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calc help!!!! how do you differentiate absolute values?!?!??!?!
 one year ago
 one year ago
calc help!!!! how do you differentiate absolute values?!?!??!?!
 one year ago
 one year ago

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phiBest ResponseYou've already chosen the best response.2
when x > 1/3 this is the same as y= 3x1 when x< 1/3 it is y= 3x+1
 one year ago

abannavongBest ResponseYou've already chosen the best response.0
so what rule can u use for the absolute value problems or can u do it on ur calculator
 one year ago

abannavongBest ResponseYou've already chosen the best response.0
bc i know you cant use the product rule or the quotient rule or the power rule it seems like or the chain rule
 one year ago

phiBest ResponseYou've already chosen the best response.2
one other thing, dy/dx is undefined at x= 1/3 use the power rule d/dx a x^n = a n x^(n1)
 one year ago

abannavongBest ResponseYou've already chosen the best response.0
how would u use the power rule for the abs(3x1)
 one year ago

abannavongBest ResponseYou've already chosen the best response.0
would u set (3x1)^1 ?
 one year ago

phiBest ResponseYou've already chosen the best response.2
you get 3 different answers, depending on x x> 1/3 d/dx (y= 3x1) x= 1/3 undefined x<1/3 d/dx (y= 3x+1) d/dx y = dy/dx d/dx (3x^1  1) = d/dx 3x^1 + d/dx (1) can you finish?
 one year ago

abannavongBest ResponseYou've already chosen the best response.0
yeah now i can oh ok and also i have another question for absolute values differentiate y= abs(x^25x+4) would u jst factor it out first?
 one year ago

abannavongBest ResponseYou've already chosen the best response.0
and use the product rule?
 one year ago

phiBest ResponseYou've already chosen the best response.2
for abs(x^25x+4) you have to find the values of x where this stays positive and the regions where it is negative (then replace abs with  )
 one year ago

phiBest ResponseYou've already chosen the best response.2
First finish the first problem, then repost this quadratic, because it is more complicated, and might take time to explain
 one year ago

TuringTestBest ResponseYou've already chosen the best response.2
if I may add, one trick to differentiating absolute value can be to use the definition\[x=\sqrt{x^2}\]let\[u=x^2\]then\[\frac d{dx}\sqrt u=\frac{u'}{2\sqrt u}=\frac{2x}{2x}=\frac x{x}\]
 one year ago

abannavongBest ResponseYou've already chosen the best response.0
can u differentiate it on your calculator?
 one year ago

TuringTestBest ResponseYou've already chosen the best response.2
I rely on my brain for differentiation usually, I've lost track of what handheld calculators are good for besides graphing and handling ugly nmbers
 one year ago

abannavongBest ResponseYou've already chosen the best response.0
i dont think my teacher has taught us how to differentiate absolute values yet but she assigned us an assignment with like 2 absolute value problems im still a bit confused on how to differentiate it
 one year ago

TuringTestBest ResponseYou've already chosen the best response.2
I just showed you one way
 one year ago

abannavongBest ResponseYou've already chosen the best response.0
what r the other ways
 one year ago

phiBest ResponseYou've already chosen the best response.2
btw, turing I think you should tweak your rule to x dx/x
 one year ago

L.T.Best ResponseYou've already chosen the best response.0
@abannavong, another way to find the derivative is to set up the difference quotient and multiply by the conjugate of the numerator (x+hx)/h>((x+hx)(x+h+x))/(h*(x+h+x)) Hint: When you square an absolute value, you can drop the absolute value signs
 one year ago
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