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micahwood50

  • 2 years ago

A 2-kg body rests on frictionless wedge that has an inclination of 60º and an acceleration a to the right such that the mass remains stationary relative to the wedge. Find a.

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  1. micahwood50
    • 2 years ago
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    |dw:1349586481376:dw|

  2. Algebraic!
    • 2 years ago
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    didn't we do this already?

  3. micahwood50
    • 2 years ago
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    No, we didn't.

  4. micahwood50
    • 2 years ago
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    Still don't understand the force...

  5. micahwood50
    • 2 years ago
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    FBD: |dw:1349586646724:dw| Not sure if it's right, though.

  6. Algebraic!
    • 2 years ago
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    |dw:1349586759042:dw|

  7. severus
    • 2 years ago
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    acos60=gcos30 (Balancing forces along the wedge in the reference frame of the wedge)

  8. Algebraic!
    • 2 years ago
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    heh

  9. Algebraic!
    • 2 years ago
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    |dw:1349587034552:dw|

  10. Algebraic!
    • 2 years ago
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    a= gtan60

  11. micahwood50
    • 2 years ago
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    How do you set the equation for y? Not sure if I'm doing it right...\[\Sigma F_y = Nsin60º = ma\]

  12. Algebraic!
    • 2 years ago
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    Ncos60 - mg =0

  13. micahwood50
    • 2 years ago
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    Hold on, give me time.

  14. micahwood50
    • 2 years ago
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    Why Ncos60, not sin?

  15. Algebraic!
    • 2 years ago
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    look at the sketch

  16. Algebraic!
    • 2 years ago
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    Nsin30 - mg =0 (if you like)

  17. micahwood50
    • 2 years ago
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    Yeah, silly me. Got it. Just give me a little more time.

  18. micahwood50
    • 2 years ago
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    Can you explain me why Nsin60º = ma?

  19. Algebraic!
    • 2 years ago
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    because there are only two forces acting on the mass... N and mg. if you think about it, it's magic otherwise... because if the block is being accelerated it can only be because the ramp is 'pushing' it... ie the Normal force...

  20. Algebraic!
    • 2 years ago
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    if the block were somehow accelerated otherwise, it would be some magical force:)

  21. micahwood50
    • 2 years ago
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    Now you're making it a little clear. If the wedge was given a greater cceleration, the block will slip upward, right?

  22. micahwood50
    • 2 years ago
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    acceleration*

  23. Algebraic!
    • 2 years ago
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    it's like sitting in a car seat when someone stomps on the gas... you feel pushed back but the actuality is that the seat's Normal force has increased and is acting to accelerate you...

  24. Algebraic!
    • 2 years ago
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    No.:)

  25. micahwood50
    • 2 years ago
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    Why not?

  26. Algebraic!
    • 2 years ago
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    N would get longer, but it would still be perp. to the ramp face...

  27. Algebraic!
    • 2 years ago
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    you're thinking maybe of a more "real-life" situation wherein air resistance is a factor... then yes, the block would slide up the ramp at some point...

  28. micahwood50
    • 2 years ago
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    Now you're mention about air resistance, it does make block slide up. Thanks.

  29. Algebraic!
    • 2 years ago
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    hmm actually, maybe you're right about that...

  30. Algebraic!
    • 2 years ago
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    because mg is fixed so... if N stays perp. to the ramp face and ma gets longer...I guess N would have a y component larger than mg....

  31. micahwood50
    • 2 years ago
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    Hmm I see. It does make sense.

  32. Algebraic!
    • 2 years ago
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    I answered too quickly... sorry :P

  33. micahwood50
    • 2 years ago
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    It's ok. You helped me a lot. Thanks. I wish I could give you more medals, lol.

  34. Algebraic!
    • 2 years ago
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    heh.

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