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Ruchi.

  • 2 years ago

a steel tape is calibrated at 20'c .on a cold day when the temperature is -15'c ,what will be percentage error in tape?

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  1. Ruchi.
    • 2 years ago
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    @tanvidais13 @csaltos @uncle

  2. Ruchi.
    • 2 years ago
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    @HELLSGUARDIAN

  3. HELLSGUARDIAN
    • 2 years ago
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    whenever something is heated it expands & when cooled it contracts..so this case can be considered as the case of cooling..use equation \[change \in length=- \alpha \Delta T L\] where L is original length ,\[\Delta T\] is change in temperature..and \[\alpha \] is coefficient of thermal expansion of steel.. when u have found the change in length the %ge error will be given as (change in length/original length)*100 can u do the calculations?

  4. Ruchi.
    • 2 years ago
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    hey i hav to find percentage error intape.

  5. HELLSGUARDIAN
    • 2 years ago
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    it will be change in length/original length*100

  6. Ruchi.
    • 2 years ago
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    bt length is nt mention only temp. is mention

  7. HELLSGUARDIAN
    • 2 years ago
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    L in this formula will be cancelled as it is in both numerator and denominator..

  8. Ruchi.
    • 2 years ago
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    hey cn u solve it i'm nt getting u?

  9. HELLSGUARDIAN
    • 2 years ago
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    wait for 5 minute then i will upload the solution

  10. Ruchi.
    • 2 years ago
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    okay

  11. HELLSGUARDIAN
    • 2 years ago
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  12. HELLSGUARDIAN
    • 2 years ago
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    you get it?

  13. Ruchi.
    • 2 years ago
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    no

  14. HELLSGUARDIAN
    • 2 years ago
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    okay tell me where u have the doubt?

  15. Ruchi.
    • 2 years ago
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    change in length

  16. 03225186213
    • 2 years ago
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    orignal lenth is calibrated length and change is occur when measured at -15c

  17. 03225186213
    • 2 years ago
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    have u got it

  18. Ruchi.
    • 2 years ago
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    @UnkleRhaukus

  19. Ruchi.
    • 2 years ago
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    hey ash can u hlp me out

  20. ash2326
    • 2 years ago
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    Yes. Where do you have trouble understanding?

  21. Ruchi.
    • 2 years ago
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    i'm nt geting the percentage error

  22. ash2326
    • 2 years ago
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    All materials' length changes with temperature. Change in length is given as \[\Delta L=\alpha \Delta T L\] Here \(\Delta T\) is the change in temp. \(\alpha\) is the linear coefficient of thermal expansion. Do you get this formula?

  23. Ruchi.
    • 2 years ago
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    yes,after put result answer is nt coming

  24. ash2326
    • 2 years ago
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    Let's find the change in length \(\alpha \) for steel= \(10.8\times 10^{-6} / C\) C= degree centigrade What's \(\Delta T\) here?

  25. Ruchi.
    • 2 years ago
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    35

  26. ash2326
    • 2 years ago
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    it's -35. The length will decrease \[\Delta T=(-15)-(20)=-35\]

  27. ash2326
    • 2 years ago
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    \[\text{now find}\ \Delta L \ \text{in terms of L} \]

  28. Ruchi.
    • 2 years ago
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    nt getting ANSWER CORRECT

  29. ash2326
    • 2 years ago
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    Do you have the answer?

  30. Ruchi.
    • 2 years ago
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    YES

  31. ash2326
    • 2 years ago
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    Mind sharing here?

  32. Ruchi.
    • 2 years ago
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    its -0.042%

  33. ash2326
    • 2 years ago
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    Does you question mentions the value of alpha?

  34. Ruchi.
    • 2 years ago
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    no ur answer that u get

  35. ash2326
    • 2 years ago
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    It's because of the value of alpha. For steel it varies between \(11-13 *10^{(-6)} /C\) Use \(12\times 10^{-6} /C\) and you'd get the answer

  36. ash2326
    • 2 years ago
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    Do you get it?

  37. rohit123
    • 2 years ago
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    99.94%

  38. Ruchi.
    • 2 years ago
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    no .

  39. Ruchi.
    • 2 years ago
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    i think that if we use difference in reading we get the answer.in place of length

  40. Ruchi.
    • 2 years ago
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    @sauravshakya @shadowfiend @TuringTest

  41. Ruchi.
    • 2 years ago
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    @experimentX

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