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radhBest ResponseYou've already chosen the best response.1
From my calculations, it's unfactorable. Is this a multiple choice answer?
 one year ago

micahwood50Best ResponseYou've already chosen the best response.0
It's not multiply choice. It is factorable, but into two quadratics. Those cannot be factor. All I'm asking is how do you factor this?
 one year ago

micahwood50Best ResponseYou've already chosen the best response.0
How do you factor 3x⁴17x³12x²62 x+20 into two quadratics?
 one year ago

micahwood50Best ResponseYou've already chosen the best response.0
Link would be helpful too.
 one year ago

radhBest ResponseYou've already chosen the best response.1
I get it. I know I have a video of this somewhere. One second.
 one year ago

mathsloverBest ResponseYou've already chosen the best response.0
Factor theorem will surely work.
 one year ago

mathsloverBest ResponseYou've already chosen the best response.0
find the factors of 20 first... can you tell me @micahwood50 ?
 one year ago

micahwood50Best ResponseYou've already chosen the best response.0
I'm not sure how to do this, can you show me?
 one year ago

mathsloverBest ResponseYou've already chosen the best response.0
what are the factors of 20?
 one year ago

micahwood50Best ResponseYou've already chosen the best response.0
1, 2, 4, 5, 10, 20
 one year ago

mathsloverBest ResponseYou've already chosen the best response.0
is 1 , 2 , 4,5,10, 20 also factors of 20 ?
 one year ago

mathsloverBest ResponseYou've already chosen the best response.0
so , now one by one put : \(\pm 1,\pm 2, \pm 4, \pm 5, \pm 10, \pm 20\) at the place of x in the given expression
 one year ago

mathsloverBest ResponseYou've already chosen the best response.0
In which you get the answer as 0 ?
 one year ago

mathsloverBest ResponseYou've already chosen the best response.0
3x⁴17x³12x²62 x+20 for example : \(3(1)^4 17(1)^3 12(1)^2 62(1)+20\) \(3 +17 12 + 62 + 20 \) \(84 \ne 0\) Do like this for each : \(\pm 1,\pm 2, \pm 4, \pm 5, \pm 10, \pm 20\)
 one year ago

mathsloverBest ResponseYou've already chosen the best response.0
Can you do this @micahwood50 ?
 one year ago

micahwood50Best ResponseYou've already chosen the best response.0
Umm, I tried all of them, none of them works.
 one year ago

MrMooseBest ResponseYou've already chosen the best response.0
http://www.wolframalpha.com/input/?i=factor%283x%5E417x%5E312x%5E262x%2B20%29
 one year ago

MrMooseBest ResponseYou've already chosen the best response.0
those are only the rational roots
 one year ago

mathsloverBest ResponseYou've already chosen the best response.0
we want integral roots...
 one year ago

micahwood50Best ResponseYou've already chosen the best response.0
You know what? Save your time and help someone else. I'm googling Factor theorem. Thanks, though.
 one year ago

MrMooseBest ResponseYou've already chosen the best response.0
if the lowest terms with integer coefficients are quadratics, there aren't any.
 one year ago

MrMooseBest ResponseYou've already chosen the best response.0
that wording was bad, but I think you know what I mean
 one year ago

ByteMeBest ResponseYou've already chosen the best response.0
\(\large 3x^417x^312x^262x+20 =(3x^2+4x+10)(x^27x+2)\) "Link would be helpful too. " I read a post about factoring into quadratics. Here is a post in which someone tried to explain the method of factoring into quadratics, but I could not understand it. :( http://openstudy.com/users/dpainc#/updates/4fcfdafce4b0c6963adaf2bc
 one year ago

MrMooseBest ResponseYou've already chosen the best response.0
I don't think that that would apply in this situation, unless you could see that x^2 7x + 2 is a factor.
 one year ago
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