anonymous
  • anonymous
What method(s) would you choose to solve the equation? Explain your reasoning. 2x^2 +4x - 3 = 0
Mathematics
chestercat
  • chestercat
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions

anonymous
  • anonymous
quadratic formula and factoring
calculusfunctions
  • calculusfunctions
Factoring over integers is not possible, thus solving by the quadratic formula would be the most efficient method. You could also solve by the method of completing the square.
anonymous
  • anonymous
i would complete the square because after \[2x^2+4x=3\] and \[x^2+2x=\frac{3}{2}\] the coefficient of the middle term is even so you can go right to \[(x+1)^2=\frac{3}{2}+1=\frac{5}{2}\]

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
Which is a better way the quadratic formula or the square and why
anonymous
  • anonymous
Depends which you prefer. Quadratic is easier to some. Completing the square just requires you be a little more tedious :)
anonymous
  • anonymous
@dylanhouse, i do not think i need to solve.I think i just need to say which formala would i use and why
anonymous
  • anonymous
Well, you would use the quadratic formula \[x=\frac{ -b \pm \sqrt{b^2-4ac} }{ 2a }\] simply because it is a quadratic equation!
anonymous
  • anonymous
It has the \[x^2\] term.
anonymous
  • anonymous
The quadratic formula is the result of completing the square. They are equivalent. You choose one over the other depending on the coefficients of the terms. Some numbers are easy to play with algebraically (small integers, etc.), others (big, clunky decimals) would probably be easier to just plug-and-chug in a formula.
anonymous
  • anonymous
I'm with satellite on this one. I'd complete the square. The numbers are small and friendly, and it only takes a couple steps to move things around.
anonymous
  • anonymous
@CliffSedge,(my answer) My method to solve the equation would be completing the sqaure... and I can just put my reasoning because the numbers are small and it only takes a couple steps??
anonymous
  • anonymous
@satellite73
anonymous
  • anonymous
Sounds good to me, though you should probably also include that you chose that because it is not factorable.
anonymous
  • anonymous
Though sometimes I have a quadratic equation that is factorable, and I use the quadratic formula anyway because I'm feeling lazy. "Feeling lazy" is a perfectly acceptable reason sometimes - as long as you still get the right answer with whatever method you choose.
anonymous
  • anonymous
theequation is not factorable @CliffSedge ?
anonymous
  • anonymous
Like calculusfunctions said, not with integers.
anonymous
  • anonymous
To see, take the leading coefficient, 2, and the constant, -3 from 2x^2 +4x - 3 and multiply them and get -6 There are no factors of -6 that add to make 4.

Looking for something else?

Not the answer you are looking for? Search for more explanations.