## InsanelyChaotic 3 years ago Can someone please help me with this. I'm beyond desperate at this point. Use the elimination method to solve the following system of equations.2x - y + z = -32x + 2y + 3z = 23x - 3y - z = -4 (-1, -3, -2) (1, -3, -2) (1, 3, -2) (1, 3, 2)

1. Decart

only the last equation is equal to a number?

2. InsanelyChaotic

yes

3. InsanelyChaotic

My apologies for not breaking it down, that's how it comes to me

4. InsanelyChaotic

So far, yes, I'm writing this down so I can refer back to it

5. richyw

do you know matrix algebra?

6. InsanelyChaotic

@richyw Not that well, but if I were to look in a book and find out the gist of it, then yes

7. richyw

keep listining to cambell for now, but look it up after!

8. InsanelyChaotic

@richyw Sure thing :)

9. Algebraic!
10. Algebraic!

she bailed.

11. richyw

wait I didn't read what campbel was saying. This is wrong.

12. richyw

\[2x - y + z = -32x + 2y + 3z = 23x - 3y - z = -4\] gives this system of equations\[2x-y+z=-4\]\[-32x+2y+3z=-4\]\[23x-3y-z=-4\]

13. Decart

no they are not all equal to -4

14. Decart

or are they?

15. richyw

the original post shows them all =-4, but it might have been a copy and pasting error. But what is written IS what I just showed.

16. Decart

does not seem correct

17. richyw

But your initial system is incorrect.

18. richyw

i am assuming it was a typo and will just leave though. but for future warning. What the OP posted implied that they were all equal to -4. Copying and pasting this into wolfram alpha also outputs the answer that I got when I made this assumption!

19. Algebraic!

let's do algebra homework for everyone who posts a semi-coherent question and then logs off.

20. richyw

yup I see that. I am not saying you don't understand it! I was just saying that the OP posted the incorrect question. The answer to the OP question is given here... (and is not one of the answers) http://www.wolframalpha.com/input/?i=2x+-+y+%2B+z+%3D+-32x+%2B+2y+%2B+3z+%3D+23x+-+3y+-+z+%3D+-4+

21. Algebraic!

We'll call it Open Study and get the government to pay for it.

22. InsanelyChaotic

I'm back, my apologies. My Internet went out for a short amount of time. Let me scroll up to see how far we've gotten.

23. InsanelyChaotic

@Algebraic! I didn't mean to log off, it was my mistake. And that's the way the problem was given to me. No need for bullying.

24. InsanelyChaotic

It makes sense so far, by the way

25. Algebraic!

bullying. is that your response to every situation wherein someone on the internet isn't serving your immediate interests?

26. InsanelyChaotic

@Algebraic! Come again? I have no problem in admitting to my wrongdoing, that is if i am doing wrong. All I did was explain why I suddenly disappeared to the kind people who are helping me solve this problem.

27. CliffSedge
28. Algebraic!

I'm aware of 'her' past @CliffSedge

29. CliffSedge

Well, ya' know just so anyone interested can get an insight into what's going on. Enjoy.

30. Algebraic!

thanks

31. InsanelyChaotic

And the problem with needinG feedback in a subject i'm ro

32. InsanelyChaotic

I'm rocky in is

33. Algebraic!

@InsanelyChaotic nice name. apropos.

34. richyw

can you post a screen shot of what the question looks like? you are either getting bad questions, or are messing them up when posting them here. The answer to what you posted, is x=8/27 y=104/27 and -20/27. That IS the ONLY correct answer to the question. Math is not based on interpretation. What you have us DOES have those answers. So it is either you or your homework that is messing up somewhere. A screenshot is needed to determine this.

35. richyw

sorry z=-20/27

36. InsanelyChaotic

@richyw That's part of the problem. That is how I am receiving the questions. The big part of not being able to solve these solutions is not knowing how they are set up from the start.

37. InsanelyChaotic

@Algebraic! Do you honestly think I would care about what you think of a username? Of all things you could say, you point something as minor as a screen name?

38. Algebraic!

39. richyw

@campbell_st This is what the output displays like on my screen. Does it not look like this for you?

40. InsanelyChaotic

No, I am not mad at all, I'm almost too calm right now, but thank you.

41. Algebraic!

post an ss of the page with the problem @InsanelyChaotic

42. InsanelyChaotic

What is incorrectly written? @campbell_st

43. richyw

I realize that. So we need a screen shot of the original question to determine where the error is!

44. InsanelyChaotic

He did screen shot it, this is the original one: Use the elimination method to solve the following system of equations.2x - y + z = -32x + 2y + 3z = 23x - 3y - z = -4

45. Algebraic!

...

46. Algebraic!

no.

47. Dido525

Okay. Are the all equal to-4? Then the question become a lot easier to solve.

48. Algebraic!

the questions as it was given to you. not as you posted it to OS.

49. Dido525

I can solve it if you confirm that.

50. richyw

@InsanelyChaotic no what we need is to see a screenshot of what YOU see... What we see gives the answer that I posted.

51. InsanelyChaotic

@Algebraic! You clearly have nothing to offer here. Can you please just get off of this site since you're not wanting to contribute? I'm not even asking you to at this point. It's difficult to learn a single thing, or grasp any part of this with your sarcastic comments.

52. InsanelyChaotic

One second, @richyw

53. Algebraic!

lol no.

54. InsanelyChaotic

2x−y+z=−32x+2y+3z=23x−3y−z=−4 2x−y+z=−4 −32x+2y+3z=−4 23x−3y−z=−4

55. Dido525

There we go.

56. Algebraic!

the problem's already been solved for you. Too bad he deleted the soln. Also too bad that many people had to waste their time deciphering your equation spaghetti.

57. InsanelyChaotic

This is where I'm confused, whether it's equal to -4? That's how I personally see it as.

58. Algebraic!

post an ss or stop posting.

59. InsanelyChaotic

If I knew how to decipher it myself, believe me I wouldn't have even thought of going on here. My apologies for the mix up and my appreciation towards all who have spent their time working this with me,

60. richyw

@InsanelyChaotic Copying and pasting is NOT screen capturing. We need to see if the error is occurring BEFORE or AFTER you copy and paste it to open study. I am not trying to be rude, I am trying to help you get quality answers.

61. InsanelyChaotic

I can't screen capture it; this computer doesn't allow me to

62. InsanelyChaotic

There is no error. That's how it has been given to me.

63. InsanelyChaotic

Well, clearly there's an error in deciphering what it's asking, but that's how it is asked. I don't know how to separate the equations properly.

64. richyw

ok on your screen does it look like this \[2x - y + z = -32x + 2y + 3z = 23x - 3y - z = -4 \]or this...\[2x - y + z = -32\;\; x + 2y + 3z = 23\:\:x - 3y - z = -4\]

65. richyw

I mean is there a space between the -32 and the x?

66. InsanelyChaotic

It looks like the first one, @richyw

67. InsanelyChaotic

No space

68. Algebraic!

it's 2x-y+z =-3 2x+2y+3z=2 3x-3y-z=-4

69. richyw

ok then there is no deciphering to be done. These ARE all equal to -4 in the way you are solving the problem. There is obviously a technological issue you are having! You will need to figure these out before we can help you on open study! It's simple as that. If you show your math teacher the issue they will understand why it is a problem.

70. InsanelyChaotic

71. richyw

no worries, I hope you are able to sort it out soon so you can start doing the math problems!

72. InsanelyChaotic

I appreciate it very much, really. I didn't mean to waste your time but your efforts were thoughtful.