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andriod09
 4 years ago
Algebra II question, a fraction on top of a fraction, please help me!
andriod09
 4 years ago
Algebra II question, a fraction on top of a fraction, please help me!

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0a fraction on top of a fraction can be rewritten as say (2/3)/(3/4) then you can flip the second one because to divide you multiply by the reciprocal (2/3)*(4/3) then you multiply across the fractions (2*4)/(3*3).

andriod09
 4 years ago
Best ResponseYou've already chosen the best response.0\[\huge\frac{\frac{30x^2+27x+6}{9x^249}}{\frac{30x+15}{30x70}}\] That is the fraction.

Hero
 4 years ago
Best ResponseYou've already chosen the best response.0Put a divide sign between both of them, then put them next to each other. You'll know what to do then.

Hero
 4 years ago
Best ResponseYou've already chosen the best response.0\[\huge\frac{30x^2+27x+6}{9x^249} \div \frac{30x+15}{30x70} \]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0((30x2+27x+6)/(9x2−49))/((30x+15)/(30x−70)) is where we start. then you can flip the bottom half and multiply ((30x2+27x+6)/(9x2−49))*((30x−70)/(30x+15)) then you just multiply though ((30x2+27x+6)*(30x−70))/((9x2−49)*(30x+15))

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yeah so flip that second fraction

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i really have to learn how to use the equation bar

andriod09
 4 years ago
Best ResponseYou've already chosen the best response.0@cpattison you should use the \\[LaTeX\] by using the \[\\] minus the \ in the middle.

Hero
 4 years ago
Best ResponseYou've already chosen the best response.0I just copied and pasted what @andriod09 wrote with a few minor changes :P

andriod09
 4 years ago
Best ResponseYou've already chosen the best response.0\[\huge\text iknowhowtouseLaTeX\]

andriod09
 4 years ago
Best ResponseYou've already chosen the best response.0the answer isn't supposed to be like that. it is supposed to be on top of each other though. thats what it says. the answer it: \[\frac{2(5x+2)}{(x7)}\]

Hero
 4 years ago
Best ResponseYou've already chosen the best response.0You failed to execute the proper steps. That's why you didn't get it right

Hero
 4 years ago
Best ResponseYou've already chosen the best response.0Did you flip the second fraction?

andriod09
 4 years ago
Best ResponseYou've already chosen the best response.0no. i don't know how to solve it like that, you have to factor it out is what the book says, but i don't get it.

Hero
 4 years ago
Best ResponseYou've already chosen the best response.0If you had \[\frac{3}{6} \div \frac{3}{9}\] you would have no clue what to do?

andriod09
 4 years ago
Best ResponseYou've already chosen the best response.0thats simple: \[\frac{3}{6}\div\frac{3}{9}=\frac{1.5}{1}\]

Hero
 4 years ago
Best ResponseYou've already chosen the best response.0actually, you have it but you failed to execuate the reciprocal rule

Hero
 4 years ago
Best ResponseYou've already chosen the best response.0\[\frac{3}{6}\div\frac{3}{9}=\frac{3}{6} \times \frac{9}{3} = \frac{3}{2}\]

Hero
 4 years ago
Best ResponseYou've already chosen the best response.0But really, you're supposed to do the reciprocal then reduce in this manner: \[\frac{3}{6}\div\frac{3}{9}=\frac{3}{6} \times \frac{9}{3} =\frac{1}{2} \times 3= \frac{3}{2}\]

Hero
 4 years ago
Best ResponseYou've already chosen the best response.0Show me the full steps of how you got 1.5 from 3/6 div 3/9 @andriod09

Hero
 4 years ago
Best ResponseYou've already chosen the best response.0You must have used a calculator bro, lol

Hero
 4 years ago
Best ResponseYou've already chosen the best response.0Because you never divide by fractions to get a decimal. Only a calculator would do that.

andriod09
 4 years ago
Best ResponseYou've already chosen the best response.0\[\frac{3}{6}\div\frac{3}{9}=\frac{3}{6}\times\frac{9}{3}=\frac{1}{2}\times3=\frac{3}{2}\]

andriod09
 4 years ago
Best ResponseYou've already chosen the best response.0btw, hero i literally typed all that out.

Hero
 4 years ago
Best ResponseYou've already chosen the best response.0Good for you. Now do your original problem in the same manner.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1349572930013:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1349573068242:dw

Hero
 4 years ago
Best ResponseYou've already chosen the best response.0Don't forget to reduce before executing

andriod09
 4 years ago
Best ResponseYou've already chosen the best response.0that doesn't help me any @cpattison

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1349573260282:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i'm trying to work this out too by the way

andriod09
 4 years ago
Best ResponseYou've already chosen the best response.0can you please use the \[LaTeX\]

andriod09
 4 years ago
Best ResponseYou've already chosen the best response.0just use the equation button if need be.

Hero
 4 years ago
Best ResponseYou've already chosen the best response.0Try not to do it the hard way @cpattison

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[\frac{ 30(10x^2+9x+2)(3x7) }{ 15(9x^24)(2x+1) }\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i'm not sure i know the easy way. enlighten me?

Hero
 4 years ago
Best ResponseYou've already chosen the best response.0First I'd have to make sure you're even doing this correctly

andriod09
 4 years ago
Best ResponseYou've already chosen the best response.0How is that the answer though... the answer, from the book, says that the answer is: \[\frac{2(5x+2)}{3x+7}\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i don't know how that happened unless we all have done something wrong. i get \[\frac{ 2(25x^227x14) }{ 9x^24 }\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0if i were you i would try and find someone in my class or around me to ask, and double check your equations

andriod09
 4 years ago
Best ResponseYou've already chosen the best response.0A)im homeschooled, B)this is me catching up

Hero
 4 years ago
Best ResponseYou've already chosen the best response.0I was following what @cpattison did. I'm sure I would have gotten it if I had taken my own approach.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Extremesovermeans, anyone? \[\large \frac{\frac{a}{b}}{\frac{c}{d}} = \frac{ad}{bc}\]

Hero
 4 years ago
Best ResponseYou've already chosen the best response.0Yep, @cpattison made a mistake because 9x^2  49 is in the denominator

andriod09
 4 years ago
Best ResponseYou've already chosen the best response.0cliff. dafaq/dahell does that even mean????

Hero
 4 years ago
Best ResponseYou've already chosen the best response.0\[\frac{ 2(5x+2)(3x7) }{(3x+7)(3x7) }\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0oh okay. sorry for that.

Hero
 4 years ago
Best ResponseYou've already chosen the best response.0And now the 3x  7 reduces to: \[\frac{ 2(5x+2) }{(3x+7) }\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0@andriod09 "extremesovermeans" dw:1349575148786:dw

Hero
 4 years ago
Best ResponseYou've already chosen the best response.0I already know about means over extremes. I was just trying to explain it in a way that @andriod09 should have already been familiar with.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0(It's the same thing . . )

andriod09
 4 years ago
Best ResponseYou've already chosen the best response.0I don't understand it.... \[:{\]

Hero
 4 years ago
Best ResponseYou've already chosen the best response.0You ignored the part where I said something "he should have already been familiar with".

Hero
 4 years ago
Best ResponseYou've already chosen the best response.0Normal students other than @Cliffsedge learn how to change division to multiplication by flipping the second fraction.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0It's the same thing . . .

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1349575395748:dw

Hero
 4 years ago
Best ResponseYou've already chosen the best response.0I know that bro, but you should have registered that I was trying to show the poor kid something he should have already been familiar with. Ask the majority of students at a school what means over extremes mean and they'll give you a blank stare.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0http://www.khanacademy.org/math/arithmetic/fractions/v/dividingfractions this could help. he's great

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Anyway, I was merely offering a method that might have been recognized. It wasn't, carry on.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0@Hero , but did you notice that I didn't just pop in and say, "extremesovermeans, yo!" and leave? I gave a formula that should be immediately recognized by the more modern phrasing of "keepflipchange." I'll just leave now, because I don't want you to continue derailing the thread just to bark at me.

Hero
 4 years ago
Best ResponseYou've already chosen the best response.0I'm not a dog, so unfortunately I don't know how to bark.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0none of that helps. @andriod09 is there anything else?

andriod09
 4 years ago
Best ResponseYou've already chosen the best response.0yea. i would like to understand how to work the stupid fraction problem. :{

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0did khan help at all?

Hero
 4 years ago
Best ResponseYou've already chosen the best response.0I could have sworn I just showed you. I suppose now you need help with factoring and reducing polynomials.

andriod09
 4 years ago
Best ResponseYou've already chosen the best response.0cp, i don't havethe time for khan, but yes, Sam is a really good tutor. i have been to that site nealy a year now. And Hero, YES PLEASE.

andriod09
 4 years ago
Best ResponseYou've already chosen the best response.0@Hero are you still here??

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[\frac{\frac{30x^2+27x+6}{9x^249}}{\frac{30x+15}{30x70}}=\frac{30x^2+27x+6}{9x^249}\times \frac{30x70}{30x+15}\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0factor and cancel if you can

jiteshmeghwal9
 4 years ago
Best ResponseYou've already chosen the best response.2A type of complex fraction\[\huge\frac{\frac{30x^2+27x+6}{9x^249}}{\frac{30x+15}{30x70}}\]\[\LARGE{\frac{30x^2+27x+6}{9x^249} \div \frac{30x+15}{30x70}}\]\[\LARGE{\frac{30x^2+27x+6}{9x^249} \times \frac{30x70}{30x+15}}\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0for example \(9x^249=(3x+7)(3x7)\)

andriod09
 4 years ago
Best ResponseYou've already chosen the best response.0ENGLISH PLEASE. K'THANKS

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0and \(30x70=10(x7)\) etc etc. there will be an orgy of cancellation

andriod09
 4 years ago
Best ResponseYou've already chosen the best response.0can you please type that in English for me, step by step?

andriod09
 4 years ago
Best ResponseYou've already chosen the best response.0@jiteshmeghwal9 2 things, 1) i luv your prof pic, 2) what do i do after all that> I dont get... :{

jiteshmeghwal9
 4 years ago
Best ResponseYou've already chosen the best response.2bro first factor the numerators & denominators of both fractions then tell me what do u gt ?

jiteshmeghwal9
 4 years ago
Best ResponseYou've already chosen the best response.2what u haven't studied factorization yet

jiteshmeghwal9
 4 years ago
Best ResponseYou've already chosen the best response.2without studying factorization u can't do this question :(

andriod09
 4 years ago
Best ResponseYou've already chosen the best response.0not for fractions. i can factor \[x^2+10x+20\] easily. just not for fractions. plus, im homeschooled, so things aren't the same for me.

jiteshmeghwal9
 4 years ago
Best ResponseYou've already chosen the best response.2so factor \[30x^2+27x+6\]

andriod09
 4 years ago
Best ResponseYou've already chosen the best response.0\[30x^2+27x+6\] should i find a comon factor? because i don't think there is one. buy anyway. isn't it: \[2(5x+2)\]

jiteshmeghwal9
 4 years ago
Best ResponseYou've already chosen the best response.2\[ax^2+(a+b)x+b\]use this identity

andriod09
 4 years ago
Best ResponseYou've already chosen the best response.0thas makes no sense to me. :/

jiteshmeghwal9
 4 years ago
Best ResponseYou've already chosen the best response.2i mean break the middle term such that the sum becomes 27x & product becomes \(30x^2*6\)

andriod09
 4 years ago
Best ResponseYou've already chosen the best response.0but was the answer right? it should be right.

jiteshmeghwal9
 4 years ago
Best ResponseYou've already chosen the best response.2but after multiplying that u r not getting the right exression

jiteshmeghwal9
 4 years ago
Best ResponseYou've already chosen the best response.2\[30x^2+15x+12x+6\]\[15x(2x+1)+6(2x+1)\]\[(15x+6)(2x+1)\]

jiteshmeghwal9
 4 years ago
Best ResponseYou've already chosen the best response.2\[(3x)^2(7)^2\]\[(3x+7)(3x7)\]

jiteshmeghwal9
 4 years ago
Best ResponseYou've already chosen the best response.2\[30x70\]\[10(3x7)\]

jiteshmeghwal9
 4 years ago
Best ResponseYou've already chosen the best response.2\[30x+15\]\[15(2x+1)\]

jiteshmeghwal9
 4 years ago
Best ResponseYou've already chosen the best response.2\[\frac{(15x+6)(2x+1)15(2x+1)}{(3x+7)(3x7)10(3x7)}\]

jiteshmeghwal9
 4 years ago
Best ResponseYou've already chosen the best response.2bye & thanx for liking my profile profile pic
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