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how would you solve this



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magepker728
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dw:1349555414557:dw

Decart
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a=x

magepker728
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how and why

Decart
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this is an old eqaution from Issac Newton

zzr0ck3r
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((73(x+h))  (73x))/h

magepker728
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@zzr0ck3r you replace 73x with f(a) why is that?

zzr0ck3r
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take f(x) and put in a+h for x
f(a+h) = 73(a+h)
then subtract f(a) from all that
(73(a+h)  (73a)) then put that all over h
(73(a+h)  (73a)) /h

Decart
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This is called the differance quotient

Decart
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\[\frac{ f(x+h)f(x) }{ h }\]

zzr0ck3r
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I dont think the name and its history is helping him much, as im sure they told him that in class.

Decart
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you substitute 73x for all x values

magepker728
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well thanks everyone...

zzr0ck3r
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no, this is not what you do....

zzr0ck3r
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Please stop @Decart you are saying many wrong things

zzr0ck3r
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(73a3h(73a))/h


Fgcbear16
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I'm with @zzr0ck3r. you didn't distribute your h @Decart

Decart
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you are correct i did not srry

Decart
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I had to refer to my precalculus text book it had been some time since I had this

Decart
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\[\frac{ 73(a+h)(73a) }{ h }\]