Need some help with these problems :/ 1. Your club is baking vanilla and chocolate cakes for a bake sale. They need at most 15 cakes. You cannot have more than 11 chocolate cakes. Write and graph a system of inequalities to model this system. Let x = the number of vanilla cakes. Let y = the number of chocolate cakes. 2.Solve the system of inequalities by graphing. https://www.connexus.com/content/media/642225-162012-115732-AM-38496864.png 3. Solve the system of inequalities by graphing. https://www.connexus.com/content/media/642225-162012-115514-AM-349314999.png

- anonymous

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- katieb

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- anonymous

Help on any one of them would be appreciated :/

- anonymous

Hey Satellite (:

- anonymous

hi

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## More answers

- anonymous

Hahah yay, Satellite to the rescue.

- anonymous

the second two wont open
the first one is going to be
\[x+y\leq 15\]
\[y\leq 11\]

- anonymous

Hm thats odd :/ One sec I'll copy em down by hand.

- anonymous

picture looks like this
http://www.wolframalpha.com/input/?i=x%2By%3C%3D15%2Cy%3C%3D11

- anonymous

Thanks for that ^-^

- anonymous

yw

- anonymous

y is Less than or equal to -4x-2 , y > 3x-2 Is the first problem.

- anonymous

and y is greater than or equal to 3 , y> lx+1l Was the 2nd one, haha those are absolute value signs sorta btw x.x

- anonymous

|dw:1349639449107:dw|

- anonymous

LOL XD

- anonymous

that's so helpful..

- anonymous

These questions are junk :P

- anonymous

here is a better picture
the idea is to graph the two lines and then shade in the appropriate region
http://www.wolframalpha.com/input/?i=y%3C+-4x-2+%2C+y+%3E+3x-2

- anonymous

I hate solving junk by graphing so much x.x I'd rather like chop off a finger Dx

- anonymous

you have to graph \(y=-4x-2\)a line with slope \(-4\) and \(y\) intercept \(-2\) then graph \(y=3x-2\) a line with slope 3 and y intercept also \(-2\)

- anonymous

Yeah I get that I just suck at actually figuring it out :/

- anonymous

what region to graph, or how to graph the lines?

- anonymous

well haha I'll give em my best educated guess x)

- anonymous

How to graph them :P

- anonymous

i sent you a link with the graph of the second one

- anonymous

oh get some graph paper and plot two points for each line
for example, for \(y=-4x-2\)you know it crosses the \(y\) axis at \((0,-2)\) and if \(x=2\) you get \(-10\) so \((2,-10)\) is on the graph, or, go over one, down 4
connect the dots la la la la la
repeat for second line
it is tedious but you can do it

- anonymous

or type them in to wolfram and let the machine do it
there is really no shortcut, you just have to graph the lines

- anonymous

lol yeah ! that's true, I think I'll be alright on the test on it. but I do need to find my pesky graph paper :/ Keeps hiding on me.

- anonymous

I'm probly gonna start using that site more too haha

- anonymous

as for \(y=|x+1|\) it looks like a V sitting at \((-1,0)\)

- anonymous

|dw:1349640010650:dw|

- anonymous

Thanks again Satellite! I gotta get going sadly x.x

- anonymous

Thanks so much (:

- anonymous

shad in the stuff above, because it says \(y>|x+1|\)

- anonymous

later

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