A community for students. Sign up today!
Here's the question you clicked on:
 0 viewing
 2 years ago
how is it possible ?
x=(pi +3)/2
2x=pi +3
2x(pi 3)=(pi +3)(pi 3)
2pi*x 6x =(pi)^2 9
9 6x =(pi)^2 2pi*x
9 6x +x^2 =(pi)^2 2pi*x +x^2
(3 x)^2 =(pi x)^2
3x = pi x
pi =3
 2 years ago
how is it possible ? x=(pi +3)/2 2x=pi +3 2x(pi 3)=(pi +3)(pi 3) 2pi*x 6x =(pi)^2 9 9 6x =(pi)^2 2pi*x 9 6x +x^2 =(pi)^2 2pi*x +x^2 (3 x)^2 =(pi x)^2 3x = pi x pi =3

This Question is Closed

radar
 2 years ago
Best ResponseYou've already chosen the best response.0Everything looks legal, maybe when taking sq roots there is something that gets twisted.

estudier
 2 years ago
Best ResponseYou've already chosen the best response.0If you take the negative root, u get the start equation.....

cwrw238
 2 years ago
Best ResponseYou've already chosen the best response.0look at the 3rd line if pi = 3 then both sides of equation = 0

AnimalAin
 2 years ago
Best ResponseYou've already chosen the best response.0Didn't consider the plus or minus when taking the square root. We get \[3x= \pm(\pix) \implies 3x=\pi  x~or~3x=x\pi\] The first equation generates the contradiction from the problem. The second generates the value of x given at the getgo.
Ask your own question
Ask a QuestionFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.