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spndsh

  • 3 years ago

d/dt (1-tan t/sec t)

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  1. Algebraic!
    • 3 years ago
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    you can re-write as \[1- \frac{ \sin(t) \cos(t) }{ \cos(t) }\]

  2. Algebraic!
    • 3 years ago
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    aka the derivative of -sin(t)

  3. spndsh
    • 3 years ago
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    what about 1/(1/cos)?

  4. Algebraic!
    • 3 years ago
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    =cos

  5. spndsh
    • 3 years ago
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    shouldn't is be cos-sin?

  6. spndsh
    • 3 years ago
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    *it

  7. Algebraic!
    • 3 years ago
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    why? because the problem is actually \[\frac{ d}{dt }\frac{ 1-\tan t }{\sec t }\] ?

  8. spndsh
    • 3 years ago
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    i get it now, sorry about that! thanks again

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