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burhan101 Group TitleBest ResponseYou've already chosen the best response.0
is it a quadratic equation question ?
 one year ago

micahwood50 Group TitleBest ResponseYou've already chosen the best response.1
Do you mean x²+4x+4?
 one year ago

burhan101 Group TitleBest ResponseYou've already chosen the best response.0
no it's 4 i've been working on it, but it's no factoring :/
 one year ago

micahwood50 Group TitleBest ResponseYou've already chosen the best response.1
Because factoring x²+4x4 is pretty difficult.
 one year ago

micahwood50 Group TitleBest ResponseYou've already chosen the best response.1
Well, It's safe to say that it cannot be factored.
 one year ago

Copythat Group TitleBest ResponseYou've already chosen the best response.1
Using the quadratic formula would be the easiest method
 one year ago

micahwood50 Group TitleBest ResponseYou've already chosen the best response.1
@Copythat How can quadratic formula help us to factor it?
 one year ago

burhan101 Group TitleBest ResponseYou've already chosen the best response.0
yeah, i dont think the formula's working
 one year ago

burhan101 Group TitleBest ResponseYou've already chosen the best response.0
\[\lim_{x \rightarrow 3} \frac{ x^2+4x4 }{ x3 }\]
 one year ago

Copythat Group TitleBest ResponseYou've already chosen the best response.1
You could try factoring out the x. x(x+4)4
 one year ago

micahwood50 Group TitleBest ResponseYou've already chosen the best response.1
I don't see why you have to factor the numerator. All you have to do is plug 3 into x.
 one year ago

burhan101 Group TitleBest ResponseYou've already chosen the best response.0
but the i get a number over x
 one year ago

micahwood50 Group TitleBest ResponseYou've already chosen the best response.1
What do you mean? Ave to do is plug 3, like this:\[\frac{ (3)^2 + 4(3)  4 }{ (3)  3 }\]
 one year ago

burhan101 Group TitleBest ResponseYou've already chosen the best response.0
yes you're right i got 7/6
 one year ago

micahwood50 Group TitleBest ResponseYou've already chosen the best response.1
Yeah. Glad I helped.
 one year ago
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