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 2 years ago
Prove that (xa) is a factor of x^3  (a + b + c)x^2 + (ab +bc + ca)xabc. How do I prove this???
 2 years ago
Prove that (xa) is a factor of x^3  (a + b + c)x^2 + (ab +bc + ca)xabc. How do I prove this???

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satellite73
 2 years ago
Best ResponseYou've already chosen the best response.1show that if you replace \(x\) by \(a\) you get 0

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.1then you know if \(a\) is a root of a polynomial \(p(x)\) then you can factor as \(p(x)=(xa)(q(x))\)

sabika13
 2 years ago
Best ResponseYou've already chosen the best response.0yeah i tried that, but i couldnt end up with a zero..

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.1if you do not get 0, then you cannot factor

sabika13
 2 years ago
Best ResponseYou've already chosen the best response.0i probably made a mistake.. because it has to equal to zero

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.1\[a^3  (a + b + c)a^2 + (ab +bc + ca)aabc\] is a startr

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.1yeah it works, try again

sabika13
 2 years ago
Best ResponseYou've already chosen the best response.0a^3  (a + b +c)a^2 + (ab+ bc +ca)a abc = a^3  a^3 + a^3b + a^3 c + a^2b + bc+ca^  abc

sabika13
 2 years ago
Best ResponseYou've already chosen the best response.0ohhh i see it, i messed up

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.1hmmm forgot the distributive property for the second term

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.1and some other mistakes too, but you can clean it up i am sure

sabika13
 2 years ago
Best ResponseYou've already chosen the best response.0okay i tried and i ended up like this: 2a^2 + 2a^2c

sabika13
 2 years ago
Best ResponseYou've already chosen the best response.0ohh its negative.. i got it

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.1first step \[a^3  (a + b + c)a^2 + (ab +bc + ca)aabc\] second step ok

sabika13
 2 years ago
Best ResponseYou've already chosen the best response.0yeah i didnt see the negative sign infront of the first bracket, thank you so much!!

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.1yw (you did all the work)
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