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zaphod
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25 cm^3 of 2mol/dm^3 Sodium hydrixude solution and 25cm^3 of 2 mol/dm^3 Sulphuric acid were mixed well to make a solution X. Calculate the concentration of Sulphuric acid in the final solution..
 2 years ago
 2 years ago
zaphod Group Title
25 cm^3 of 2mol/dm^3 Sodium hydrixude solution and 25cm^3 of 2 mol/dm^3 Sulphuric acid were mixed well to make a solution X. Calculate the concentration of Sulphuric acid in the final solution..
 2 years ago
 2 years ago

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zaphod Group TitleBest ResponseYou've already chosen the best response.0
@Callisto @TuringTest
 2 years ago

Callisto Group TitleBest ResponseYou've already chosen the best response.0
Sodium hydroxide?
 2 years ago

Callisto Group TitleBest ResponseYou've already chosen the best response.0
Do you mean sodium hydroxide for ''Sodium hydrixude''?
 2 years ago

Callisto Group TitleBest ResponseYou've already chosen the best response.0
Can you write the chemical equation for the reaction first?
 2 years ago

zaphod Group TitleBest ResponseYou've already chosen the best response.0
2NaOH + H2SO4 > Na2SO4 + 2H20
 2 years ago

Callisto Group TitleBest ResponseYou've already chosen the best response.0
In this reaction, what is the limiting agent?
 2 years ago

zaphod Group TitleBest ResponseYou've already chosen the best response.0
limiting agent means? i found the answer it is 1 moldm^3 cn u check it
 2 years ago

Callisto Group TitleBest ResponseYou've already chosen the best response.0
Hmm, I didn't get the same answer as you.
 2 years ago

zaphod Group TitleBest ResponseYou've already chosen the best response.0
can u shw ur working
 2 years ago

Callisto Group TitleBest ResponseYou've already chosen the best response.0
Perhaps I didn't do it correctly, since I haven't studied chemistry for quite a long time.. No. of mole of H2SO4 used = 1/2 (no. of mole of NaOH) = (1/2) (2x25/1000) = x *NaOH is the limiting agent that will be used up in the reaction. No. of mole of H2SO4 left = no. of mole of H2SO4  no. of mole of H2SO4 used = (2x25/1000)  x = y Concentration of H2SO4 in the final solution = no. of mole of H2SO4 left / volume of the solution. And I take volume of the solution remains unchange, that is 25cm^3 + 25cm^3 = 50cm^3 Did I do anything wrong?
 2 years ago

zaphod Group TitleBest ResponseYou've already chosen the best response.0
This is how i did, check if im wrong 2NaOH + H2SO4 > Na2So4 +2 H20 the molar ratio is tht, 2 moles of NAOH reacts with 1 mole of H2so4 when u calculate the number of moles in each reactnt it is 0.05 mole, which means 0.05 mol of Naoh react with 0.025 mol of H2so4...so there is 0.025 mole of H2so4 left n = c*v/ 1000 0.025 = c * 25/1000 c = 1 mol dm^3
 2 years ago

Callisto Group TitleBest ResponseYou've already chosen the best response.0
Why is it 25cm^3 for your volume?
 2 years ago

zaphod Group TitleBest ResponseYou've already chosen the best response.0
should it be 50 or 25?
 2 years ago

zaphod Group TitleBest ResponseYou've already chosen the best response.0
im not sure of this
 2 years ago

Callisto Group TitleBest ResponseYou've already chosen the best response.0
Hmm.. final solution, it's not just the volume of H2SO4, so I prefer using the total volume. But I'm not sure though. As I've said, I haven't studied chemistry for quite a long time!
 2 years ago

zaphod Group TitleBest ResponseYou've already chosen the best response.0
then the answer becomes 0.5 moldm^3
 2 years ago

Callisto Group TitleBest ResponseYou've already chosen the best response.0
That's what I got. Sorry for the late reply
 2 years ago

zaphod Group TitleBest ResponseYou've already chosen the best response.0
so my method is right?
 2 years ago

Callisto Group TitleBest ResponseYou've already chosen the best response.0
The method is right, just the volume is not right/
 2 years ago

zaphod Group TitleBest ResponseYou've already chosen the best response.0
thanks alot :)
 2 years ago

Callisto Group TitleBest ResponseYou've already chosen the best response.0
Welcome :)
 2 years ago
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