Here's the question you clicked on:
shubhamsrg
limit question x->infinity (20 + 2sqrt(x) + 3cuberoot(x) ) / ( 2 + sqrt(4x - 3) + cuberoot(8x -4) )
divide all by sqrt(x) ... you should get 2/sqrt(4) = 1
or you can put x=y^6 and then divide numerator and denominator by y^3 same thing.....
ohh,,thats brilliant,,thanks a ton !