determine the values of constant real numbers a and b, so that this function is differentiable at x= -5
f(x) = (ax^2) - 4x -76 x<=(-5)
= bx - 1 x > 5

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\[ax^2 - 4x - 76, x \le -5\]
\[bx -1, x > -5\]

answers are
a = -3
b = 26

what do i do to get the answers though

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