## AbbeyD16 Group Title 4) Eight million (8,000,000) kg of water are at the verge of dropping over Niagara Falls to the rocks 50.0 meters below. What is the change in gravitational potential energy as the water splashes on the rocks below? one year ago one year ago

1. henpen Group Title

U=mgh $\Delta U=mgh_1-mgh_0=mg(h_1-h_0)=mg( \Delta h)$ $\Delta U = 8,000,000*9.8*(-50)$

2. AbbeyD16 Group Title

thanks

3. henpen Group Title

$\Delta=\text{'change \in'}$