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anonymous
 4 years ago
solve the following for x...
anonymous
 4 years ago
solve the following for x...

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[\frac{ f(x)  (33) }{ x  0 }\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0f(x) = \[f(x) = 36xsin(17x) + 306\sqrt{3}x^2 33\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[\frac{ f(x)  (33)}{ x0 } = f'(x)\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0that is the derivative formula at x=0; X=0 is your answer

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0is it? the answers says that x = 5Pi/102 and 7Pi/102

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0alright Plug in either 5pi/102 or 7pi/102 in f(x) and see if you get 33.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0the original question was find the x coordinates of all points on the curve \[y = 36xsin(17x) + 306\sqrt{3}x^2 33\] with a domain of \[\frac{ \Pi }{ 34 } < x < \frac{ 3\Pi }{ 34 }\] where to tangent line passes through the point P(0, 33)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so im not sure if the rise/run formula is the right thing to do

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0also the point (0, 33) is actually not on the curve, but this line is touching points of the curve somewhere

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0which is where answer x= 5Pi/102 and 7Pi/102 comes from

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0alright. let's see if we can write the equation of the tangent line

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0with one m being rise/ivrun and the other m being the derivativer equate the two toeeach other

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dont think it works though

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yea the derivative is not defined at 0

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0m = m \[\frac{ f(x)  (33) }{ x  0} = f'(x)\] \[\frac{ (36xsin(17x) + 306\sqrt{3}x^2 33)  (33) }{x } = 612xcos(17x) + 36\sin(17x) + 712\sqrt{3}x\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i tried doing this but im still not getting the correct answer

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0did you try getting f'(x), maybe i did it wrong

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0is the x^2 in the square root?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0oh, then I was doing it all wrong... let me start over

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0the slope is 0; you just have to use the x in the denominator to cancel the xs in the numerator and take the limit of that as x approaches 0

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so take the limit after the rise/run formula after you factor it?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0this gives you the slope, and then what do you do to get the answer

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[\lim_{x \rightarrow0}36\sin(17x) + 306\sqrt{3}x^2\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0slope equals to 0, and then...?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.00 = f'(x) 0 = \[0 = 612xcos(17x) + 36\sin(17x) + 712\sqrt{3}x\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0maybe solving for x here would be the answer?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0the answer is 5pi/102

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0and 7pi/102... you took the derivative wrong

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0you shouldn't have 712, its 612

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0and set them equal as you did before, 36sin(17x)+306(3)^(1/2)x=36sin(17x)+612xcos(17x)+612sqrt(3)x

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0solve for x, and thats what you get?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[36\sin(17x)+306sqrt(3)x=36\sin(17x)+612xcos(17x)+612\sqrt(3)x\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yea, x= (1/102)(12*k*pi+5pi) or x = (1/102)(12*k*pi5pi)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0n is an integer, pick n so that x is between pi/34 and 3pi/34

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0hold on a second I will attach a file soon

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0on the pdf file, it should not be 5pi + or  12kpi; it should be 5pi+12kpi or x=5pi+12kpi since cos(a)=cos(a); it is 2kpi + or  a with a being 5pi/6 in our case... any questions??

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I used k instead of n; its the same thing

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0when you isolated for k , what are you finding

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0is that like the period

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0no; im trying to find k. x should be in a certain range. so if x is between pi/34 and 3pi/34 then (pi/34)<x<(3pi/34). this will help you find an interval for k so that your x is in the right range or domain if you want to call it that... now k should be an integer so you look at the interval of k and decide which integers are inside that interval... if you do this for 12kpi5pi; you should get k=1... pi/34<=(1/102)(12kpi5pi)<=3pi/4... try it

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0thanks for your help!
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