Christopher is 68 years old and Gabriela is 4 years old.How many years will it take until Christopher is only 5 times as old as Gabriela? (yes i know I have to set up an equation. but thats the tricky part)
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga.
Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus.
Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
5(4+x).... that could be part of it :) do you see why?
yeah but what about the other side of the equation?
Not the answer you are looking for? Search for more explanations.
You can solve this question in two ways
1) Setting up an equation
Christopher's age=68, let X no.of years pass before Christopher becomes 5 times as old as Gabriela..so Christopher's age after X years=68+X. Gabriela's age after X years=4+X.
Now according to the criterion set, 68+X=5*(4+X)
now solve for X.answer should be 12
2)Without setting up the equation
Difference between Christopher's and Gabriela's Age=68-4=64 years
Now. Christopher will at one point be only 5 time as old as Gabriela. At that point, Difference in ages= 5Gabriela-Gabriela=4Gabriela
--> 4Gabriela=64 or Gabriela=16 years
which means 16-4=12 more years need to pass