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sabika13
Group Title
Prove that (xa) is a factor of x^3  (a + b + c)x^2 + (ab +bc + ca)xabc. How do I prove this???
 2 years ago
 2 years ago
sabika13 Group Title
Prove that (xa) is a factor of x^3  (a + b + c)x^2 + (ab +bc + ca)xabc. How do I prove this???
 2 years ago
 2 years ago

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satellite73 Group TitleBest ResponseYou've already chosen the best response.1
show that if you replace \(x\) by \(a\) you get 0
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
then you know if \(a\) is a root of a polynomial \(p(x)\) then you can factor as \(p(x)=(xa)(q(x))\)
 2 years ago

sabika13 Group TitleBest ResponseYou've already chosen the best response.0
yeah i tried that, but i couldnt end up with a zero..
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
if you do not get 0, then you cannot factor
 2 years ago

sabika13 Group TitleBest ResponseYou've already chosen the best response.0
i probably made a mistake.. because it has to equal to zero
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
\[a^3  (a + b + c)a^2 + (ab +bc + ca)aabc\] is a startr
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
yeah it works, try again
 2 years ago

sabika13 Group TitleBest ResponseYou've already chosen the best response.0
a^3  (a + b +c)a^2 + (ab+ bc +ca)a abc = a^3  a^3 + a^3b + a^3 c + a^2b + bc+ca^  abc
 2 years ago

sabika13 Group TitleBest ResponseYou've already chosen the best response.0
ohhh i see it, i messed up
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
hmmm forgot the distributive property for the second term
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
and some other mistakes too, but you can clean it up i am sure
 2 years ago

sabika13 Group TitleBest ResponseYou've already chosen the best response.0
okay i tried and i ended up like this: 2a^2 + 2a^2c
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
lets go slow
 2 years ago

sabika13 Group TitleBest ResponseYou've already chosen the best response.0
ohh its negative.. i got it
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
first step \[a^3  (a + b + c)a^2 + (ab +bc + ca)aabc\] second step ok
 2 years ago

sabika13 Group TitleBest ResponseYou've already chosen the best response.0
yeah i didnt see the negative sign infront of the first bracket, thank you so much!!
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
yw (you did all the work)
 2 years ago
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