Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

Ashja

  • 3 years ago

Metal: Aluminum Mass of metal: 27.776 g Volume of water in the calorimeter: 26.0 mL Initial temperature of water in calorimeter: 25.3 °C Temperature of hot water and metal in hot water bath: 100.5 °C Final temperature reached in the calorimeter: 31.6 °C 1. Calculate the energy change (q) of the surroundings (water) using the enthalpy equation qwater = m × c × ΔT. We can assume that the specific heat capacity of water is 4.18 J / (g × °C) and the density of water is 1.00 g/mL. The water has absorbed the heat of the metal. So, qwater = qmetal

  • This Question is Closed
  1. Ashja
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    2. Using the formula qmetal = m × c × ΔT, calculate the specific heat of the metal. Use the data from your experiment for the metal in your calculation.

  2. goformit100
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    put their values in it

  3. goformit100
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    r u there ?

  4. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy