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iop360

  • 3 years ago

find the slope of the line tangent to the following curve at x=1...

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  1. iop360
    • 3 years ago
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    \[y = \sin \left[ x - \tan(\frac{ \Pi }{ 4 }x ^{66}) \right] + x ^{\frac{ 1 }{ 1+66\Pi }}\]

  2. iop360
    • 3 years ago
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    slope of the line TANGENT to this curve at x =1

  3. iop360
    • 3 years ago
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    answer: -99Pi

  4. iop360
    • 3 years ago
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    \[y' = \cos \left[ x - \tan(\frac{ \Pi }{ 4 }x ^{66})\right](1 - \sec ^{2}(\frac{ \Pi }{ 4 }x ^{66}))(2\sec(\frac{ \Pi }{ 4 }x ^{66}))(\frac{ 33\Pi }{ 2 }x ^{65}) + \frac{ 1 }{1+66\Pi }x ^{\frac{ 1 }{ 1+66\Pi }-1}\]

  5. iop360
    • 3 years ago
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    is what i get for the derivative

  6. iop360
    • 3 years ago
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    damn even this is too long

  7. iop360
    • 3 years ago
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    could you guys verify the derivative expression

  8. iop360
    • 3 years ago
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    if youre working on this

  9. Edutopia
    • 3 years ago
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    what kind of sadistic math teacher gave you this problem....

  10. helder_edwin
    • 3 years ago
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    what is the power of x to the right??

  11. Edutopia
    • 3 years ago
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    you have to use chain rule then substitute x=1.

  12. Edutopia
    • 3 years ago
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    your y(prime) is correct up to 2sec...

  13. Edutopia
    • 3 years ago
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    \[66pix^{65}/4\]

  14. Edutopia
    • 3 years ago
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    the above should be in place of your 2sec value... then add the derivative of that last value and substitute x=1

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