anonymous
  • anonymous
A 2-kg body rests on frictionless wedge that has an inclination of 60º and an acceleration a to the right such that the mass remains stationary relative to the wedge. Find a.
Physics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
|dw:1349586481376:dw|
anonymous
  • anonymous
didn't we do this already?
anonymous
  • anonymous
No, we didn't.

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More answers

anonymous
  • anonymous
Still don't understand the force...
anonymous
  • anonymous
FBD: |dw:1349586646724:dw| Not sure if it's right, though.
anonymous
  • anonymous
|dw:1349586759042:dw|
anonymous
  • anonymous
acos60=gcos30 (Balancing forces along the wedge in the reference frame of the wedge)
anonymous
  • anonymous
heh
anonymous
  • anonymous
|dw:1349587034552:dw|
anonymous
  • anonymous
a= gtan60
anonymous
  • anonymous
How do you set the equation for y? Not sure if I'm doing it right...\[\Sigma F_y = Nsin60º = ma\]
anonymous
  • anonymous
Ncos60 - mg =0
anonymous
  • anonymous
Hold on, give me time.
anonymous
  • anonymous
Why Ncos60, not sin?
anonymous
  • anonymous
look at the sketch
anonymous
  • anonymous
Nsin30 - mg =0 (if you like)
anonymous
  • anonymous
Yeah, silly me. Got it. Just give me a little more time.
anonymous
  • anonymous
Can you explain me why Nsin60º = ma?
anonymous
  • anonymous
because there are only two forces acting on the mass... N and mg. if you think about it, it's magic otherwise... because if the block is being accelerated it can only be because the ramp is 'pushing' it... ie the Normal force...
anonymous
  • anonymous
if the block were somehow accelerated otherwise, it would be some magical force:)
anonymous
  • anonymous
Now you're making it a little clear. If the wedge was given a greater cceleration, the block will slip upward, right?
anonymous
  • anonymous
acceleration*
anonymous
  • anonymous
it's like sitting in a car seat when someone stomps on the gas... you feel pushed back but the actuality is that the seat's Normal force has increased and is acting to accelerate you...
anonymous
  • anonymous
No.:)
anonymous
  • anonymous
Why not?
anonymous
  • anonymous
N would get longer, but it would still be perp. to the ramp face...
anonymous
  • anonymous
you're thinking maybe of a more "real-life" situation wherein air resistance is a factor... then yes, the block would slide up the ramp at some point...
anonymous
  • anonymous
Now you're mention about air resistance, it does make block slide up. Thanks.
anonymous
  • anonymous
hmm actually, maybe you're right about that...
anonymous
  • anonymous
because mg is fixed so... if N stays perp. to the ramp face and ma gets longer...I guess N would have a y component larger than mg....
anonymous
  • anonymous
Hmm I see. It does make sense.
anonymous
  • anonymous
I answered too quickly... sorry :P
anonymous
  • anonymous
It's ok. You helped me a lot. Thanks. I wish I could give you more medals, lol.
anonymous
  • anonymous
heh.

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