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Claire4christ Group Title

I need help with question. Im gonna download question.

  • 2 years ago
  • 2 years ago

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  1. Claire4christ Group Title
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  2. Claire4christ Group Title
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    @radar

    • 2 years ago
  3. Algebraic! Group Title
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    who opens .docx anymore?

    • 2 years ago
  4. Claire4christ Group Title
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    you can open do docx

    • 2 years ago
  5. Decart Group Title
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    you need to use trigonometric functions

    • 2 years ago
  6. Claire4christ Group Title
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    i got cos 50=x/90 right

    • 2 years ago
  7. Claire4christ Group Title
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    so i got 57.9

    • 2 years ago
  8. Claire4christ Group Title
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    The cosine of a 50° angle is 57.9 right

    • 2 years ago
  9. Decart Group Title
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    which part the first blank is asking which function to use to find the height

    • 2 years ago
  10. Claire4christ Group Title
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    part 1 i think its cosine

    • 2 years ago
  11. Decart Group Title
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    if yo are using cos(50)=x/90

    • 2 years ago
  12. Claire4christ Group Title
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    yes that's what i did

    • 2 years ago
  13. Claire4christ Group Title
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    and i got 57.9

    • 2 years ago
  14. Decart Group Title
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    then the next part is asking for the reverse how do you find the cosine function with the two sides

    • 2 years ago
  15. Decart Group Title
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    57.8

    • 2 years ago
  16. Decart Group Title
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    then input the cosine of 50 in your calculator for the next blank

    • 2 years ago
  17. Claire4christ Group Title
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    its asking this this represents the value created when length _____ is divided by ______ feet.

    • 2 years ago
  18. Decart Group Title
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    the angle is the value when you divide the sides accordingly

    • 2 years ago
  19. radar Group Title
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    Cos 50 degrees is 0.6428

    • 2 years ago
  20. Claire4christ Group Title
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    The cosine of a 50° angle is 57.9 is this right for the second part

    • 2 years ago
  21. Decart Group Title
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    all the trig functions are is a relationship between the lengths of sides if you divide two known sides and take that data it represents and angle.

    • 2 years ago
  22. Decart Group Title
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    so like radar has said the cosine of 50 is .6428 so the sides divided are also .6428

    • 2 years ago
  23. Decart Group Title
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    57.8 is the height of the tower because you multiplied the hypotenuse by the cosine to find x

    • 2 years ago
  24. Claire4christ Group Title
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    so it will be .6428x.6428

    • 2 years ago
  25. radar Group Title
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    Cos is the adjacent side divided by the hypotenusel.

    • 2 years ago
  26. Decart Group Title
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    what happens if you divide the side x by the side of 90

    • 2 years ago
  27. Claire4christ Group Title
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    adjacemt side is x right and hypotenusel is 90

    • 2 years ago
  28. Decart Group Title
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    so 57.8 divided by 90

    • 2 years ago
  29. Claire4christ Group Title
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    that's what i got

    • 2 years ago
  30. radar Group Title
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    \[\cos 50^{0}=x/90 ft\]

    • 2 years ago
  31. Decart Group Title
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    you get .6422

    • 2 years ago
  32. Claire4christ Group Title
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    i got 57.9

    • 2 years ago
  33. Decart Group Title
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    roughly the same as the cosine for 50 degrees

    • 2 years ago
  34. radar Group Title
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    \[x=.6428 \times90\]

    • 2 years ago
  35. Decart Group Title
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    |dw:1349577896978:dw|

    • 2 years ago
  36. Decart Group Title
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    that is what we have so far

    • 2 years ago
  37. Claire4christ Group Title
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    so it would be 57.9

    • 2 years ago
  38. Claire4christ Group Title
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    so x side is 57.9

    • 2 years ago
  39. radar Group Title
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    Yes

    • 2 years ago
  40. radar Group Title
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    when angle was 50 degrees

    • 2 years ago
  41. Decart Group Title
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    \[\cos(50^{0})=\frac{ adjacent }{ hypotenuse}\]

    • 2 years ago
  42. Claire4christ Group Title
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    The cosine of a 50° angle is .6422 right

    • 2 years ago
  43. Decart Group Title
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    the first question only wanted to know that you would use the cosine function to find x

    • 2 years ago
  44. Decart Group Title
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    the next blank wants you to input the cosine of 50 which you have .6422

    • 2 years ago
  45. Claire4christ Group Title
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    its .6428

    • 2 years ago
  46. Decart Group Title
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    yes if you type in cos50 in your calculator that is what you get

    • 2 years ago
  47. Claire4christ Group Title
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    this represents the value created when length ____ is divided by ____ feet.

    • 2 years ago
  48. Claire4christ Group Title
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    so what about this one

    • 2 years ago
  49. Decart Group Title
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    if you look at the funtion you know that it is x divided by the 90 feet if you divide the value you got for x by 90 it is about the same as cos 50

    • 2 years ago
  50. Claire4christ Group Title
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    when length is 50 is divided by x feet right

    • 2 years ago
  51. Decart Group Title
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    no 50 is the angle you want the height of the tower divided by the lenght of the decline which is 90

    • 2 years ago
  52. Claire4christ Group Title
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    when length is 90 divided by x feet

    • 2 years ago
  53. Decart Group Title
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    |dw:1349578522617:dw|

    • 2 years ago
  54. Claire4christ Group Title
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    right

    • 2 years ago
  55. Decart Group Title
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    see how it is lenght x divided by 90 feet

    • 2 years ago
  56. Claire4christ Group Title
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    ok i see now x/90

    • 2 years ago
  57. Decart Group Title
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    that is a balanced equation if you divide that you get the same value as you did when you input cos of 50 into your calculator

    • 2 years ago
  58. Claire4christ Group Title
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    ok

    • 2 years ago
  59. Claire4christ Group Title
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    If the angle of declination changed to 60°, the cosine would be 0.5; now the length of x would be ________ feet.

    • 2 years ago
  60. Decart Group Title
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    use the same equation with the cos of 60 instead

    • 2 years ago
  61. Claire4christ Group Title
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    so its gonna be cos(60)=x/90

    • 2 years ago
  62. Decart Group Title
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    \[\cos(60^{0})=\frac{ x }{ 90ft }\]

    • 2 years ago
  63. Decart Group Title
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    so now you need to solve for x

    • 2 years ago
  64. Claire4christ Group Title
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    so it would be 45

    • 2 years ago
  65. Decart Group Title
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    yes one more blank left

    • 2 years ago
  66. Decart Group Title
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    there is two ways to solve for this but you are suppose to use a trig function

    • 2 years ago
  67. Decart Group Title
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    there are srry

    • 2 years ago
  68. Claire4christ Group Title
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    0.5

    • 2 years ago
  69. Claire4christ Group Title
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    If the angle of declination changed to 60°, the angle of inclination would be _____ degrees.

    • 2 years ago
  70. Decart Group Title
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    no it wants to know the angle of inclination which is the angle from the bottom

    • 2 years ago
  71. Decart Group Title
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    |dw:1349579030126:dw|

    • 2 years ago
  72. radar Group Title
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    |dw:1349579070499:dw|

    • 2 years ago
  73. Decart Group Title
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    the angel theta is unknown do you know which trig function to use to solve it

    • 2 years ago
  74. Claire4christ Group Title
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    not sure

    • 2 years ago
  75. Claire4christ Group Title
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    so theta is 60 degrees right

    • 2 years ago
  76. Decart Group Title
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    if you look at the trig functions there are sin=opposite / hypotenuse cos which we covered and tangent = opposite / adjacent

    • 2 years ago
  77. Claire4christ Group Title
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    ok

    • 2 years ago
  78. Decart Group Title
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    so you want to use the sine function

    • 2 years ago
  79. radar Group Title
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    From reading the problem, I believe you could solve simply from the fact you are working with a right triangle, and the sum of the two acute angles equals 90 degrees.

    • 2 years ago
  80. Decart Group Title
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    |dw:1349579230668:dw|

    • 2 years ago
  81. Claire4christ Group Title
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    so apposite side is 45 right

    • 2 years ago
  82. Decart Group Title
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    yes

    • 2 years ago
  83. Claire4christ Group Title
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    so we trying to find the bottom right

    • 2 years ago
  84. Decart Group Title
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    yes the bottom angle

    • 2 years ago
  85. Decart Group Title
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    on your calculator you push the 2nd button then 45/90

    • 2 years ago
  86. Claire4christ Group Title
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    i got 0.5

    • 2 years ago
  87. Decart Group Title
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    you need the inverse sine of .5 which is 2nd sin .5

    • 2 years ago
  88. Decart Group Title
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    are you using a ti calculator

    • 2 years ago
  89. Claire4christ Group Title
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    no my iphone

    • 2 years ago
  90. Decart Group Title
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    you need to look for \[\sin ^{-1}\]

    • 2 years ago
  91. Claire4christ Group Title
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    ok

    • 2 years ago
  92. Claire4christ Group Title
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    you press sin ^-1

    • 2 years ago
  93. Claire4christ Group Title
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    and than 45/90

    • 2 years ago
  94. Decart Group Title
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    is that a button

    • 2 years ago
  95. Claire4christ Group Title
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    yes its sin^(-1)

    • 2 years ago
  96. Decart Group Title
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    yes what do you get when you put that in

    • 2 years ago
  97. Claire4christ Group Title
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    0.5

    • 2 years ago
  98. Decart Group Title
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    .5 is what you get when you do the division without the sine function I am not sure what your calculator is doing

    • 2 years ago
  99. Decart Group Title
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    when you get the true inverse sine you will get 30 degrees

    • 2 years ago
  100. Claire4christ Group Title
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    i got 30

    • 2 years ago
  101. Decart Group Title
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    that is correct know do you notice that the 30 you got and the 60 degree other angle add up to 90 and the right angle is also 90 every triangle has 180 degrees in it so you could have just found the missing amount from 180

    • 2 years ago
  102. Decart Group Title
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    http://www.youtube.com/watch?v=T8B8Tcz8kog&feature=related

    • 2 years ago
  103. Decart Group Title
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    that is a link to a tutorial that might be able to help

    • 2 years ago
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is replying to Can someone tell me what button the professor is hitting...

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