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Find the probability P(prime sum when tossing 2 dice). Write in fraction form. Please explain. Thanks

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It would be helpful if we knew all the possible sums of the dice. I think it is easiest to use a table with numbers 1-6 on the top row and 1-6 on the left column, and just compute all the sums. Then we can easily see all the prime sums from the table. |dw:1349635556005:dw|
|dw:1349635743681:dw| Completed Table ^
|dw:1349635839214:dw| So, you can see all of the prime sums on the table: The probability from there is just (# of primes)/(total entries in the table)

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I tried that and I missed a few sums. Your table makes it more clear. Thank you. very much. So it would be 15/36 reduced into 5/12 correct?
Yes. :)
Thank you!!!
You're welcome!

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