solve the following for x...

- anonymous

solve the following for x...

- jamiebookeater

See more answers at brainly.com

At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga.
Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus.
Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this

and **thousands** of other questions

- anonymous

\[\frac{ f(x) - (-33) }{ x - 0 }\]

- anonymous

f(x) = \[f(x) = 36xsin(17x) + 306\sqrt{3}x^2 -33\]

- anonymous

x=0

Looking for something else?

Not the answer you are looking for? Search for more explanations.

## More answers

- anonymous

\[\frac{ f(x) - (-33)}{ x-0 } = f'(x)\]

- anonymous

that is the derivative formula at x=0; X=0 is your answer

- anonymous

is it? the answers says that x = 5Pi/102 and 7Pi/102

- anonymous

alright Plug in either 5pi/102 or 7pi/102 in f(x) and see if you get -33.

- anonymous

the original question was find the x coordinates of all points on the curve
\[y = 36xsin(17x) + 306\sqrt{3}x^2 -33\]
with a domain of
\[\frac{ \Pi }{ 34 } < x < \frac{ 3\Pi }{ 34 }\]
where to tangent line passes through the point P(0, -33)

- anonymous

so im not sure if the rise/run formula is the right thing to do

- anonymous

also the point (0, -33) is actually not on the curve, but this line is touching points of the curve somewhere

- anonymous

which is where answer x= 5Pi/102 and 7Pi/102 comes from

- anonymous

alright. let's see if we can write the equation of the tangent line

- anonymous

maybe?

- anonymous

with one m being rise/ivrun and the other m being the derivativer
equate the two toeeach other

- anonymous

dont think it works though

- anonymous

yea the derivative is not defined at 0

- anonymous

m = m
\[\frac{ f(x) - (-33) }{ x - 0} = f'(x)\]
\[\frac{ (36xsin(17x) + 306\sqrt{3}x^2 -33) - (-33) }{x } = 612xcos(17x) + 36\sin(17x) + 712\sqrt{3}x\]

- anonymous

i tried doing this but im still not getting the correct answer

- anonymous

did you try getting f'(x), maybe i did it wrong

- anonymous

is the x^2 in the square root?

- anonymous

no

- anonymous

oh, then I was doing it all wrong... let me start over

- anonymous

the slope is 0; you just have to use the x in the denominator to cancel the xs in the numerator and take the limit of that as x approaches 0

- anonymous

so take the limit after the rise/run formula after you factor it?

- anonymous

of the rise/run*

- anonymous

yea

- anonymous

this gives you the slope, and then what do you do to get the answer

- anonymous

\[\lim_{x \rightarrow0}36\sin(17x) + 306\sqrt{3}x^2\]

- anonymous

slope equals to 0, and then...?

- anonymous

0 = f'(x)
0 = \[0 = 612xcos(17x) + 36\sin(17x) + 712\sqrt{3}x\]

- anonymous

maybe solving for x here would be the answer?

- anonymous

the answer is 5pi/102

- anonymous

oh did you get it?

- anonymous

and 7pi/102... you took the derivative wrong

- anonymous

oh..

- anonymous

you shouldn't have 712, its 612

- anonymous

what is f'(x)?

- anonymous

ohh

- anonymous

and set them equal as you did before, 36sin(17x)+306(3)^(1/2)x=36sin(17x)+612xcos(17x)+612sqrt(3)x

- anonymous

solve for x, and thats what you get?

- anonymous

\[36\sin(17x)+306sqrt(3)x=36\sin(17x)+612xcos(17x)+612\sqrt(3)x\]

- anonymous

yea, x= (1/102)(12*k*pi+5pi) or x = (1/102)(12*k*pi-5pi)

- anonymous

n is an integer, pick n so that x is between pi/34 and 3pi/34

- anonymous

oh ok, thanks!

- anonymous

np

- anonymous

whats n?

- anonymous

hold on a second I will attach a file soon

- anonymous

there you go

##### 1 Attachment

- anonymous

on the pdf file, it should not be 5pi + or - 12kpi; it should be 5pi+12kpi or x=-5pi+12kpi since cos(-a)=cos(a); it is 2kpi + or - a with a being 5pi/6 in our case... any questions??

- anonymous

what is k?

- anonymous

I used k instead of n; its the same thing

- anonymous

oh ok

- anonymous

when you isolated for k , what are you finding

- anonymous

is that like the period

- anonymous

no; im trying to find k. x should be in a certain range. so if x is between pi/34 and 3pi/34 then (pi/34)

- anonymous

ok i finally got it

- anonymous

thanks for your help!

- anonymous

np...

Looking for something else?

Not the answer you are looking for? Search for more explanations.