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dildar

  • 3 years ago

find the laplace transform of sin2tcos2t?

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  1. ksaimouli
    • 3 years ago
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    u mean derivative

  2. dildar
    • 3 years ago
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    no it is the laplace transform.

  3. dildar
    • 3 years ago
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    master level math

  4. dildar
    • 3 years ago
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    university

  5. AccessDenied
    • 3 years ago
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    I am not particularly familiar with Laplace Transforms, but I am curious if it would be helpful to simplify sin(2t)cos(2t) using a trig identity: \(\sin(2x) = 2 \sin x \cos x\) \(\sin 2t \cos 2t = \frac{1}{2}\left( 2 \sin 2t \cos 2t \right) = \frac{1}{2} \sin (4t) \) At least, it tends to be easier to play with a single sine than a product of two trig functions. :)

  6. estudier
    • 3 years ago
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    So , 1/2 w/s^2 +w^2 where w = 4 -> 2/(s^2+16)

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