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iop360 Group TitleBest ResponseYou've already chosen the best response.0
\[\frac{ f(x)  (33) }{ x  0 }\]
 2 years ago

iop360 Group TitleBest ResponseYou've already chosen the best response.0
f(x) = \[f(x) = 36xsin(17x) + 306\sqrt{3}x^2 33\]
 2 years ago

iop360 Group TitleBest ResponseYou've already chosen the best response.0
\[\frac{ f(x)  (33)}{ x0 } = f'(x)\]
 2 years ago

josiahh Group TitleBest ResponseYou've already chosen the best response.1
that is the derivative formula at x=0; X=0 is your answer
 2 years ago

iop360 Group TitleBest ResponseYou've already chosen the best response.0
is it? the answers says that x = 5Pi/102 and 7Pi/102
 2 years ago

josiahh Group TitleBest ResponseYou've already chosen the best response.1
alright Plug in either 5pi/102 or 7pi/102 in f(x) and see if you get 33.
 2 years ago

iop360 Group TitleBest ResponseYou've already chosen the best response.0
the original question was find the x coordinates of all points on the curve \[y = 36xsin(17x) + 306\sqrt{3}x^2 33\] with a domain of \[\frac{ \Pi }{ 34 } < x < \frac{ 3\Pi }{ 34 }\] where to tangent line passes through the point P(0, 33)
 2 years ago

iop360 Group TitleBest ResponseYou've already chosen the best response.0
so im not sure if the rise/run formula is the right thing to do
 2 years ago

iop360 Group TitleBest ResponseYou've already chosen the best response.0
also the point (0, 33) is actually not on the curve, but this line is touching points of the curve somewhere
 2 years ago

iop360 Group TitleBest ResponseYou've already chosen the best response.0
which is where answer x= 5Pi/102 and 7Pi/102 comes from
 2 years ago

josiahh Group TitleBest ResponseYou've already chosen the best response.1
alright. let's see if we can write the equation of the tangent line
 2 years ago

iop360 Group TitleBest ResponseYou've already chosen the best response.0
with one m being rise/ivrun and the other m being the derivativer equate the two toeeach other
 2 years ago

iop360 Group TitleBest ResponseYou've already chosen the best response.0
dont think it works though
 2 years ago

josiahh Group TitleBest ResponseYou've already chosen the best response.1
yea the derivative is not defined at 0
 2 years ago

iop360 Group TitleBest ResponseYou've already chosen the best response.0
m = m \[\frac{ f(x)  (33) }{ x  0} = f'(x)\] \[\frac{ (36xsin(17x) + 306\sqrt{3}x^2 33)  (33) }{x } = 612xcos(17x) + 36\sin(17x) + 712\sqrt{3}x\]
 2 years ago

iop360 Group TitleBest ResponseYou've already chosen the best response.0
i tried doing this but im still not getting the correct answer
 2 years ago

iop360 Group TitleBest ResponseYou've already chosen the best response.0
did you try getting f'(x), maybe i did it wrong
 2 years ago

josiahh Group TitleBest ResponseYou've already chosen the best response.1
is the x^2 in the square root?
 2 years ago

josiahh Group TitleBest ResponseYou've already chosen the best response.1
oh, then I was doing it all wrong... let me start over
 2 years ago

josiahh Group TitleBest ResponseYou've already chosen the best response.1
the slope is 0; you just have to use the x in the denominator to cancel the xs in the numerator and take the limit of that as x approaches 0
 2 years ago

iop360 Group TitleBest ResponseYou've already chosen the best response.0
so take the limit after the rise/run formula after you factor it?
 2 years ago

iop360 Group TitleBest ResponseYou've already chosen the best response.0
of the rise/run*
 2 years ago

iop360 Group TitleBest ResponseYou've already chosen the best response.0
this gives you the slope, and then what do you do to get the answer
 2 years ago

iop360 Group TitleBest ResponseYou've already chosen the best response.0
\[\lim_{x \rightarrow0}36\sin(17x) + 306\sqrt{3}x^2\]
 2 years ago

iop360 Group TitleBest ResponseYou've already chosen the best response.0
slope equals to 0, and then...?
 2 years ago

iop360 Group TitleBest ResponseYou've already chosen the best response.0
0 = f'(x) 0 = \[0 = 612xcos(17x) + 36\sin(17x) + 712\sqrt{3}x\]
 2 years ago

iop360 Group TitleBest ResponseYou've already chosen the best response.0
maybe solving for x here would be the answer?
 2 years ago

josiahh Group TitleBest ResponseYou've already chosen the best response.1
the answer is 5pi/102
 2 years ago

iop360 Group TitleBest ResponseYou've already chosen the best response.0
oh did you get it?
 2 years ago

josiahh Group TitleBest ResponseYou've already chosen the best response.1
and 7pi/102... you took the derivative wrong
 2 years ago

josiahh Group TitleBest ResponseYou've already chosen the best response.1
you shouldn't have 712, its 612
 2 years ago

iop360 Group TitleBest ResponseYou've already chosen the best response.0
what is f'(x)?
 2 years ago

josiahh Group TitleBest ResponseYou've already chosen the best response.1
and set them equal as you did before, 36sin(17x)+306(3)^(1/2)x=36sin(17x)+612xcos(17x)+612sqrt(3)x
 2 years ago

iop360 Group TitleBest ResponseYou've already chosen the best response.0
solve for x, and thats what you get?
 2 years ago

josiahh Group TitleBest ResponseYou've already chosen the best response.1
\[36\sin(17x)+306sqrt(3)x=36\sin(17x)+612xcos(17x)+612\sqrt(3)x\]
 2 years ago

josiahh Group TitleBest ResponseYou've already chosen the best response.1
yea, x= (1/102)(12*k*pi+5pi) or x = (1/102)(12*k*pi5pi)
 2 years ago

josiahh Group TitleBest ResponseYou've already chosen the best response.1
n is an integer, pick n so that x is between pi/34 and 3pi/34
 2 years ago

iop360 Group TitleBest ResponseYou've already chosen the best response.0
oh ok, thanks!
 2 years ago

josiahh Group TitleBest ResponseYou've already chosen the best response.1
hold on a second I will attach a file soon
 2 years ago

josiahh Group TitleBest ResponseYou've already chosen the best response.1
there you go
 2 years ago

josiahh Group TitleBest ResponseYou've already chosen the best response.1
on the pdf file, it should not be 5pi + or  12kpi; it should be 5pi+12kpi or x=5pi+12kpi since cos(a)=cos(a); it is 2kpi + or  a with a being 5pi/6 in our case... any questions??
 2 years ago

josiahh Group TitleBest ResponseYou've already chosen the best response.1
I used k instead of n; its the same thing
 2 years ago

iop360 Group TitleBest ResponseYou've already chosen the best response.0
when you isolated for k , what are you finding
 2 years ago

iop360 Group TitleBest ResponseYou've already chosen the best response.0
is that like the period
 2 years ago

josiahh Group TitleBest ResponseYou've already chosen the best response.1
no; im trying to find k. x should be in a certain range. so if x is between pi/34 and 3pi/34 then (pi/34)<x<(3pi/34). this will help you find an interval for k so that your x is in the right range or domain if you want to call it that... now k should be an integer so you look at the interval of k and decide which integers are inside that interval... if you do this for 12kpi5pi; you should get k=1... pi/34<=(1/102)(12kpi5pi)<=3pi/4... try it
 2 years ago

iop360 Group TitleBest ResponseYou've already chosen the best response.0
ok i finally got it
 2 years ago

iop360 Group TitleBest ResponseYou've already chosen the best response.0
thanks for your help!
 2 years ago
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