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sws._.
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Christopher is 68 years old and Gabriela is 4 years old.How many years will it take until Christopher is only 5 times as old as Gabriela? (yes i know I have to set up an equation. but thats the tricky part)
 one year ago
 one year ago
sws._. Group Title
Christopher is 68 years old and Gabriela is 4 years old.How many years will it take until Christopher is only 5 times as old as Gabriela? (yes i know I have to set up an equation. but thats the tricky part)
 one year ago
 one year ago

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Edutopia Group TitleBest ResponseYou've already chosen the best response.0
5(4+x).... that could be part of it :) do you see why?
 one year ago

sws._. Group TitleBest ResponseYou've already chosen the best response.0
yeah but what about the other side of the equation?
 one year ago

sws._. Group TitleBest ResponseYou've already chosen the best response.0
because i also have to include the 68 in there
 one year ago

viktor.ray Group TitleBest ResponseYou've already chosen the best response.0
You can solve this question in two ways 1) Setting up an equation Christopher's age=68, let X no.of years pass before Christopher becomes 5 times as old as Gabriela..so Christopher's age after X years=68+X. Gabriela's age after X years=4+X. Now according to the criterion set, 68+X=5*(4+X) now solve for X.answer should be 12 2)Without setting up the equation Difference between Christopher's and Gabriela's Age=684=64 years Now. Christopher will at one point be only 5 time as old as Gabriela. At that point, Difference in ages= 5GabrielaGabriela=4Gabriela > 4Gabriela=64 or Gabriela=16 years which means 164=12 more years need to pass
 one year ago

sws._. Group TitleBest ResponseYou've already chosen the best response.0
okay thank you so much :]
 one year ago
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