac{ 3\Pi }{ 34 }\] where to tangent line passes through the point P(0, 33)
 one year ago

iop360Best ResponseYou've already chosen the best response.0
so im not sure if the rise/run formula is the right thing to do
 one year ago

iop360Best ResponseYou've already chosen the best response.0
also the point (0, 33) is actually not on the curve, but this line is touching points of the curve somewhere
 one year ago

iop360Best ResponseYou've already chosen the best response.0
which is where answer x= 5Pi/102 and 7Pi/102 comes from
 one year ago

josiahhBest ResponseYou've already chosen the best response.1
alright. let's see if we can write the equation of the tangent line
 one year ago

iop360Best ResponseYou've already chosen the best response.0
with one m being rise/ivrun and the other m being the derivativer equate the two toeeach other
 one year ago

iop360Best ResponseYou've already chosen the best response.0
dont think it works though
 one year ago

josiahhBest ResponseYou've already chosen the best response.1
yea the derivative is not defined at 0
 one year ago

iop360Best ResponseYou've already chosen the best response.0
m = m \[\frac{ f(x)  (33) }{ x  0} = f'(x)\] \[\frac{ (36xsin(17x) + 306\sqrt{3}x^2 33)  (33) }{x } = 612xcos(17x) + 36\sin(17x) + 712\sqrt{3}x\]
 one year ago

iop360Best ResponseYou've already chosen the best response.0
i tried doing this but im still not getting the correct answer
 one year ago

iop360Best ResponseYou've already chosen the best response.0
did you try getting f'(x), maybe i did it wrong
 one year ago

josiahhBest ResponseYou've already chosen the best response.1
is the x^2 in the square root?
 one year ago

josiahhBest ResponseYou've already chosen the best response.1
oh, then I was doing it all wrong... let me start over
 one year ago

josiahhBest ResponseYou've already chosen the best response.1
the slope is 0; you just have to use the x in the denominator to cancel the xs in the numerator and take the limit of that as x approaches 0
 one year ago

iop360Best ResponseYou've already chosen the best response.0
so take the limit after the rise/run formula after you factor it?
 one year ago

iop360Best ResponseYou've already chosen the best response.0
this gives you the slope, and then what do you do to get the answer
 one year ago

iop360Best ResponseYou've already chosen the best response.0
\[\lim_{x \rightarrow0}36\sin(17x) + 306\sqrt{3}x^2\]
 one year ago

iop360Best ResponseYou've already chosen the best response.0
slope equals to 0, and then...?
 one year ago

iop360Best ResponseYou've already chosen the best response.0
0 = f'(x) 0 = \[0 = 612xcos(17x) + 36\sin(17x) + 712\sqrt{3}x\]
 one year ago

iop360Best ResponseYou've already chosen the best response.0
maybe solving for x here would be the answer?
 one year ago

josiahhBest ResponseYou've already chosen the best response.1
and 7pi/102... you took the derivative wrong
 one year ago

josiahhBest ResponseYou've already chosen the best response.1
you shouldn't have 712, its 612
 one year ago

josiahhBest ResponseYou've already chosen the best response.1
and set them equal as you did before, 36sin(17x)+306(3)^(1/2)x=36sin(17x)+612xcos(17x)+612sqrt(3)x
 one year ago

iop360Best ResponseYou've already chosen the best response.0
solve for x, and thats what you get?
 one year ago

josiahhBest ResponseYou've already chosen the best response.1
\[36\sin(17x)+306sqrt(3)x=36\sin(17x)+612xcos(17x)+612\sqrt(3)x\]
 one year ago

josiahhBest ResponseYou've already chosen the best response.1
yea, x= (1/102)(12*k*pi+5pi) or x = (1/102)(12*k*pi5pi)
 one year ago

josiahhBest ResponseYou've already chosen the best response.1
n is an integer, pick n so that x is between pi/34 and 3pi/34
 one year ago

josiahhBest ResponseYou've already chosen the best response.1
hold on a second I will attach a file soon
 one year ago

josiahhBest ResponseYou've already chosen the best response.1
on the pdf file, it should not be 5pi + or  12kpi; it should be 5pi+12kpi or x=5pi+12kpi since cos(a)=cos(a); it is 2kpi + or  a with a being 5pi/6 in our case... any questions??
 one year ago

josiahhBest ResponseYou've already chosen the best response.1
I used k instead of n; its the same thing
 one year ago

iop360Best ResponseYou've already chosen the best response.0
when you isolated for k , what are you finding
 one year ago

iop360Best ResponseYou've already chosen the best response.0
is that like the period
 one year ago

josiahhBest ResponseYou've already chosen the best response.1
no; im trying to find k. x should be in a certain range. so if x is between pi/34 and 3pi/34 then (pi/34)<x<(3pi/34). this will help you find an interval for k so that your x is in the right range or domain if you want to call it that... now k should be an integer so you look at the interval of k and decide which integers are inside that interval... if you do this for 12kpi5pi; you should get k=1... pi/34<=(1/102)(12kpi5pi)<=3pi/4... try it
 one year ago
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