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ksaimouli
Group Title
A block is pulled by a string that makes an angle of 25º to the horizontal. If the mass of the block is 12.0 kg and the coefficient of friction is 0.25, what force would keep the block moving at a constant velocity?
 2 years ago
 2 years ago
ksaimouli Group Title
A block is pulled by a string that makes an angle of 25º to the horizontal. If the mass of the block is 12.0 kg and the coefficient of friction is 0.25, what force would keep the block moving at a constant velocity?
 2 years ago
 2 years ago

This Question is Closed

henpen Group TitleBest ResponseYou've already chosen the best response.2
dw:1349633059599:dw
 2 years ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.1
dw:1349633142335:dw
 2 years ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.1
what to do after this i am totally confused
 2 years ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.1
i know that ff=u*fn
 2 years ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.1
we need to find fn
 2 years ago

henpen Group TitleBest ResponseYou've already chosen the best response.2
\[F_n=mgF_y=12*9.8Fsin(25)\]
 2 years ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.1
i got this but how do u find the F
 2 years ago

henpen Group TitleBest ResponseYou've already chosen the best response.2
\[F_f= \mu F_n= 0.25(117.6Fsin(25))=F_x=Fcos(25)\]
 2 years ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.1
how did u get 117.6
 2 years ago

henpen Group TitleBest ResponseYou've already chosen the best response.2
\[29.40.25\sin(25)F=Fcos(25)\] \[\frac{29.4}{\cos(25)+0.25\sin(25)}=F\]
 2 years ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.1
why =fcos(25)
 2 years ago

henpen Group TitleBest ResponseYou've already chosen the best response.2
dw:1349634909926:dwBasic trig
 2 years ago

henpen Group TitleBest ResponseYou've already chosen the best response.2
\[F_f=F_x=Fcos(25)\]
 2 years ago

henpen Group TitleBest ResponseYou've already chosen the best response.2
No acceleration => no net force in xdirection
 2 years ago
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