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anonymous
 4 years ago
find the slope of the line tangent to the following curve at x=1...
anonymous
 4 years ago
find the slope of the line tangent to the following curve at x=1...

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[y = \sin \left[ x  \tan(\frac{ \Pi }{ 4 }x ^{66}) \right] + x ^{\frac{ 1 }{ 1+66\Pi }}\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0slope of the line TANGENT to this curve at x =1

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[y' = \cos \left[ x  \tan(\frac{ \Pi }{ 4 }x ^{66})\right](1  \sec ^{2}(\frac{ \Pi }{ 4 }x ^{66}))(2\sec(\frac{ \Pi }{ 4 }x ^{66}))(\frac{ 33\Pi }{ 2 }x ^{65}) + \frac{ 1 }{1+66\Pi }x ^{\frac{ 1 }{ 1+66\Pi }1}\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0is what i get for the derivative

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0damn even this is too long

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0could you guys verify the derivative expression

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0if youre working on this

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0what kind of sadistic math teacher gave you this problem....

helder_edwin
 4 years ago
Best ResponseYou've already chosen the best response.0what is the power of x to the right??

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0you have to use chain rule then substitute x=1.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0your y(prime) is correct up to 2sec...

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0the above should be in place of your 2sec value... then add the derivative of that last value and substitute x=1
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