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radh
 2 years ago
Best ResponseYou've already chosen the best response.1From my calculations, it's unfactorable. Is this a multiple choice answer?

micahwood50
 2 years ago
Best ResponseYou've already chosen the best response.0It's not multiply choice. It is factorable, but into two quadratics. Those cannot be factor. All I'm asking is how do you factor this?

micahwood50
 2 years ago
Best ResponseYou've already chosen the best response.0How do you factor 3x⁴17x³12x²62 x+20 into two quadratics?

micahwood50
 2 years ago
Best ResponseYou've already chosen the best response.0Link would be helpful too.

radh
 2 years ago
Best ResponseYou've already chosen the best response.1I get it. I know I have a video of this somewhere. One second.

mathslover
 2 years ago
Best ResponseYou've already chosen the best response.0Factor theorem will surely work.

mathslover
 2 years ago
Best ResponseYou've already chosen the best response.0find the factors of 20 first... can you tell me @micahwood50 ?

micahwood50
 2 years ago
Best ResponseYou've already chosen the best response.0I'm not sure how to do this, can you show me?

mathslover
 2 years ago
Best ResponseYou've already chosen the best response.0what are the factors of 20?

mathslover
 2 years ago
Best ResponseYou've already chosen the best response.0is 1 , 2 , 4,5,10, 20 also factors of 20 ?

mathslover
 2 years ago
Best ResponseYou've already chosen the best response.0so , now one by one put : \(\pm 1,\pm 2, \pm 4, \pm 5, \pm 10, \pm 20\) at the place of x in the given expression

mathslover
 2 years ago
Best ResponseYou've already chosen the best response.0In which you get the answer as 0 ?

mathslover
 2 years ago
Best ResponseYou've already chosen the best response.03x⁴17x³12x²62 x+20 for example : \(3(1)^4 17(1)^3 12(1)^2 62(1)+20\) \(3 +17 12 + 62 + 20 \) \(84 \ne 0\) Do like this for each : \(\pm 1,\pm 2, \pm 4, \pm 5, \pm 10, \pm 20\)

mathslover
 2 years ago
Best ResponseYou've already chosen the best response.0Can you do this @micahwood50 ?

micahwood50
 2 years ago
Best ResponseYou've already chosen the best response.0Umm, I tried all of them, none of them works.

MrMoose
 2 years ago
Best ResponseYou've already chosen the best response.0http://www.wolframalpha.com/input/?i=factor%283x%5E417x%5E312x%5E262x%2B20%29

MrMoose
 2 years ago
Best ResponseYou've already chosen the best response.0those are only the rational roots

mathslover
 2 years ago
Best ResponseYou've already chosen the best response.0we want integral roots...

micahwood50
 2 years ago
Best ResponseYou've already chosen the best response.0You know what? Save your time and help someone else. I'm googling Factor theorem. Thanks, though.

MrMoose
 2 years ago
Best ResponseYou've already chosen the best response.0if the lowest terms with integer coefficients are quadratics, there aren't any.

MrMoose
 2 years ago
Best ResponseYou've already chosen the best response.0that wording was bad, but I think you know what I mean

ByteMe
 2 years ago
Best ResponseYou've already chosen the best response.0\(\large 3x^417x^312x^262x+20 =(3x^2+4x+10)(x^27x+2)\) "Link would be helpful too. " I read a post about factoring into quadratics. Here is a post in which someone tried to explain the method of factoring into quadratics, but I could not understand it. :( http://openstudy.com/users/dpainc#/updates/4fcfdafce4b0c6963adaf2bc

MrMoose
 2 years ago
Best ResponseYou've already chosen the best response.0I don't think that that would apply in this situation, unless you could see that x^2 7x + 2 is a factor.
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