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spndsh Group Title

(a^2(1+ cos)^2+sin^2)^1/2

  • 2 years ago
  • 2 years ago

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  1. spndsh Group Title
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    |dw:1349561714189:dw|

    • 2 years ago
  2. spndsh Group Title
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    sint^2=1-cost^2, so would it become (a^2(2))^1/2

    • 2 years ago
  3. zepdrix Group Title
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    |dw:1349561865986:dw| Hmm this is the approach I took, lemme know if you find it confusing :)

    • 2 years ago
  4. zepdrix Group Title
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    Woops, in the first step, that outside square should be attached to the sint, sorry about that. Just a notation error, not math :3

    • 2 years ago
  5. spndsh Group Title
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    ok i see what you did. but what about sint^2 into 1-cost^2?

    • 2 years ago
  6. zepdrix Group Title
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    |dw:1349562320913:dw| Hmmm..

    • 2 years ago
  7. zepdrix Group Title
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    |dw:1349562593839:dw| Hmmmmmm weird, getting different answers :3

    • 2 years ago
  8. spndsh Group Title
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    i agree with you, thanks!

    • 2 years ago
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