A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 3 years ago
Find the absolute maximum and minimum values of f on the set D.
f(x,y) = x^2+y^2+(x^2)y+4
D = abs(x)<or=1, abs(y)<or=1
anonymous
 3 years ago
Find the absolute maximum and minimum values of f on the set D. f(x,y) = x^2+y^2+(x^2)y+4 D = abs(x)<or=1, abs(y)<or=1

This Question is Closed

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[f(x,y)=x^2+y^2+x^2y+4 \] \[D=\left x \right\le 1, \left y \right\le 1\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0ok u have a continous function so u just need to find extremums in given region ; setting partial derivatives equal to zero\[\frac{\partial f}{\partial x}=0\]\[\frac{\partial f}{\partial y}=0\]and finally compare the values of extremums with value of function at boudaries

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0when u want to find max and min at boundaries for example this onedw:1349636466076:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\(x=1\) and \(1\le y \le1\) ... ur function will be\[f(x,y)=f(1,y)=y^2+y+5\]which is a one variable function with respect to y and u can max and min of it easily :)
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.