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magepker728
 2 years ago
Best ResponseYou've already chosen the best response.0dw:1349555414557:dw

Decart
 2 years ago
Best ResponseYou've already chosen the best response.1this is an old eqaution from Issac Newton

zzr0ck3r
 2 years ago
Best ResponseYou've already chosen the best response.1((73(x+h))  (73x))/h

magepker728
 2 years ago
Best ResponseYou've already chosen the best response.0@zzr0ck3r you replace 73x with f(a) why is that?

zzr0ck3r
 2 years ago
Best ResponseYou've already chosen the best response.1take f(x) and put in a+h for x f(a+h) = 73(a+h) then subtract f(a) from all that (73(a+h)  (73a)) then put that all over h (73(a+h)  (73a)) /h

Decart
 2 years ago
Best ResponseYou've already chosen the best response.1This is called the differance quotient

Decart
 2 years ago
Best ResponseYou've already chosen the best response.1\[\frac{ f(x+h)f(x) }{ h }\]

zzr0ck3r
 2 years ago
Best ResponseYou've already chosen the best response.1I dont think the name and its history is helping him much, as im sure they told him that in class.

Decart
 2 years ago
Best ResponseYou've already chosen the best response.1you substitute 73x for all x values

magepker728
 2 years ago
Best ResponseYou've already chosen the best response.0well thanks everyone...

zzr0ck3r
 2 years ago
Best ResponseYou've already chosen the best response.1no, this is not what you do....

zzr0ck3r
 2 years ago
Best ResponseYou've already chosen the best response.1Please stop @Decart you are saying many wrong things

Fgcbear16
 2 years ago
Best ResponseYou've already chosen the best response.0I'm with @zzr0ck3r. you didn't distribute your h @Decart

Decart
 2 years ago
Best ResponseYou've already chosen the best response.1you are correct i did not srry

Decart
 2 years ago
Best ResponseYou've already chosen the best response.1I had to refer to my precalculus text book it had been some time since I had this

Decart
 2 years ago
Best ResponseYou've already chosen the best response.1\[\frac{ 73(a+h)(73a) }{ h }\]
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