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MrOrbit

  • 3 years ago

Let k(x) = x^5 + 3x -2 and let k^-1 denote the inverse of k. Then, find (k^-1)'(2)

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  1. mukushla
    • 3 years ago
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    actually in such cases u dont need to find the inverse itself and differentiate it... so what is the formula for the derivative of inverse?

  2. mukushla
    • 3 years ago
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    \[(f^{-1}(x))'=\frac{1}{f'(f^{-1}(x))}\]am i right ?

  3. dpaInc
    • 3 years ago
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    yes...

  4. mukushla
    • 3 years ago
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    how about the asker? are u familiar with that formula?

  5. mukushla
    • 3 years ago
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    ok i gotta go but here are some hints for u MrOrbit\[(f^{-1})'(2)=\frac{1}{f'(f^{-1}(2))}\]so all that u need is finding\[f^{-1}(2)\]for reaching there note that\[f(1)=2\]

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