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sws._.
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Christopher is 68 years old and Gabriela is 4 years old.How many years will it take until Christopher is only 5 times as old as Gabriela? (yes i know I have to set up an equation. but thats the tricky part)
 2 years ago
 2 years ago
sws._. Group Title
Christopher is 68 years old and Gabriela is 4 years old.How many years will it take until Christopher is only 5 times as old as Gabriela? (yes i know I have to set up an equation. but thats the tricky part)
 2 years ago
 2 years ago

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Edutopia Group TitleBest ResponseYou've already chosen the best response.0
5(4+x).... that could be part of it :) do you see why?
 2 years ago

sws._. Group TitleBest ResponseYou've already chosen the best response.0
yeah but what about the other side of the equation?
 2 years ago

sws._. Group TitleBest ResponseYou've already chosen the best response.0
because i also have to include the 68 in there
 2 years ago

viktor.ray Group TitleBest ResponseYou've already chosen the best response.0
You can solve this question in two ways 1) Setting up an equation Christopher's age=68, let X no.of years pass before Christopher becomes 5 times as old as Gabriela..so Christopher's age after X years=68+X. Gabriela's age after X years=4+X. Now according to the criterion set, 68+X=5*(4+X) now solve for X.answer should be 12 2)Without setting up the equation Difference between Christopher's and Gabriela's Age=684=64 years Now. Christopher will at one point be only 5 time as old as Gabriela. At that point, Difference in ages= 5GabrielaGabriela=4Gabriela > 4Gabriela=64 or Gabriela=16 years which means 164=12 more years need to pass
 2 years ago

sws._. Group TitleBest ResponseYou've already chosen the best response.0
okay thank you so much :]
 2 years ago
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