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MeganDarling
Need some help with these problems :/ 1. Your club is baking vanilla and chocolate cakes for a bake sale. They need at most 15 cakes. You cannot have more than 11 chocolate cakes. Write and graph a system of inequalities to model this system. Let x = the number of vanilla cakes. Let y = the number of chocolate cakes. 2.Solve the system of inequalities by graphing. https://www.connexus.com/content/media/642225-162012-115732-AM-38496864.png 3. Solve the system of inequalities by graphing. https://www.connexus.com/content/media/642225-162012-115514-AM-349314999.png
Help on any one of them would be appreciated :/
Hahah yay, Satellite to the rescue.
the second two wont open the first one is going to be \[x+y\leq 15\] \[y\leq 11\]
Hm thats odd :/ One sec I'll copy em down by hand.
picture looks like this http://www.wolframalpha.com/input/?i=x%2By%3C%3D15%2Cy%3C%3D11
Thanks for that ^-^
y is Less than or equal to -4x-2 , y > 3x-2 Is the first problem.
and y is greater than or equal to 3 , y> lx+1l Was the 2nd one, haha those are absolute value signs sorta btw x.x
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that's so helpful..
These questions are junk :P
here is a better picture the idea is to graph the two lines and then shade in the appropriate region http://www.wolframalpha.com/input/?i=y%3C+-4x-2+%2C+y+%3E+3x-2
I hate solving junk by graphing so much x.x I'd rather like chop off a finger Dx
you have to graph \(y=-4x-2\)a line with slope \(-4\) and \(y\) intercept \(-2\) then graph \(y=3x-2\) a line with slope 3 and y intercept also \(-2\)
Yeah I get that I just suck at actually figuring it out :/
what region to graph, or how to graph the lines?
well haha I'll give em my best educated guess x)
How to graph them :P
i sent you a link with the graph of the second one
oh get some graph paper and plot two points for each line for example, for \(y=-4x-2\)you know it crosses the \(y\) axis at \((0,-2)\) and if \(x=2\) you get \(-10\) so \((2,-10)\) is on the graph, or, go over one, down 4 connect the dots la la la la la repeat for second line it is tedious but you can do it
or type them in to wolfram and let the machine do it there is really no shortcut, you just have to graph the lines
lol yeah ! that's true, I think I'll be alright on the test on it. but I do need to find my pesky graph paper :/ Keeps hiding on me.
I'm probly gonna start using that site more too haha
as for \(y=|x+1|\) it looks like a V sitting at \((-1,0)\)
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Thanks again Satellite! I gotta get going sadly x.x
shad in the stuff above, because it says \(y>|x+1|\)