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spndsh

  • 3 years ago

(a^2(1+ cos)^2+sin^2)^1/2

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  1. spndsh
    • 3 years ago
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    |dw:1349561714189:dw|

  2. spndsh
    • 3 years ago
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    sint^2=1-cost^2, so would it become (a^2(2))^1/2

  3. zepdrix
    • 3 years ago
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    |dw:1349561865986:dw| Hmm this is the approach I took, lemme know if you find it confusing :)

  4. zepdrix
    • 3 years ago
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    Woops, in the first step, that outside square should be attached to the sint, sorry about that. Just a notation error, not math :3

  5. spndsh
    • 3 years ago
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    ok i see what you did. but what about sint^2 into 1-cost^2?

  6. zepdrix
    • 3 years ago
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    |dw:1349562320913:dw| Hmmm..

  7. zepdrix
    • 3 years ago
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    |dw:1349562593839:dw| Hmmmmmm weird, getting different answers :3

  8. spndsh
    • 3 years ago
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    i agree with you, thanks!

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