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micahwood50

A 2-kg body rests on frictionless wedge that has an inclination of 60º and an acceleration a to the right such that the mass remains stationary relative to the wedge. Find a.

  • one year ago
  • one year ago

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  1. micahwood50
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    |dw:1349586481376:dw|

    • one year ago
  2. Algebraic!
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    didn't we do this already?

    • one year ago
  3. micahwood50
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    No, we didn't.

    • one year ago
  4. micahwood50
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    Still don't understand the force...

    • one year ago
  5. micahwood50
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    FBD: |dw:1349586646724:dw| Not sure if it's right, though.

    • one year ago
  6. Algebraic!
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    |dw:1349586759042:dw|

    • one year ago
  7. severus
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    acos60=gcos30 (Balancing forces along the wedge in the reference frame of the wedge)

    • one year ago
  8. Algebraic!
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    heh

    • one year ago
  9. Algebraic!
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    |dw:1349587034552:dw|

    • one year ago
  10. Algebraic!
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    a= gtan60

    • one year ago
  11. micahwood50
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    How do you set the equation for y? Not sure if I'm doing it right...\[\Sigma F_y = Nsin60º = ma\]

    • one year ago
  12. Algebraic!
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    Ncos60 - mg =0

    • one year ago
  13. micahwood50
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    Hold on, give me time.

    • one year ago
  14. micahwood50
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    Why Ncos60, not sin?

    • one year ago
  15. Algebraic!
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    look at the sketch

    • one year ago
  16. Algebraic!
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    Nsin30 - mg =0 (if you like)

    • one year ago
  17. micahwood50
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    Yeah, silly me. Got it. Just give me a little more time.

    • one year ago
  18. micahwood50
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    Can you explain me why Nsin60º = ma?

    • one year ago
  19. Algebraic!
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    because there are only two forces acting on the mass... N and mg. if you think about it, it's magic otherwise... because if the block is being accelerated it can only be because the ramp is 'pushing' it... ie the Normal force...

    • one year ago
  20. Algebraic!
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    if the block were somehow accelerated otherwise, it would be some magical force:)

    • one year ago
  21. micahwood50
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    Now you're making it a little clear. If the wedge was given a greater cceleration, the block will slip upward, right?

    • one year ago
  22. micahwood50
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    acceleration*

    • one year ago
  23. Algebraic!
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    it's like sitting in a car seat when someone stomps on the gas... you feel pushed back but the actuality is that the seat's Normal force has increased and is acting to accelerate you...

    • one year ago
  24. Algebraic!
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    No.:)

    • one year ago
  25. micahwood50
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    Why not?

    • one year ago
  26. Algebraic!
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    N would get longer, but it would still be perp. to the ramp face...

    • one year ago
  27. Algebraic!
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    you're thinking maybe of a more "real-life" situation wherein air resistance is a factor... then yes, the block would slide up the ramp at some point...

    • one year ago
  28. micahwood50
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    Now you're mention about air resistance, it does make block slide up. Thanks.

    • one year ago
  29. Algebraic!
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    hmm actually, maybe you're right about that...

    • one year ago
  30. Algebraic!
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    because mg is fixed so... if N stays perp. to the ramp face and ma gets longer...I guess N would have a y component larger than mg....

    • one year ago
  31. micahwood50
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    Hmm I see. It does make sense.

    • one year ago
  32. Algebraic!
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    I answered too quickly... sorry :P

    • one year ago
  33. micahwood50
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    It's ok. You helped me a lot. Thanks. I wish I could give you more medals, lol.

    • one year ago
  34. Algebraic!
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    heh.

    • one year ago
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