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aceace
 2 years ago
Best ResponseYou've already chosen the best response.0What's the easy way of doing it?

aceace
 2 years ago
Best ResponseYou've already chosen the best response.0I think the answer is three?

Algebraic!
 2 years ago
Best ResponseYou've already chosen the best response.0there's problem a general expression for the sum, don't know what exactly it is, but it's easy enough to see... \[(\sqrt[4]{1+1} \sqrt[4]{1}) +(\sqrt[4]{1+2} \sqrt[4]{2}) + (\sqrt[4]{1+3} \sqrt[4]{3})...\] 1st and 4th terms cancel, 3rd and 6th terms cancel... etc. all terms cancel but the second and last
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