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Algebra II question, a fraction on top of a fraction, please help me!
 one year ago
 one year ago
Algebra II question, a fraction on top of a fraction, please help me!
 one year ago
 one year ago

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cpattisonBest ResponseYou've already chosen the best response.0
a fraction on top of a fraction can be rewritten as say (2/3)/(3/4) then you can flip the second one because to divide you multiply by the reciprocal (2/3)*(4/3) then you multiply across the fractions (2*4)/(3*3).
 one year ago

andriod09Best ResponseYou've already chosen the best response.0
\[\huge\frac{\frac{30x^2+27x+6}{9x^249}}{\frac{30x+15}{30x70}}\] That is the fraction.
 one year ago

HeroBest ResponseYou've already chosen the best response.0
Put a divide sign between both of them, then put them next to each other. You'll know what to do then.
 one year ago

HeroBest ResponseYou've already chosen the best response.0
\[\huge\frac{30x^2+27x+6}{9x^249} \div \frac{30x+15}{30x70} \]
 one year ago

cpattisonBest ResponseYou've already chosen the best response.0
((30x2+27x+6)/(9x2−49))/((30x+15)/(30x−70)) is where we start. then you can flip the bottom half and multiply ((30x2+27x+6)/(9x2−49))*((30x−70)/(30x+15)) then you just multiply though ((30x2+27x+6)*(30x−70))/((9x2−49)*(30x+15))
 one year ago

cpattisonBest ResponseYou've already chosen the best response.0
yeah so flip that second fraction
 one year ago

cpattisonBest ResponseYou've already chosen the best response.0
i really have to learn how to use the equation bar
 one year ago

andriod09Best ResponseYou've already chosen the best response.0
@cpattison you should use the \\[LaTeX\] by using the \[\\] minus the \ in the middle.
 one year ago

HeroBest ResponseYou've already chosen the best response.0
I just copied and pasted what @andriod09 wrote with a few minor changes :P
 one year ago

andriod09Best ResponseYou've already chosen the best response.0
\[\huge\text iknowhowtouseLaTeX\]
 one year ago

andriod09Best ResponseYou've already chosen the best response.0
the answer isn't supposed to be like that. it is supposed to be on top of each other though. thats what it says. the answer it: \[\frac{2(5x+2)}{(x7)}\]
 one year ago

HeroBest ResponseYou've already chosen the best response.0
You failed to execute the proper steps. That's why you didn't get it right
 one year ago

HeroBest ResponseYou've already chosen the best response.0
Did you flip the second fraction?
 one year ago

andriod09Best ResponseYou've already chosen the best response.0
no. i don't know how to solve it like that, you have to factor it out is what the book says, but i don't get it.
 one year ago

HeroBest ResponseYou've already chosen the best response.0
If you had \[\frac{3}{6} \div \frac{3}{9}\] you would have no clue what to do?
 one year ago

andriod09Best ResponseYou've already chosen the best response.0
thats simple: \[\frac{3}{6}\div\frac{3}{9}=\frac{1.5}{1}\]
 one year ago

HeroBest ResponseYou've already chosen the best response.0
actually, you have it but you failed to execuate the reciprocal rule
 one year ago

HeroBest ResponseYou've already chosen the best response.0
\[\frac{3}{6}\div\frac{3}{9}=\frac{3}{6} \times \frac{9}{3} = \frac{3}{2}\]
 one year ago

HeroBest ResponseYou've already chosen the best response.0
But really, you're supposed to do the reciprocal then reduce in this manner: \[\frac{3}{6}\div\frac{3}{9}=\frac{3}{6} \times \frac{9}{3} =\frac{1}{2} \times 3= \frac{3}{2}\]
 one year ago

HeroBest ResponseYou've already chosen the best response.0
Show me the full steps of how you got 1.5 from 3/6 div 3/9 @andriod09
 one year ago

HeroBest ResponseYou've already chosen the best response.0
You must have used a calculator bro, lol
 one year ago

HeroBest ResponseYou've already chosen the best response.0
Because you never divide by fractions to get a decimal. Only a calculator would do that.
 one year ago

andriod09Best ResponseYou've already chosen the best response.0
\[\frac{3}{6}\div\frac{3}{9}=\frac{3}{6}\times\frac{9}{3}=\frac{1}{2}\times3=\frac{3}{2}\]
 one year ago

andriod09Best ResponseYou've already chosen the best response.0
btw, hero i literally typed all that out.
 one year ago

HeroBest ResponseYou've already chosen the best response.0
Good for you. Now do your original problem in the same manner.
 one year ago

cpattisonBest ResponseYou've already chosen the best response.0
dw:1349572930013:dw
 one year ago

cpattisonBest ResponseYou've already chosen the best response.0
dw:1349573068242:dw
 one year ago

HeroBest ResponseYou've already chosen the best response.0
Don't forget to reduce before executing
 one year ago

andriod09Best ResponseYou've already chosen the best response.0
that doesn't help me any @cpattison
 one year ago

cpattisonBest ResponseYou've already chosen the best response.0
dw:1349573260282:dw
 one year ago

cpattisonBest ResponseYou've already chosen the best response.0
i'm trying to work this out too by the way
 one year ago

andriod09Best ResponseYou've already chosen the best response.0
can you please use the \[LaTeX\]
 one year ago

andriod09Best ResponseYou've already chosen the best response.0
just use the equation button if need be.
 one year ago

HeroBest ResponseYou've already chosen the best response.0
Try not to do it the hard way @cpattison
 one year ago

cpattisonBest ResponseYou've already chosen the best response.0
\[\frac{ 30(10x^2+9x+2)(3x7) }{ 15(9x^24)(2x+1) }\]
 one year ago

cpattisonBest ResponseYou've already chosen the best response.0
i'm not sure i know the easy way. enlighten me?
 one year ago

HeroBest ResponseYou've already chosen the best response.0
First I'd have to make sure you're even doing this correctly
 one year ago

andriod09Best ResponseYou've already chosen the best response.0
How is that the answer though... the answer, from the book, says that the answer is: \[\frac{2(5x+2)}{3x+7}\]
 one year ago

cpattisonBest ResponseYou've already chosen the best response.0
i don't know how that happened unless we all have done something wrong. i get \[\frac{ 2(25x^227x14) }{ 9x^24 }\]
 one year ago

cpattisonBest ResponseYou've already chosen the best response.0
if i were you i would try and find someone in my class or around me to ask, and double check your equations
 one year ago

andriod09Best ResponseYou've already chosen the best response.0
A)im homeschooled, B)this is me catching up
 one year ago

HeroBest ResponseYou've already chosen the best response.0
I was following what @cpattison did. I'm sure I would have gotten it if I had taken my own approach.
 one year ago

CliffSedgeBest ResponseYou've already chosen the best response.0
Extremesovermeans, anyone? \[\large \frac{\frac{a}{b}}{\frac{c}{d}} = \frac{ad}{bc}\]
 one year ago

HeroBest ResponseYou've already chosen the best response.0
Yep, @cpattison made a mistake because 9x^2  49 is in the denominator
 one year ago

andriod09Best ResponseYou've already chosen the best response.0
cliff. dafaq/dahell does that even mean????
 one year ago

HeroBest ResponseYou've already chosen the best response.0
\[\frac{ 2(5x+2)(3x7) }{(3x+7)(3x7) }\]
 one year ago

cpattisonBest ResponseYou've already chosen the best response.0
oh okay. sorry for that.
 one year ago

HeroBest ResponseYou've already chosen the best response.0
And now the 3x  7 reduces to: \[\frac{ 2(5x+2) }{(3x+7) }\]
 one year ago

CliffSedgeBest ResponseYou've already chosen the best response.0
@andriod09 "extremesovermeans" dw:1349575148786:dw
 one year ago

HeroBest ResponseYou've already chosen the best response.0
I already know about means over extremes. I was just trying to explain it in a way that @andriod09 should have already been familiar with.
 one year ago

CliffSedgeBest ResponseYou've already chosen the best response.0
(It's the same thing . . )
 one year ago

andriod09Best ResponseYou've already chosen the best response.0
I don't understand it.... \[:{\]
 one year ago

HeroBest ResponseYou've already chosen the best response.0
You ignored the part where I said something "he should have already been familiar with".
 one year ago

HeroBest ResponseYou've already chosen the best response.0
Normal students other than @Cliffsedge learn how to change division to multiplication by flipping the second fraction.
 one year ago

CliffSedgeBest ResponseYou've already chosen the best response.0
It's the same thing . . .
 one year ago

CliffSedgeBest ResponseYou've already chosen the best response.0
dw:1349575395748:dw
 one year ago

HeroBest ResponseYou've already chosen the best response.0
I know that bro, but you should have registered that I was trying to show the poor kid something he should have already been familiar with. Ask the majority of students at a school what means over extremes mean and they'll give you a blank stare.
 one year ago

cpattisonBest ResponseYou've already chosen the best response.0
http://www.khanacademy.org/math/arithmetic/fractions/v/dividingfractions this could help. he's great
 one year ago

CliffSedgeBest ResponseYou've already chosen the best response.0
Anyway, I was merely offering a method that might have been recognized. It wasn't, carry on.
 one year ago

CliffSedgeBest ResponseYou've already chosen the best response.0
@Hero , but did you notice that I didn't just pop in and say, "extremesovermeans, yo!" and leave? I gave a formula that should be immediately recognized by the more modern phrasing of "keepflipchange." I'll just leave now, because I don't want you to continue derailing the thread just to bark at me.
 one year ago

HeroBest ResponseYou've already chosen the best response.0
I'm not a dog, so unfortunately I don't know how to bark.
 one year ago

cpattisonBest ResponseYou've already chosen the best response.0
none of that helps. @andriod09 is there anything else?
 one year ago

andriod09Best ResponseYou've already chosen the best response.0
yea. i would like to understand how to work the stupid fraction problem. :{
 one year ago

cpattisonBest ResponseYou've already chosen the best response.0
did khan help at all?
 one year ago

HeroBest ResponseYou've already chosen the best response.0
I could have sworn I just showed you. I suppose now you need help with factoring and reducing polynomials.
 one year ago

andriod09Best ResponseYou've already chosen the best response.0
cp, i don't havethe time for khan, but yes, Sam is a really good tutor. i have been to that site nealy a year now. And Hero, YES PLEASE.
 one year ago

andriod09Best ResponseYou've already chosen the best response.0
@Hero are you still here??
 one year ago

satellite73Best ResponseYou've already chosen the best response.1
\[\frac{\frac{30x^2+27x+6}{9x^249}}{\frac{30x+15}{30x70}}=\frac{30x^2+27x+6}{9x^249}\times \frac{30x70}{30x+15}\]
 one year ago

satellite73Best ResponseYou've already chosen the best response.1
factor and cancel if you can
 one year ago

jiteshmeghwal9Best ResponseYou've already chosen the best response.2
A type of complex fraction\[\huge\frac{\frac{30x^2+27x+6}{9x^249}}{\frac{30x+15}{30x70}}\]\[\LARGE{\frac{30x^2+27x+6}{9x^249} \div \frac{30x+15}{30x70}}\]\[\LARGE{\frac{30x^2+27x+6}{9x^249} \times \frac{30x70}{30x+15}}\]
 one year ago

satellite73Best ResponseYou've already chosen the best response.1
for example \(9x^249=(3x+7)(3x7)\)
 one year ago

andriod09Best ResponseYou've already chosen the best response.0
ENGLISH PLEASE. K'THANKS
 one year ago

satellite73Best ResponseYou've already chosen the best response.1
and \(30x70=10(x7)\) etc etc. there will be an orgy of cancellation
 one year ago

andriod09Best ResponseYou've already chosen the best response.0
can you please type that in English for me, step by step?
 one year ago

andriod09Best ResponseYou've already chosen the best response.0
@jiteshmeghwal9 2 things, 1) i luv your prof pic, 2) what do i do after all that> I dont get... :{
 one year ago

jiteshmeghwal9Best ResponseYou've already chosen the best response.2
bro first factor the numerators & denominators of both fractions then tell me what do u gt ?
 one year ago

jiteshmeghwal9Best ResponseYou've already chosen the best response.2
what u haven't studied factorization yet
 one year ago

jiteshmeghwal9Best ResponseYou've already chosen the best response.2
without studying factorization u can't do this question :(
 one year ago

andriod09Best ResponseYou've already chosen the best response.0
not for fractions. i can factor \[x^2+10x+20\] easily. just not for fractions. plus, im homeschooled, so things aren't the same for me.
 one year ago

jiteshmeghwal9Best ResponseYou've already chosen the best response.2
so factor \[30x^2+27x+6\]
 one year ago

andriod09Best ResponseYou've already chosen the best response.0
\[30x^2+27x+6\] should i find a comon factor? because i don't think there is one. buy anyway. isn't it: \[2(5x+2)\]
 one year ago

jiteshmeghwal9Best ResponseYou've already chosen the best response.2
\[ax^2+(a+b)x+b\]use this identity
 one year ago

andriod09Best ResponseYou've already chosen the best response.0
thas makes no sense to me. :/
 one year ago

jiteshmeghwal9Best ResponseYou've already chosen the best response.2
i mean break the middle term such that the sum becomes 27x & product becomes \(30x^2*6\)
 one year ago

andriod09Best ResponseYou've already chosen the best response.0
but was the answer right? it should be right.
 one year ago

jiteshmeghwal9Best ResponseYou've already chosen the best response.2
but after multiplying that u r not getting the right exression
 one year ago

jiteshmeghwal9Best ResponseYou've already chosen the best response.2
\[30x^2+15x+12x+6\]\[15x(2x+1)+6(2x+1)\]\[(15x+6)(2x+1)\]
 one year ago

jiteshmeghwal9Best ResponseYou've already chosen the best response.2
\[(3x)^2(7)^2\]\[(3x+7)(3x7)\]
 one year ago

jiteshmeghwal9Best ResponseYou've already chosen the best response.2
\[30x70\]\[10(3x7)\]
 one year ago

jiteshmeghwal9Best ResponseYou've already chosen the best response.2
\[30x+15\]\[15(2x+1)\]
 one year ago

jiteshmeghwal9Best ResponseYou've already chosen the best response.2
\[\frac{(15x+6)(2x+1)15(2x+1)}{(3x+7)(3x7)10(3x7)}\]
 one year ago

jiteshmeghwal9Best ResponseYou've already chosen the best response.2
bye & thanx for liking my profile profile pic
 one year ago
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