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micahwood50

  • 3 years ago

Factor 3x⁴-17x³-12x²-62 x+20

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  1. radh
    • 3 years ago
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    From my calculations, it's unfactorable. Is this a multiple choice answer?

  2. micahwood50
    • 3 years ago
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    It's not multiply choice. It is factorable, but into two quadratics. Those cannot be factor. All I'm asking is how do you factor this?

  3. micahwood50
    • 3 years ago
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    How do you factor 3x⁴-17x³-12x²-62 x+20 into two quadratics?

  4. micahwood50
    • 3 years ago
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    Link would be helpful too.

  5. radh
    • 3 years ago
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    I get it. I know I have a video of this somewhere. One second.

  6. mathslover
    • 3 years ago
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    Factor theorem will surely work.

  7. mathslover
    • 3 years ago
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    find the factors of 20 first... can you tell me @micahwood50 ?

  8. micahwood50
    • 3 years ago
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    I'm not sure how to do this, can you show me?

  9. mathslover
    • 3 years ago
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    what are the factors of 20?

  10. micahwood50
    • 3 years ago
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    1, 2, 4, 5, 10, 20

  11. mathslover
    • 3 years ago
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    is -1 , -2 , -4,-5,-10, -20 also factors of 20 ?

  12. micahwood50
    • 3 years ago
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    Yeah.

  13. mathslover
    • 3 years ago
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    so , now one by one put : \(\pm 1,\pm 2, \pm 4, \pm 5, \pm 10, \pm 20\) at the place of x in the given expression

  14. mathslover
    • 3 years ago
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    In which you get the answer as 0 ?

  15. mathslover
    • 3 years ago
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    3x⁴-17x³-12x²-62 x+20 for example : \(3(-1)^4 -17(-1)^3 -12(-1)^2 -62(-1)+20\) \(-3 +17 -12 + 62 + 20 \) \(84 \ne 0\) Do like this for each : \(\pm 1,\pm 2, \pm 4, \pm 5, \pm 10, \pm 20\)

  16. mathslover
    • 3 years ago
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    Can you do this @micahwood50 ?

  17. micahwood50
    • 3 years ago
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    Umm, I tried all of them, none of them works.

  18. MrMoose
    • 3 years ago
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    http://www.wolframalpha.com/input/?i=factor%283x%5E4-17x%5E3-12x%5E2-62x%2B20%29

  19. MrMoose
    • 3 years ago
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    those are only the rational roots

  20. mathslover
    • 3 years ago
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    we want integral roots...

  21. micahwood50
    • 3 years ago
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    You know what? Save your time and help someone else. I'm googling Factor theorem. Thanks, though.

  22. MrMoose
    • 3 years ago
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    if the lowest terms with integer coefficients are quadratics, there aren't any.

  23. MrMoose
    • 3 years ago
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    factors, not terms

  24. MrMoose
    • 3 years ago
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    that wording was bad, but I think you know what I mean

  25. ByteMe
    • 3 years ago
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    \(\large 3x^4-17x^3-12x^2-62x+20 =(3x^2+4x+10)(x^2-7x+2)\) "Link would be helpful too. " I read a post about factoring into quadratics. Here is a post in which someone tried to explain the method of factoring into quadratics, but I could not understand it. :( http://openstudy.com/users/dpainc#/updates/4fcfdafce4b0c6963adaf2bc

  26. MrMoose
    • 3 years ago
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    I don't think that that would apply in this situation, unless you could see that x^2 -7x + 2 is a factor.

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