A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 3 years ago
A 2kg body rests on frictionless wedge that has an inclination of 60º and an acceleration a to the right such that the mass remains stationary relative to the wedge. Find a.
anonymous
 3 years ago
A 2kg body rests on frictionless wedge that has an inclination of 60º and an acceleration a to the right such that the mass remains stationary relative to the wedge. Find a.

This Question is Closed

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1349586481376:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0didn't we do this already?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Still don't understand the force...

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0FBD: dw:1349586646724:dw Not sure if it's right, though.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1349586759042:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0acos60=gcos30 (Balancing forces along the wedge in the reference frame of the wedge)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1349587034552:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0How do you set the equation for y? Not sure if I'm doing it right...\[\Sigma F_y = Nsin60º = ma\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Hold on, give me time.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Nsin30  mg =0 (if you like)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Yeah, silly me. Got it. Just give me a little more time.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Can you explain me why Nsin60º = ma?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0because there are only two forces acting on the mass... N and mg. if you think about it, it's magic otherwise... because if the block is being accelerated it can only be because the ramp is 'pushing' it... ie the Normal force...

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0if the block were somehow accelerated otherwise, it would be some magical force:)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Now you're making it a little clear. If the wedge was given a greater cceleration, the block will slip upward, right?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0it's like sitting in a car seat when someone stomps on the gas... you feel pushed back but the actuality is that the seat's Normal force has increased and is acting to accelerate you...

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0N would get longer, but it would still be perp. to the ramp face...

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0you're thinking maybe of a more "reallife" situation wherein air resistance is a factor... then yes, the block would slide up the ramp at some point...

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Now you're mention about air resistance, it does make block slide up. Thanks.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0hmm actually, maybe you're right about that...

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0because mg is fixed so... if N stays perp. to the ramp face and ma gets longer...I guess N would have a y component larger than mg....

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Hmm I see. It does make sense.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I answered too quickly... sorry :P

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0It's ok. You helped me a lot. Thanks. I wish I could give you more medals, lol.
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.