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ksaimouli
Group Title
A block is pulled by a string that makes an angle of 25º to the horizontal. If the mass of the block is 12.0 kg and the coefficient of friction is 0.25, what force would keep the block moving at a constant velocity?
 one year ago
 one year ago
ksaimouli Group Title
A block is pulled by a string that makes an angle of 25º to the horizontal. If the mass of the block is 12.0 kg and the coefficient of friction is 0.25, what force would keep the block moving at a constant velocity?
 one year ago
 one year ago

This Question is Closed

henpen Group TitleBest ResponseYou've already chosen the best response.2
dw:1349633059599:dw
 one year ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.1
dw:1349633142335:dw
 one year ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.1
what to do after this i am totally confused
 one year ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.1
i know that ff=u*fn
 one year ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.1
we need to find fn
 one year ago

henpen Group TitleBest ResponseYou've already chosen the best response.2
\[F_n=mgF_y=12*9.8Fsin(25)\]
 one year ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.1
i got this but how do u find the F
 one year ago

henpen Group TitleBest ResponseYou've already chosen the best response.2
\[F_f= \mu F_n= 0.25(117.6Fsin(25))=F_x=Fcos(25)\]
 one year ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.1
how did u get 117.6
 one year ago

henpen Group TitleBest ResponseYou've already chosen the best response.2
\[29.40.25\sin(25)F=Fcos(25)\] \[\frac{29.4}{\cos(25)+0.25\sin(25)}=F\]
 one year ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.1
why =fcos(25)
 one year ago

henpen Group TitleBest ResponseYou've already chosen the best response.2
dw:1349634909926:dwBasic trig
 one year ago

henpen Group TitleBest ResponseYou've already chosen the best response.2
\[F_f=F_x=Fcos(25)\]
 one year ago

henpen Group TitleBest ResponseYou've already chosen the best response.2
No acceleration => no net force in xdirection
 one year ago
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