Quantcast

Got Homework?

Connect with other students for help. It's a free community.

  • across
    MIT Grad Student
    Online now
  • laura*
    Helped 1,000 students
    Online now
  • Hero
    College Math Guru
    Online now

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

amrit_srovar Group Title

A plane flies with a speed of 278 mps along a course which passes over an anti-aircraft gun on the ground. The airplane is at an altitude of 5390 m. If the muzzle velocity of the projectile is 735 mps with a slope of 4 vertical to 3 horizontal, determine the angle between the horizontal and the line of sight at which the projectile must be fired in order to hit the airplane during the upward motion of the projectile.

  • one year ago
  • one year ago

  • This Question is Closed
  1. Fellowroot Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    Is it meters per second or miles per second?

    • one year ago
  2. amrit_srovar Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    meters per second

    • one year ago
  3. Fellowroot Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    I know you may not like this, but I'm going to say that the bullet never touches the aircraft. I may off on something, but I think I'm right.

    • one year ago
  4. amrit_srovar Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    is ur conclusion based on any solution or....?

    • one year ago
  5. Fellowroot Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    • one year ago
    1 Attachment
  6. Fellowroot Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    I think I see where I'm wrong. It has to do with the bullet velocity. I'll redo.

    • one year ago
  7. amrit_srovar Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    ok

    • one year ago
  8. Fellowroot Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    I need to know what this muzzle velocity of the projectile is 735 mps is?

    • one year ago
  9. amrit_srovar Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    the muzzle velocity is the velocity of the projectile of the bullet as it leaves the muzzle of the gun. it is 735 mps

    • one year ago
  10. Fellowroot Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    Is it a horizontal component or vertical component or both or what. It tells me the slope but you can't use it directly because its probably a reduced form the slope. Slope is velocity and they say 4 up and 3 right, but you can't take those values literally. 8/6 is same as 4/3 so we don't know.

    • one year ago
  11. Fellowroot Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    Is it 735 in the vertical or horizontal? That's what I need to know.

    • one year ago
  12. amrit_srovar Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    well, i think it is both the horizontal and vertical v.

    • one year ago
  13. Fellowroot Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    and thats the problem.

    • one year ago
  14. amrit_srovar Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    but i think that we can get the horizontal and vertical v though the slope. use the slope to get the angle, then after u get the angle, use the 735 mps and the angle to get the vx and vy...im not sure with that

    • one year ago
  15. amrit_srovar Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    through*

    • one year ago
  16. Fellowroot Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    i think i got it hang on

    • one year ago
  17. Algebraic! Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    I looked at this question earlier. Honestly, it doesn't really make sense. They stipulate the angle and then they ask for the angle. Make sure you got the wording right, or, if there's a diagram that somehow explains this, post it.

    • one year ago
  18. amrit_srovar Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    well, i agree with u @Algebraic! because u can simply get the angle with the given slope. im also confused with that, but maybe the point is that we will use the angle to get the vx and vy, and then use the equations to get the theta

    • one year ago
  19. Algebraic! Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    impossible.

    • one year ago
  20. Algebraic! Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    changing the angle changes Vx and Vy.

    • one year ago
  21. Algebraic! Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    yet they stipulate Vy/Vx ... doesn't make sense.

    • one year ago
  22. Algebraic! Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    is this from an online problem set? or if it's from a text book, can you scan and post the pic. or take an ss?

    • one year ago
  23. amrit_srovar Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    it is from a book, but there's no picture. i posted exactly the same problem as it is in the book

    • one year ago
  24. Algebraic! Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    Well, I've tried interpreting this problem statement in a way that somehow makes sense.. but nothing has come to me.

    • one year ago
  25. amrit_srovar Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    or maybe we won't be using the slope....haha, i just don't know

    • one year ago
  26. amrit_srovar Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    please help =(

    • one year ago
  27. Algebraic! Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    how?

    • one year ago
  28. amrit_srovar Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    this is our homework to be submitted tomorrow....=(

    • one year ago
  29. Fellowroot Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    |dw:1349577709975:dw|

    • one year ago
  30. amrit_srovar Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    =( i just don't know what to do

    • one year ago
  31. Fellowroot Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    |dw:1349578270124:dw|

    • one year ago
  32. Fellowroot Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    and i dont think the speed of the plane matters at all

    • one year ago
  33. Arindam Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    the angle between the muzzle and horizontal plane is tan-1(4/3)or 53.13 roughly. thus the initial vertical velocity of the missile is 735*Sin(53.13) or 588 m and accn is 9.8 mps^2 towards the ground. thus using the formula s = ut-.5gt^2 the time taken to reach 5390 m comes to be 10 secs. In this 10 secs the projectile moved horizontally 10*735*cos(53.13) metres or 4410 metres. and the plane has moved 2780 metres. Thus the plane was initially at (4410-2780) or 1630 metres horizontal distance from muzzle. thus the initial angle becomes tan-1(5390/1630) m or 73.174 m.

    • one year ago
  34. amrit_srovar Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    thnx a lot =)))))))))))

    • one year ago
  35. Fellowroot Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    How can the angle be arctan(4/3) =53 and then at the end its 73 ???

    • one year ago
    • Attachments:

See more questions >>>

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.