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InsanelyChaotic
Group Title
Can someone please help me with this. I'm beyond desperate at this point.
Use the elimination method to solve the following system of equations.2x  y + z = 32x + 2y + 3z = 23x  3y  z = 4
(1, 3, 2)
(1, 3, 2)
(1, 3, 2)
(1, 3, 2)
 2 years ago
 2 years ago
InsanelyChaotic Group Title
Can someone please help me with this. I'm beyond desperate at this point. Use the elimination method to solve the following system of equations.2x  y + z = 32x + 2y + 3z = 23x  3y  z = 4 (1, 3, 2) (1, 3, 2) (1, 3, 2) (1, 3, 2)
 2 years ago
 2 years ago

This Question is Closed

Decart Group TitleBest ResponseYou've already chosen the best response.0
only the last equation is equal to a number?
 2 years ago

InsanelyChaotic Group TitleBest ResponseYou've already chosen the best response.0
yes
 2 years ago

InsanelyChaotic Group TitleBest ResponseYou've already chosen the best response.0
My apologies for not breaking it down, that's how it comes to me
 2 years ago

InsanelyChaotic Group TitleBest ResponseYou've already chosen the best response.0
So far, yes, I'm writing this down so I can refer back to it
 2 years ago

richyw Group TitleBest ResponseYou've already chosen the best response.1
do you know matrix algebra?
 2 years ago

InsanelyChaotic Group TitleBest ResponseYou've already chosen the best response.0
@richyw Not that well, but if I were to look in a book and find out the gist of it, then yes
 2 years ago

richyw Group TitleBest ResponseYou've already chosen the best response.1
keep listining to cambell for now, but look it up after!
 2 years ago

InsanelyChaotic Group TitleBest ResponseYou've already chosen the best response.0
@richyw Sure thing :)
 2 years ago

Algebraic! Group TitleBest ResponseYou've already chosen the best response.0
she bailed.
 2 years ago

richyw Group TitleBest ResponseYou've already chosen the best response.1
wait I didn't read what campbel was saying. This is wrong.
 2 years ago

richyw Group TitleBest ResponseYou've already chosen the best response.1
\[2x  y + z = 32x + 2y + 3z = 23x  3y  z = 4\] gives this system of equations\[2xy+z=4\]\[32x+2y+3z=4\]\[23x3yz=4\]
 2 years ago

Decart Group TitleBest ResponseYou've already chosen the best response.0
no they are not all equal to 4
 2 years ago

Decart Group TitleBest ResponseYou've already chosen the best response.0
or are they?
 2 years ago

richyw Group TitleBest ResponseYou've already chosen the best response.1
the original post shows them all =4, but it might have been a copy and pasting error. But what is written IS what I just showed.
 2 years ago

Decart Group TitleBest ResponseYou've already chosen the best response.0
does not seem correct
 2 years ago

richyw Group TitleBest ResponseYou've already chosen the best response.1
But your initial system is incorrect.
 2 years ago

richyw Group TitleBest ResponseYou've already chosen the best response.1
i am assuming it was a typo and will just leave though. but for future warning. What the OP posted implied that they were all equal to 4. Copying and pasting this into wolfram alpha also outputs the answer that I got when I made this assumption!
 2 years ago

Algebraic! Group TitleBest ResponseYou've already chosen the best response.0
let's do algebra homework for everyone who posts a semicoherent question and then logs off.
 2 years ago

richyw Group TitleBest ResponseYou've already chosen the best response.1
yup I see that. I am not saying you don't understand it! I was just saying that the OP posted the incorrect question. The answer to the OP question is given here... (and is not one of the answers) http://www.wolframalpha.com/input/?i=2x++y+%2B+z+%3D+32x+%2B+2y+%2B+3z+%3D+23x++3y++z+%3D+4+
 2 years ago

Algebraic! Group TitleBest ResponseYou've already chosen the best response.0
We'll call it Open Study and get the government to pay for it.
 2 years ago

InsanelyChaotic Group TitleBest ResponseYou've already chosen the best response.0
I'm back, my apologies. My Internet went out for a short amount of time. Let me scroll up to see how far we've gotten.
 2 years ago

InsanelyChaotic Group TitleBest ResponseYou've already chosen the best response.0
@Algebraic! I didn't mean to log off, it was my mistake. And that's the way the problem was given to me. No need for bullying.
 2 years ago

InsanelyChaotic Group TitleBest ResponseYou've already chosen the best response.0
It makes sense so far, by the way
 2 years ago

Algebraic! Group TitleBest ResponseYou've already chosen the best response.0
bullying. is that your response to every situation wherein someone on the internet isn't serving your immediate interests?
 2 years ago

InsanelyChaotic Group TitleBest ResponseYou've already chosen the best response.0
@Algebraic! Come again? I have no problem in admitting to my wrongdoing, that is if i am doing wrong. All I did was explain why I suddenly disappeared to the kind people who are helping me solve this problem.
 2 years ago

CliffSedge Group TitleBest ResponseYou've already chosen the best response.1
@campbell_st @Algebraic! @richyw See http://openstudy.com/users/insanelychaotic#/updates/506f29a6e4b060a360ff984a http://openstudy.com/users/insanelychaotic#/updates/506f244be4b060a360ff9358 http://openstudy.com/users/insanelychaotic#/updates/506f1707e4b060a360ff8890 http://openstudy.com/users/insanelychaotic#/updates/506f0c67e4b060a360ff8217 For similar difficulties.
 2 years ago

Algebraic! Group TitleBest ResponseYou've already chosen the best response.0
I'm aware of 'her' past @CliffSedge
 2 years ago

CliffSedge Group TitleBest ResponseYou've already chosen the best response.1
Well, ya' know just so anyone interested can get an insight into what's going on. Enjoy.
 2 years ago

InsanelyChaotic Group TitleBest ResponseYou've already chosen the best response.0
And the problem with needinG feedback in a subject i'm ro
 2 years ago

InsanelyChaotic Group TitleBest ResponseYou've already chosen the best response.0
I'm rocky in is
 2 years ago

Algebraic! Group TitleBest ResponseYou've already chosen the best response.0
@InsanelyChaotic nice name. apropos.
 2 years ago

richyw Group TitleBest ResponseYou've already chosen the best response.1
can you post a screen shot of what the question looks like? you are either getting bad questions, or are messing them up when posting them here. The answer to what you posted, is x=8/27 y=104/27 and 20/27. That IS the ONLY correct answer to the question. Math is not based on interpretation. What you have us DOES have those answers. So it is either you or your homework that is messing up somewhere. A screenshot is needed to determine this.
 2 years ago

richyw Group TitleBest ResponseYou've already chosen the best response.1
sorry z=20/27
 2 years ago

InsanelyChaotic Group TitleBest ResponseYou've already chosen the best response.0
@richyw That's part of the problem. That is how I am receiving the questions. The big part of not being able to solve these solutions is not knowing how they are set up from the start.
 2 years ago

InsanelyChaotic Group TitleBest ResponseYou've already chosen the best response.0
@Algebraic! Do you honestly think I would care about what you think of a username? Of all things you could say, you point something as minor as a screen name?
 2 years ago

richyw Group TitleBest ResponseYou've already chosen the best response.1
@campbell_st This is what the output displays like on my screen. Does it not look like this for you?
 2 years ago

InsanelyChaotic Group TitleBest ResponseYou've already chosen the best response.0
No, I am not mad at all, I'm almost too calm right now, but thank you.
 2 years ago

Algebraic! Group TitleBest ResponseYou've already chosen the best response.0
post an ss of the page with the problem @InsanelyChaotic
 2 years ago

InsanelyChaotic Group TitleBest ResponseYou've already chosen the best response.0
What is incorrectly written? @campbell_st
 2 years ago

richyw Group TitleBest ResponseYou've already chosen the best response.1
I realize that. So we need a screen shot of the original question to determine where the error is!
 2 years ago

InsanelyChaotic Group TitleBest ResponseYou've already chosen the best response.0
He did screen shot it, this is the original one: Use the elimination method to solve the following system of equations.2x  y + z = 32x + 2y + 3z = 23x  3y  z = 4
 2 years ago

Dido525 Group TitleBest ResponseYou've already chosen the best response.0
Okay. Are the all equal to4? Then the question become a lot easier to solve.
 2 years ago

Algebraic! Group TitleBest ResponseYou've already chosen the best response.0
the questions as it was given to you. not as you posted it to OS.
 2 years ago

Dido525 Group TitleBest ResponseYou've already chosen the best response.0
I can solve it if you confirm that.
 2 years ago

richyw Group TitleBest ResponseYou've already chosen the best response.1
@InsanelyChaotic no what we need is to see a screenshot of what YOU see... What we see gives the answer that I posted.
 2 years ago

InsanelyChaotic Group TitleBest ResponseYou've already chosen the best response.0
@Algebraic! You clearly have nothing to offer here. Can you please just get off of this site since you're not wanting to contribute? I'm not even asking you to at this point. It's difficult to learn a single thing, or grasp any part of this with your sarcastic comments.
 2 years ago

InsanelyChaotic Group TitleBest ResponseYou've already chosen the best response.0
One second, @richyw
 2 years ago

InsanelyChaotic Group TitleBest ResponseYou've already chosen the best response.0
2x−y+z=−32x+2y+3z=23x−3y−z=−4 2x−y+z=−4 −32x+2y+3z=−4 23x−3y−z=−4
 2 years ago

Dido525 Group TitleBest ResponseYou've already chosen the best response.0
There we go.
 2 years ago

Algebraic! Group TitleBest ResponseYou've already chosen the best response.0
the problem's already been solved for you. Too bad he deleted the soln. Also too bad that many people had to waste their time deciphering your equation spaghetti.
 2 years ago

InsanelyChaotic Group TitleBest ResponseYou've already chosen the best response.0
This is where I'm confused, whether it's equal to 4? That's how I personally see it as.
 2 years ago

Algebraic! Group TitleBest ResponseYou've already chosen the best response.0
post an ss or stop posting.
 2 years ago

InsanelyChaotic Group TitleBest ResponseYou've already chosen the best response.0
If I knew how to decipher it myself, believe me I wouldn't have even thought of going on here. My apologies for the mix up and my appreciation towards all who have spent their time working this with me,
 2 years ago

richyw Group TitleBest ResponseYou've already chosen the best response.1
@InsanelyChaotic Copying and pasting is NOT screen capturing. We need to see if the error is occurring BEFORE or AFTER you copy and paste it to open study. I am not trying to be rude, I am trying to help you get quality answers.
 2 years ago

InsanelyChaotic Group TitleBest ResponseYou've already chosen the best response.0
I can't screen capture it; this computer doesn't allow me to
 2 years ago

InsanelyChaotic Group TitleBest ResponseYou've already chosen the best response.0
There is no error. That's how it has been given to me.
 2 years ago

InsanelyChaotic Group TitleBest ResponseYou've already chosen the best response.0
Well, clearly there's an error in deciphering what it's asking, but that's how it is asked. I don't know how to separate the equations properly.
 2 years ago

richyw Group TitleBest ResponseYou've already chosen the best response.1
ok on your screen does it look like this \[2x  y + z = 32x + 2y + 3z = 23x  3y  z = 4 \]or this...\[2x  y + z = 32\;\; x + 2y + 3z = 23\:\:x  3y  z = 4\]
 2 years ago

richyw Group TitleBest ResponseYou've already chosen the best response.1
I mean is there a space between the 32 and the x?
 2 years ago

InsanelyChaotic Group TitleBest ResponseYou've already chosen the best response.0
It looks like the first one, @richyw
 2 years ago

InsanelyChaotic Group TitleBest ResponseYou've already chosen the best response.0
No space
 2 years ago

Algebraic! Group TitleBest ResponseYou've already chosen the best response.0
it's 2xy+z =3 2x+2y+3z=2 3x3yz=4
 2 years ago

richyw Group TitleBest ResponseYou've already chosen the best response.1
ok then there is no deciphering to be done. These ARE all equal to 4 in the way you are solving the problem. There is obviously a technological issue you are having! You will need to figure these out before we can help you on open study! It's simple as that. If you show your math teacher the issue they will understand why it is a problem.
 2 years ago

InsanelyChaotic Group TitleBest ResponseYou've already chosen the best response.0
I appreciate your efforts nonetheless
 2 years ago

richyw Group TitleBest ResponseYou've already chosen the best response.1
no worries, I hope you are able to sort it out soon so you can start doing the math problems!
 2 years ago

InsanelyChaotic Group TitleBest ResponseYou've already chosen the best response.0
I appreciate it very much, really. I didn't mean to waste your time but your efforts were thoughtful.
 2 years ago
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