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magepker728 Group Title

how would you solve this

  • 2 years ago
  • 2 years ago

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  1. magepker728 Group Title
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    |dw:1349555414557:dw|

    • 2 years ago
  2. Decart Group Title
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    a=x

    • 2 years ago
  3. magepker728 Group Title
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    how and why

    • 2 years ago
  4. Decart Group Title
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    this is an old eqaution from Issac Newton

    • 2 years ago
  5. zzr0ck3r Group Title
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    ((7-3(x+h)) - (7-3x))/h

    • 2 years ago
  6. magepker728 Group Title
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    @zzr0ck3r you replace 7-3x with f(a) why is that?

    • 2 years ago
  7. zzr0ck3r Group Title
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    take f(x) and put in a+h for x f(a+h) = 7-3(a+h) then subtract f(a) from all that (7-3(a+h) - (7-3a)) then put that all over h (7-3(a+h) - (7-3a)) /h

    • 2 years ago
  8. Decart Group Title
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    This is called the differance quotient

    • 2 years ago
  9. Decart Group Title
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    \[\frac{ f(x+h)-f(x) }{ h }\]

    • 2 years ago
  10. zzr0ck3r Group Title
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    I dont think the name and its history is helping him much, as im sure they told him that in class.

    • 2 years ago
  11. Decart Group Title
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    you substitute 7-3x for all x values

    • 2 years ago
  12. magepker728 Group Title
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    well thanks everyone...

    • 2 years ago
  13. zzr0ck3r Group Title
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    no, this is not what you do....

    • 2 years ago
  14. zzr0ck3r Group Title
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    Please stop @Decart you are saying many wrong things

    • 2 years ago
  15. zzr0ck3r Group Title
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    (7-3a-3h-(7-3a))/h

    • 2 years ago
  16. Decart Group Title
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    http://www.youtube.com/watch?v=ZsNiIX6gDf0

    • 2 years ago
  17. Fgcbear16 Group Title
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    I'm with @zzr0ck3r. you didn't distribute your h @Decart

    • 2 years ago
  18. Decart Group Title
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    you are correct i did not srry

    • 2 years ago
  19. Decart Group Title
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    I had to refer to my precalculus text book it had been some time since I had this

    • 2 years ago
  20. Decart Group Title
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    \[\frac{ 7-3(a+h)-(7-3a) }{ h }\]

    • 2 years ago
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spraguer (Moderator)
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is replying to Can someone tell me what button the professor is hitting...

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