## Yahoo! The sum to n terms of the series $\sqrt{2}+\sqrt{8}+\sqrt{18}+\sqrt{32}+......$ one year ago one year ago

1. serialkillaz

\sqrt{2} *(n*(n+1)/2)

2. sauravshakya

Take root 2 common

3. sauravshakya

So, it becomes root2(1+2+3+4+...)

4. hartnn

lol! so simple, i can't believe you couldn't do this.....

5. pavan3001

sqrt(2)+sqrt(2*4)+sqrt(2*9)+sqrt(2*16)+........ =sqrt(2)+2*sqrt(2)+3*sqrt(2)+4*sqrt(2)+...... =sqrt(2)*{1+2+3+4+....} =sqrt(2)*{n*(n+1)/2}