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From my calculations, it's unfactorable. Is this a multiple choice answer?
It's not multiply choice. It is factorable, but into two quadratics. Those cannot be factor. All I'm asking is how do you factor this?
How do you factor 3x⁴-17x³-12x²-62 x+20 into two quadratics?
Link would be helpful too.
I get it. I know I have a video of this somewhere. One second.
Factor theorem will surely work.
I'm not sure how to do this, can you show me?
what are the factors of 20?
1, 2, 4, 5, 10, 20
is -1 , -2 , -4,-5,-10, -20 also factors of 20 ?
so , now one by one put : \(\pm 1,\pm 2, \pm 4, \pm 5, \pm 10, \pm 20\) at the place of x in the given expression
In which you get the answer as 0 ?
3x⁴-17x³-12x²-62 x+20 for example : \(3(-1)^4 -17(-1)^3 -12(-1)^2 -62(-1)+20\) \(-3 +17 -12 + 62 + 20 \) \(84 \ne 0\) Do like this for each : \(\pm 1,\pm 2, \pm 4, \pm 5, \pm 10, \pm 20\)
Umm, I tried all of them, none of them works.
those are only the rational roots
we want integral roots...
You know what? Save your time and help someone else. I'm googling Factor theorem. Thanks, though.
if the lowest terms with integer coefficients are quadratics, there aren't any.
factors, not terms
that wording was bad, but I think you know what I mean
\(\large 3x^4-17x^3-12x^2-62x+20 =(3x^2+4x+10)(x^2-7x+2)\) "Link would be helpful too. " I read a post about factoring into quadratics. Here is a post in which someone tried to explain the method of factoring into quadratics, but I could not understand it. :( http://openstudy.com/users/dpainc#/updates/4fcfdafce4b0c6963adaf2bc
I don't think that that would apply in this situation, unless you could see that x^2 -7x + 2 is a factor.