spndsh
d/dt (1tan t/sec t)



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Algebraic!
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you can rewrite as
\[1 \frac{ \sin(t) \cos(t) }{ \cos(t) }\]

Algebraic!
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aka
the derivative of sin(t)

spndsh
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what about 1/(1/cos)?

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=cos

spndsh
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shouldn't is be cossin?

spndsh
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*it

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why? because the problem is actually
\[\frac{ d}{dt }\frac{ 1\tan t }{\sec t }\]
?

spndsh
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i get it now, sorry about that! thanks again