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abannavong
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calc help!!!! how do you differentiate absolute values?!?!??!?!
 2 years ago
 2 years ago
abannavong Group Title
calc help!!!! how do you differentiate absolute values?!?!??!?!
 2 years ago
 2 years ago

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abannavong Group TitleBest ResponseYou've already chosen the best response.0
y= abs(3x1)
 2 years ago

phi Group TitleBest ResponseYou've already chosen the best response.2
when x > 1/3 this is the same as y= 3x1 when x< 1/3 it is y= 3x+1
 2 years ago

abannavong Group TitleBest ResponseYou've already chosen the best response.0
so what rule can u use for the absolute value problems or can u do it on ur calculator
 2 years ago

abannavong Group TitleBest ResponseYou've already chosen the best response.0
bc i know you cant use the product rule or the quotient rule or the power rule it seems like or the chain rule
 2 years ago

phi Group TitleBest ResponseYou've already chosen the best response.2
one other thing, dy/dx is undefined at x= 1/3 use the power rule d/dx a x^n = a n x^(n1)
 2 years ago

abannavong Group TitleBest ResponseYou've already chosen the best response.0
how would u use the power rule for the abs(3x1)
 2 years ago

abannavong Group TitleBest ResponseYou've already chosen the best response.0
would u set (3x1)^1 ?
 2 years ago

phi Group TitleBest ResponseYou've already chosen the best response.2
you get 3 different answers, depending on x x> 1/3 d/dx (y= 3x1) x= 1/3 undefined x<1/3 d/dx (y= 3x+1) d/dx y = dy/dx d/dx (3x^1  1) = d/dx 3x^1 + d/dx (1) can you finish?
 2 years ago

abannavong Group TitleBest ResponseYou've already chosen the best response.0
yeah now i can oh ok and also i have another question for absolute values differentiate y= abs(x^25x+4) would u jst factor it out first?
 2 years ago

abannavong Group TitleBest ResponseYou've already chosen the best response.0
and use the product rule?
 2 years ago

phi Group TitleBest ResponseYou've already chosen the best response.2
for abs(x^25x+4) you have to find the values of x where this stays positive and the regions where it is negative (then replace abs with  )
 2 years ago

phi Group TitleBest ResponseYou've already chosen the best response.2
First finish the first problem, then repost this quadratic, because it is more complicated, and might take time to explain
 2 years ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.2
if I may add, one trick to differentiating absolute value can be to use the definition\[x=\sqrt{x^2}\]let\[u=x^2\]then\[\frac d{dx}\sqrt u=\frac{u'}{2\sqrt u}=\frac{2x}{2x}=\frac x{x}\]
 2 years ago

abannavong Group TitleBest ResponseYou've already chosen the best response.0
can u differentiate it on your calculator?
 2 years ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.2
I rely on my brain for differentiation usually, I've lost track of what handheld calculators are good for besides graphing and handling ugly nmbers
 2 years ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.2
numbers*
 2 years ago

abannavong Group TitleBest ResponseYou've already chosen the best response.0
i dont think my teacher has taught us how to differentiate absolute values yet but she assigned us an assignment with like 2 absolute value problems im still a bit confused on how to differentiate it
 2 years ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.2
I just showed you one way
 2 years ago

abannavong Group TitleBest ResponseYou've already chosen the best response.0
what r the other ways
 2 years ago

abannavong Group TitleBest ResponseYou've already chosen the best response.0
#stillconfused
 2 years ago

phi Group TitleBest ResponseYou've already chosen the best response.2
btw, turing I think you should tweak your rule to x dx/x
 2 years ago

L.T. Group TitleBest ResponseYou've already chosen the best response.0
@abannavong, another way to find the derivative is to set up the difference quotient and multiply by the conjugate of the numerator (x+hx)/h>((x+hx)(x+h+x))/(h*(x+h+x)) Hint: When you square an absolute value, you can drop the absolute value signs
 2 years ago

abannavong Group TitleBest ResponseYou've already chosen the best response.0
oh ok thanks @L.T.
 2 years ago
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