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InsanelyChaotic

  • 2 years ago

Can someone please help me with this. I'm beyond desperate at this point. Use the elimination method to solve the following system of equations.2x - y + z = -32x + 2y + 3z = 23x - 3y - z = -4 (-1, -3, -2) (1, -3, -2) (1, 3, -2) (1, 3, 2)

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  1. Decart
    • 2 years ago
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    only the last equation is equal to a number?

  2. InsanelyChaotic
    • 2 years ago
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    yes

  3. InsanelyChaotic
    • 2 years ago
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    My apologies for not breaking it down, that's how it comes to me

  4. InsanelyChaotic
    • 2 years ago
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    So far, yes, I'm writing this down so I can refer back to it

  5. richyw
    • 2 years ago
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    do you know matrix algebra?

  6. InsanelyChaotic
    • 2 years ago
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    @richyw Not that well, but if I were to look in a book and find out the gist of it, then yes

  7. richyw
    • 2 years ago
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    keep listining to cambell for now, but look it up after!

  8. InsanelyChaotic
    • 2 years ago
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    @richyw Sure thing :)

  9. Algebraic!
    • 2 years ago
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    http://i.imgur.com/CMgMz.gif

  10. Algebraic!
    • 2 years ago
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    she bailed.

  11. richyw
    • 2 years ago
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    wait I didn't read what campbel was saying. This is wrong.

  12. richyw
    • 2 years ago
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    \[2x - y + z = -32x + 2y + 3z = 23x - 3y - z = -4\] gives this system of equations\[2x-y+z=-4\]\[-32x+2y+3z=-4\]\[23x-3y-z=-4\]

  13. Decart
    • 2 years ago
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    no they are not all equal to -4

  14. Decart
    • 2 years ago
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    or are they?

  15. richyw
    • 2 years ago
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    the original post shows them all =-4, but it might have been a copy and pasting error. But what is written IS what I just showed.

  16. Decart
    • 2 years ago
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    does not seem correct

  17. richyw
    • 2 years ago
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    But your initial system is incorrect.

  18. richyw
    • 2 years ago
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    i am assuming it was a typo and will just leave though. but for future warning. What the OP posted implied that they were all equal to -4. Copying and pasting this into wolfram alpha also outputs the answer that I got when I made this assumption!

  19. Algebraic!
    • 2 years ago
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    let's do algebra homework for everyone who posts a semi-coherent question and then logs off.

  20. richyw
    • 2 years ago
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    yup I see that. I am not saying you don't understand it! I was just saying that the OP posted the incorrect question. The answer to the OP question is given here... (and is not one of the answers) http://www.wolframalpha.com/input/?i=2x+-+y+%2B+z+%3D+-32x+%2B+2y+%2B+3z+%3D+23x+-+3y+-+z+%3D+-4+

  21. Algebraic!
    • 2 years ago
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    We'll call it Open Study and get the government to pay for it.

  22. InsanelyChaotic
    • 2 years ago
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    I'm back, my apologies. My Internet went out for a short amount of time. Let me scroll up to see how far we've gotten.

  23. InsanelyChaotic
    • 2 years ago
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    @Algebraic! I didn't mean to log off, it was my mistake. And that's the way the problem was given to me. No need for bullying.

  24. InsanelyChaotic
    • 2 years ago
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    It makes sense so far, by the way

  25. Algebraic!
    • 2 years ago
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    bullying. is that your response to every situation wherein someone on the internet isn't serving your immediate interests?

  26. InsanelyChaotic
    • 2 years ago
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    @Algebraic! Come again? I have no problem in admitting to my wrongdoing, that is if i am doing wrong. All I did was explain why I suddenly disappeared to the kind people who are helping me solve this problem.

  27. Algebraic!
    • 2 years ago
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    I'm aware of 'her' past @CliffSedge

  28. CliffSedge
    • 2 years ago
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    Well, ya' know just so anyone interested can get an insight into what's going on. Enjoy.

  29. Algebraic!
    • 2 years ago
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    thanks

  30. InsanelyChaotic
    • 2 years ago
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    And the problem with needinG feedback in a subject i'm ro

  31. InsanelyChaotic
    • 2 years ago
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    I'm rocky in is

  32. Algebraic!
    • 2 years ago
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    @InsanelyChaotic nice name. apropos.

  33. richyw
    • 2 years ago
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    can you post a screen shot of what the question looks like? you are either getting bad questions, or are messing them up when posting them here. The answer to what you posted, is x=8/27 y=104/27 and -20/27. That IS the ONLY correct answer to the question. Math is not based on interpretation. What you have us DOES have those answers. So it is either you or your homework that is messing up somewhere. A screenshot is needed to determine this.

  34. richyw
    • 2 years ago
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    sorry z=-20/27

  35. InsanelyChaotic
    • 2 years ago
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    @richyw That's part of the problem. That is how I am receiving the questions. The big part of not being able to solve these solutions is not knowing how they are set up from the start.

  36. InsanelyChaotic
    • 2 years ago
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    @Algebraic! Do you honestly think I would care about what you think of a username? Of all things you could say, you point something as minor as a screen name?

  37. Algebraic!
    • 2 years ago
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    u mad?

  38. richyw
    • 2 years ago
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    @campbell_st This is what the output displays like on my screen. Does it not look like this for you?

  39. InsanelyChaotic
    • 2 years ago
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    No, I am not mad at all, I'm almost too calm right now, but thank you.

  40. Algebraic!
    • 2 years ago
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    post an ss of the page with the problem @InsanelyChaotic

  41. InsanelyChaotic
    • 2 years ago
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    What is incorrectly written? @campbell_st

  42. richyw
    • 2 years ago
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    I realize that. So we need a screen shot of the original question to determine where the error is!

  43. InsanelyChaotic
    • 2 years ago
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    He did screen shot it, this is the original one: Use the elimination method to solve the following system of equations.2x - y + z = -32x + 2y + 3z = 23x - 3y - z = -4

  44. Algebraic!
    • 2 years ago
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    ...

  45. Algebraic!
    • 2 years ago
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    no.

  46. Dido525
    • 2 years ago
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    Okay. Are the all equal to-4? Then the question become a lot easier to solve.

  47. Algebraic!
    • 2 years ago
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    the questions as it was given to you. not as you posted it to OS.

  48. Dido525
    • 2 years ago
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    I can solve it if you confirm that.

  49. richyw
    • 2 years ago
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    @InsanelyChaotic no what we need is to see a screenshot of what YOU see... What we see gives the answer that I posted.

  50. InsanelyChaotic
    • 2 years ago
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    @Algebraic! You clearly have nothing to offer here. Can you please just get off of this site since you're not wanting to contribute? I'm not even asking you to at this point. It's difficult to learn a single thing, or grasp any part of this with your sarcastic comments.

  51. InsanelyChaotic
    • 2 years ago
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    One second, @richyw

  52. Algebraic!
    • 2 years ago
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    lol no.

  53. InsanelyChaotic
    • 2 years ago
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    2x−y+z=−32x+2y+3z=23x−3y−z=−4 2x−y+z=−4 −32x+2y+3z=−4 23x−3y−z=−4

  54. Dido525
    • 2 years ago
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    There we go.

  55. Algebraic!
    • 2 years ago
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    the problem's already been solved for you. Too bad he deleted the soln. Also too bad that many people had to waste their time deciphering your equation spaghetti.

  56. InsanelyChaotic
    • 2 years ago
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    This is where I'm confused, whether it's equal to -4? That's how I personally see it as.

  57. Algebraic!
    • 2 years ago
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    post an ss or stop posting.

  58. InsanelyChaotic
    • 2 years ago
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    If I knew how to decipher it myself, believe me I wouldn't have even thought of going on here. My apologies for the mix up and my appreciation towards all who have spent their time working this with me,

  59. richyw
    • 2 years ago
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    @InsanelyChaotic Copying and pasting is NOT screen capturing. We need to see if the error is occurring BEFORE or AFTER you copy and paste it to open study. I am not trying to be rude, I am trying to help you get quality answers.

  60. InsanelyChaotic
    • 2 years ago
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    I can't screen capture it; this computer doesn't allow me to

  61. InsanelyChaotic
    • 2 years ago
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    There is no error. That's how it has been given to me.

  62. InsanelyChaotic
    • 2 years ago
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    Well, clearly there's an error in deciphering what it's asking, but that's how it is asked. I don't know how to separate the equations properly.

  63. richyw
    • 2 years ago
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    ok on your screen does it look like this \[2x - y + z = -32x + 2y + 3z = 23x - 3y - z = -4 \]or this...\[2x - y + z = -32\;\; x + 2y + 3z = 23\:\:x - 3y - z = -4\]

  64. richyw
    • 2 years ago
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    I mean is there a space between the -32 and the x?

  65. InsanelyChaotic
    • 2 years ago
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    It looks like the first one, @richyw

  66. InsanelyChaotic
    • 2 years ago
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    No space

  67. Algebraic!
    • 2 years ago
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    it's 2x-y+z =-3 2x+2y+3z=2 3x-3y-z=-4

  68. richyw
    • 2 years ago
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    ok then there is no deciphering to be done. These ARE all equal to -4 in the way you are solving the problem. There is obviously a technological issue you are having! You will need to figure these out before we can help you on open study! It's simple as that. If you show your math teacher the issue they will understand why it is a problem.

  69. InsanelyChaotic
    • 2 years ago
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    I appreciate your efforts nonetheless

  70. richyw
    • 2 years ago
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    no worries, I hope you are able to sort it out soon so you can start doing the math problems!

  71. InsanelyChaotic
    • 2 years ago
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    I appreciate it very much, really. I didn't mean to waste your time but your efforts were thoughtful.

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