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phi
 2 years ago
Best ResponseYou've already chosen the best response.2when x > 1/3 this is the same as y= 3x1 when x< 1/3 it is y= 3x+1

abannavong
 2 years ago
Best ResponseYou've already chosen the best response.0so what rule can u use for the absolute value problems or can u do it on ur calculator

abannavong
 2 years ago
Best ResponseYou've already chosen the best response.0bc i know you cant use the product rule or the quotient rule or the power rule it seems like or the chain rule

phi
 2 years ago
Best ResponseYou've already chosen the best response.2one other thing, dy/dx is undefined at x= 1/3 use the power rule d/dx a x^n = a n x^(n1)

abannavong
 2 years ago
Best ResponseYou've already chosen the best response.0how would u use the power rule for the abs(3x1)

abannavong
 2 years ago
Best ResponseYou've already chosen the best response.0would u set (3x1)^1 ?

phi
 2 years ago
Best ResponseYou've already chosen the best response.2you get 3 different answers, depending on x x> 1/3 d/dx (y= 3x1) x= 1/3 undefined x<1/3 d/dx (y= 3x+1) d/dx y = dy/dx d/dx (3x^1  1) = d/dx 3x^1 + d/dx (1) can you finish?

abannavong
 2 years ago
Best ResponseYou've already chosen the best response.0yeah now i can oh ok and also i have another question for absolute values differentiate y= abs(x^25x+4) would u jst factor it out first?

abannavong
 2 years ago
Best ResponseYou've already chosen the best response.0and use the product rule?

phi
 2 years ago
Best ResponseYou've already chosen the best response.2for abs(x^25x+4) you have to find the values of x where this stays positive and the regions where it is negative (then replace abs with  )

phi
 2 years ago
Best ResponseYou've already chosen the best response.2First finish the first problem, then repost this quadratic, because it is more complicated, and might take time to explain

TuringTest
 2 years ago
Best ResponseYou've already chosen the best response.2if I may add, one trick to differentiating absolute value can be to use the definition\[x=\sqrt{x^2}\]let\[u=x^2\]then\[\frac d{dx}\sqrt u=\frac{u'}{2\sqrt u}=\frac{2x}{2x}=\frac x{x}\]

abannavong
 2 years ago
Best ResponseYou've already chosen the best response.0can u differentiate it on your calculator?

TuringTest
 2 years ago
Best ResponseYou've already chosen the best response.2I rely on my brain for differentiation usually, I've lost track of what handheld calculators are good for besides graphing and handling ugly nmbers

abannavong
 2 years ago
Best ResponseYou've already chosen the best response.0i dont think my teacher has taught us how to differentiate absolute values yet but she assigned us an assignment with like 2 absolute value problems im still a bit confused on how to differentiate it

TuringTest
 2 years ago
Best ResponseYou've already chosen the best response.2I just showed you one way

abannavong
 2 years ago
Best ResponseYou've already chosen the best response.0what r the other ways

phi
 2 years ago
Best ResponseYou've already chosen the best response.2btw, turing I think you should tweak your rule to x dx/x

L.T.
 2 years ago
Best ResponseYou've already chosen the best response.0@abannavong, another way to find the derivative is to set up the difference quotient and multiply by the conjugate of the numerator (x+hx)/h>((x+hx)(x+h+x))/(h*(x+h+x)) Hint: When you square an absolute value, you can drop the absolute value signs
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