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aceace Group TitleBest ResponseYou've already chosen the best response.0
Question 5b please!!
 2 years ago

aceace Group TitleBest ResponseYou've already chosen the best response.0
What's the easy way of doing it?
 2 years ago

aceace Group TitleBest ResponseYou've already chosen the best response.0
I think the answer is three?
 2 years ago

Algebraic! Group TitleBest ResponseYou've already chosen the best response.0
there's problem a general expression for the sum, don't know what exactly it is, but it's easy enough to see... \[(\sqrt[4]{1+1} \sqrt[4]{1}) +(\sqrt[4]{1+2} \sqrt[4]{2}) + (\sqrt[4]{1+3} \sqrt[4]{3})...\] 1st and 4th terms cancel, 3rd and 6th terms cancel... etc. all terms cancel but the second and last
 2 years ago
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