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a steel tape is calibrated at 20'c .on a cold day when the temperature is 15'c ,what will be percentage error in tape?
 one year ago
 one year ago
a steel tape is calibrated at 20'c .on a cold day when the temperature is 15'c ,what will be percentage error in tape?
 one year ago
 one year ago

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Ruchi.Best ResponseYou've already chosen the best response.0
@tanvidais13 @csaltos @uncle
 one year ago

HELLSGUARDIANBest ResponseYou've already chosen the best response.3
whenever something is heated it expands & when cooled it contracts..so this case can be considered as the case of cooling..use equation \[change \in length= \alpha \Delta T L\] where L is original length ,\[\Delta T\] is change in temperature..and \[\alpha \] is coefficient of thermal expansion of steel.. when u have found the change in length the %ge error will be given as (change in length/original length)*100 can u do the calculations?
 one year ago

Ruchi.Best ResponseYou've already chosen the best response.0
hey i hav to find percentage error intape.
 one year ago

HELLSGUARDIANBest ResponseYou've already chosen the best response.3
it will be change in length/original length*100
 one year ago

Ruchi.Best ResponseYou've already chosen the best response.0
bt length is nt mention only temp. is mention
 one year ago

HELLSGUARDIANBest ResponseYou've already chosen the best response.3
L in this formula will be cancelled as it is in both numerator and denominator..
 one year ago

Ruchi.Best ResponseYou've already chosen the best response.0
hey cn u solve it i'm nt getting u?
 one year ago

HELLSGUARDIANBest ResponseYou've already chosen the best response.3
wait for 5 minute then i will upload the solution
 one year ago

HELLSGUARDIANBest ResponseYou've already chosen the best response.3
okay tell me where u have the doubt?
 one year ago

03225186213Best ResponseYou've already chosen the best response.0
orignal lenth is calibrated length and change is occur when measured at 15c
 one year ago

Ruchi.Best ResponseYou've already chosen the best response.0
hey ash can u hlp me out
 one year ago

ash2326Best ResponseYou've already chosen the best response.2
Yes. Where do you have trouble understanding?
 one year ago

Ruchi.Best ResponseYou've already chosen the best response.0
i'm nt geting the percentage error
 one year ago

ash2326Best ResponseYou've already chosen the best response.2
All materials' length changes with temperature. Change in length is given as \[\Delta L=\alpha \Delta T L\] Here \(\Delta T\) is the change in temp. \(\alpha\) is the linear coefficient of thermal expansion. Do you get this formula?
 one year ago

Ruchi.Best ResponseYou've already chosen the best response.0
yes,after put result answer is nt coming
 one year ago

ash2326Best ResponseYou've already chosen the best response.2
Let's find the change in length \(\alpha \) for steel= \(10.8\times 10^{6} / C\) C= degree centigrade What's \(\Delta T\) here?
 one year ago

ash2326Best ResponseYou've already chosen the best response.2
it's 35. The length will decrease \[\Delta T=(15)(20)=35\]
 one year ago

ash2326Best ResponseYou've already chosen the best response.2
\[\text{now find}\ \Delta L \ \text{in terms of L} \]
 one year ago

Ruchi.Best ResponseYou've already chosen the best response.0
nt getting ANSWER CORRECT
 one year ago

ash2326Best ResponseYou've already chosen the best response.2
Do you have the answer?
 one year ago

ash2326Best ResponseYou've already chosen the best response.2
Does you question mentions the value of alpha?
 one year ago

Ruchi.Best ResponseYou've already chosen the best response.0
no ur answer that u get
 one year ago

ash2326Best ResponseYou've already chosen the best response.2
It's because of the value of alpha. For steel it varies between \(1113 *10^{(6)} /C\) Use \(12\times 10^{6} /C\) and you'd get the answer
 one year ago

Ruchi.Best ResponseYou've already chosen the best response.0
i think that if we use difference in reading we get the answer.in place of length
 one year ago

Ruchi.Best ResponseYou've already chosen the best response.0
@sauravshakya @shadowfiend @TuringTest
 one year ago
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