Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing
InsanelyChaotic
Group Title
Can someone please help me with this. I'm beyond desperate at this point.
Use the elimination method to solve the following system of equations.2x  y + z = 32x + 2y + 3z = 23x  3y  z = 4
(1, 3, 2)
(1, 3, 2)
(1, 3, 2)
(1, 3, 2)
 one year ago
 one year ago
InsanelyChaotic Group Title
Can someone please help me with this. I'm beyond desperate at this point. Use the elimination method to solve the following system of equations.2x  y + z = 32x + 2y + 3z = 23x  3y  z = 4 (1, 3, 2) (1, 3, 2) (1, 3, 2) (1, 3, 2)
 one year ago
 one year ago

This Question is Closed

Decart Group TitleBest ResponseYou've already chosen the best response.0
only the last equation is equal to a number?
 one year ago

InsanelyChaotic Group TitleBest ResponseYou've already chosen the best response.0
yes
 one year ago

InsanelyChaotic Group TitleBest ResponseYou've already chosen the best response.0
My apologies for not breaking it down, that's how it comes to me
 one year ago

InsanelyChaotic Group TitleBest ResponseYou've already chosen the best response.0
So far, yes, I'm writing this down so I can refer back to it
 one year ago

richyw Group TitleBest ResponseYou've already chosen the best response.1
do you know matrix algebra?
 one year ago

InsanelyChaotic Group TitleBest ResponseYou've already chosen the best response.0
@richyw Not that well, but if I were to look in a book and find out the gist of it, then yes
 one year ago

richyw Group TitleBest ResponseYou've already chosen the best response.1
keep listining to cambell for now, but look it up after!
 one year ago

InsanelyChaotic Group TitleBest ResponseYou've already chosen the best response.0
@richyw Sure thing :)
 one year ago

Algebraic! Group TitleBest ResponseYou've already chosen the best response.0
she bailed.
 one year ago

richyw Group TitleBest ResponseYou've already chosen the best response.1
wait I didn't read what campbel was saying. This is wrong.
 one year ago

richyw Group TitleBest ResponseYou've already chosen the best response.1
\[2x  y + z = 32x + 2y + 3z = 23x  3y  z = 4\] gives this system of equations\[2xy+z=4\]\[32x+2y+3z=4\]\[23x3yz=4\]
 one year ago

Decart Group TitleBest ResponseYou've already chosen the best response.0
no they are not all equal to 4
 one year ago

Decart Group TitleBest ResponseYou've already chosen the best response.0
or are they?
 one year ago

richyw Group TitleBest ResponseYou've already chosen the best response.1
the original post shows them all =4, but it might have been a copy and pasting error. But what is written IS what I just showed.
 one year ago

Decart Group TitleBest ResponseYou've already chosen the best response.0
does not seem correct
 one year ago

richyw Group TitleBest ResponseYou've already chosen the best response.1
But your initial system is incorrect.
 one year ago

richyw Group TitleBest ResponseYou've already chosen the best response.1
i am assuming it was a typo and will just leave though. but for future warning. What the OP posted implied that they were all equal to 4. Copying and pasting this into wolfram alpha also outputs the answer that I got when I made this assumption!
 one year ago

Algebraic! Group TitleBest ResponseYou've already chosen the best response.0
let's do algebra homework for everyone who posts a semicoherent question and then logs off.
 one year ago

richyw Group TitleBest ResponseYou've already chosen the best response.1
yup I see that. I am not saying you don't understand it! I was just saying that the OP posted the incorrect question. The answer to the OP question is given here... (and is not one of the answers) http://www.wolframalpha.com/input/?i=2x++y+%2B+z+%3D+32x+%2B+2y+%2B+3z+%3D+23x++3y++z+%3D+4+
 one year ago

Algebraic! Group TitleBest ResponseYou've already chosen the best response.0
We'll call it Open Study and get the government to pay for it.
 one year ago

InsanelyChaotic Group TitleBest ResponseYou've already chosen the best response.0
I'm back, my apologies. My Internet went out for a short amount of time. Let me scroll up to see how far we've gotten.
 one year ago

InsanelyChaotic Group TitleBest ResponseYou've already chosen the best response.0
@Algebraic! I didn't mean to log off, it was my mistake. And that's the way the problem was given to me. No need for bullying.
 one year ago

InsanelyChaotic Group TitleBest ResponseYou've already chosen the best response.0
It makes sense so far, by the way
 one year ago

Algebraic! Group TitleBest ResponseYou've already chosen the best response.0
bullying. is that your response to every situation wherein someone on the internet isn't serving your immediate interests?
 one year ago

InsanelyChaotic Group TitleBest ResponseYou've already chosen the best response.0
@Algebraic! Come again? I have no problem in admitting to my wrongdoing, that is if i am doing wrong. All I did was explain why I suddenly disappeared to the kind people who are helping me solve this problem.
 one year ago

CliffSedge Group TitleBest ResponseYou've already chosen the best response.1
@campbell_st @Algebraic! @richyw See http://openstudy.com/users/insanelychaotic#/updates/506f29a6e4b060a360ff984a http://openstudy.com/users/insanelychaotic#/updates/506f244be4b060a360ff9358 http://openstudy.com/users/insanelychaotic#/updates/506f1707e4b060a360ff8890 http://openstudy.com/users/insanelychaotic#/updates/506f0c67e4b060a360ff8217 For similar difficulties.
 one year ago

Algebraic! Group TitleBest ResponseYou've already chosen the best response.0
I'm aware of 'her' past @CliffSedge
 one year ago

CliffSedge Group TitleBest ResponseYou've already chosen the best response.1
Well, ya' know just so anyone interested can get an insight into what's going on. Enjoy.
 one year ago

InsanelyChaotic Group TitleBest ResponseYou've already chosen the best response.0
And the problem with needinG feedback in a subject i'm ro
 one year ago

InsanelyChaotic Group TitleBest ResponseYou've already chosen the best response.0
I'm rocky in is
 one year ago

Algebraic! Group TitleBest ResponseYou've already chosen the best response.0
@InsanelyChaotic nice name. apropos.
 one year ago

richyw Group TitleBest ResponseYou've already chosen the best response.1
can you post a screen shot of what the question looks like? you are either getting bad questions, or are messing them up when posting them here. The answer to what you posted, is x=8/27 y=104/27 and 20/27. That IS the ONLY correct answer to the question. Math is not based on interpretation. What you have us DOES have those answers. So it is either you or your homework that is messing up somewhere. A screenshot is needed to determine this.
 one year ago

richyw Group TitleBest ResponseYou've already chosen the best response.1
sorry z=20/27
 one year ago

InsanelyChaotic Group TitleBest ResponseYou've already chosen the best response.0
@richyw That's part of the problem. That is how I am receiving the questions. The big part of not being able to solve these solutions is not knowing how they are set up from the start.
 one year ago

InsanelyChaotic Group TitleBest ResponseYou've already chosen the best response.0
@Algebraic! Do you honestly think I would care about what you think of a username? Of all things you could say, you point something as minor as a screen name?
 one year ago

richyw Group TitleBest ResponseYou've already chosen the best response.1
@campbell_st This is what the output displays like on my screen. Does it not look like this for you?
 one year ago

InsanelyChaotic Group TitleBest ResponseYou've already chosen the best response.0
No, I am not mad at all, I'm almost too calm right now, but thank you.
 one year ago

Algebraic! Group TitleBest ResponseYou've already chosen the best response.0
post an ss of the page with the problem @InsanelyChaotic
 one year ago

InsanelyChaotic Group TitleBest ResponseYou've already chosen the best response.0
What is incorrectly written? @campbell_st
 one year ago

richyw Group TitleBest ResponseYou've already chosen the best response.1
I realize that. So we need a screen shot of the original question to determine where the error is!
 one year ago

InsanelyChaotic Group TitleBest ResponseYou've already chosen the best response.0
He did screen shot it, this is the original one: Use the elimination method to solve the following system of equations.2x  y + z = 32x + 2y + 3z = 23x  3y  z = 4
 one year ago

Dido525 Group TitleBest ResponseYou've already chosen the best response.0
Okay. Are the all equal to4? Then the question become a lot easier to solve.
 one year ago

Algebraic! Group TitleBest ResponseYou've already chosen the best response.0
the questions as it was given to you. not as you posted it to OS.
 one year ago

Dido525 Group TitleBest ResponseYou've already chosen the best response.0
I can solve it if you confirm that.
 one year ago

richyw Group TitleBest ResponseYou've already chosen the best response.1
@InsanelyChaotic no what we need is to see a screenshot of what YOU see... What we see gives the answer that I posted.
 one year ago

InsanelyChaotic Group TitleBest ResponseYou've already chosen the best response.0
@Algebraic! You clearly have nothing to offer here. Can you please just get off of this site since you're not wanting to contribute? I'm not even asking you to at this point. It's difficult to learn a single thing, or grasp any part of this with your sarcastic comments.
 one year ago

InsanelyChaotic Group TitleBest ResponseYou've already chosen the best response.0
One second, @richyw
 one year ago

Algebraic! Group TitleBest ResponseYou've already chosen the best response.0
lol no.
 one year ago

InsanelyChaotic Group TitleBest ResponseYou've already chosen the best response.0
2x−y+z=−32x+2y+3z=23x−3y−z=−4 2x−y+z=−4 −32x+2y+3z=−4 23x−3y−z=−4
 one year ago

Dido525 Group TitleBest ResponseYou've already chosen the best response.0
There we go.
 one year ago

Algebraic! Group TitleBest ResponseYou've already chosen the best response.0
the problem's already been solved for you. Too bad he deleted the soln. Also too bad that many people had to waste their time deciphering your equation spaghetti.
 one year ago

InsanelyChaotic Group TitleBest ResponseYou've already chosen the best response.0
This is where I'm confused, whether it's equal to 4? That's how I personally see it as.
 one year ago

Algebraic! Group TitleBest ResponseYou've already chosen the best response.0
post an ss or stop posting.
 one year ago

InsanelyChaotic Group TitleBest ResponseYou've already chosen the best response.0
If I knew how to decipher it myself, believe me I wouldn't have even thought of going on here. My apologies for the mix up and my appreciation towards all who have spent their time working this with me,
 one year ago

richyw Group TitleBest ResponseYou've already chosen the best response.1
@InsanelyChaotic Copying and pasting is NOT screen capturing. We need to see if the error is occurring BEFORE or AFTER you copy and paste it to open study. I am not trying to be rude, I am trying to help you get quality answers.
 one year ago

InsanelyChaotic Group TitleBest ResponseYou've already chosen the best response.0
I can't screen capture it; this computer doesn't allow me to
 one year ago

InsanelyChaotic Group TitleBest ResponseYou've already chosen the best response.0
There is no error. That's how it has been given to me.
 one year ago

InsanelyChaotic Group TitleBest ResponseYou've already chosen the best response.0
Well, clearly there's an error in deciphering what it's asking, but that's how it is asked. I don't know how to separate the equations properly.
 one year ago

richyw Group TitleBest ResponseYou've already chosen the best response.1
ok on your screen does it look like this \[2x  y + z = 32x + 2y + 3z = 23x  3y  z = 4 \]or this...\[2x  y + z = 32\;\; x + 2y + 3z = 23\:\:x  3y  z = 4\]
 one year ago

richyw Group TitleBest ResponseYou've already chosen the best response.1
I mean is there a space between the 32 and the x?
 one year ago

InsanelyChaotic Group TitleBest ResponseYou've already chosen the best response.0
It looks like the first one, @richyw
 one year ago

InsanelyChaotic Group TitleBest ResponseYou've already chosen the best response.0
No space
 one year ago

Algebraic! Group TitleBest ResponseYou've already chosen the best response.0
it's 2xy+z =3 2x+2y+3z=2 3x3yz=4
 one year ago

richyw Group TitleBest ResponseYou've already chosen the best response.1
ok then there is no deciphering to be done. These ARE all equal to 4 in the way you are solving the problem. There is obviously a technological issue you are having! You will need to figure these out before we can help you on open study! It's simple as that. If you show your math teacher the issue they will understand why it is a problem.
 one year ago

InsanelyChaotic Group TitleBest ResponseYou've already chosen the best response.0
I appreciate your efforts nonetheless
 one year ago

richyw Group TitleBest ResponseYou've already chosen the best response.1
no worries, I hope you are able to sort it out soon so you can start doing the math problems!
 one year ago

InsanelyChaotic Group TitleBest ResponseYou've already chosen the best response.0
I appreciate it very much, really. I didn't mean to waste your time but your efforts were thoughtful.
 one year ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.