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MeganDarling

  • 2 years ago

Need some help with these problems :/ 1. Your club is baking vanilla and chocolate cakes for a bake sale. They need at most 15 cakes. You cannot have more than 11 chocolate cakes. Write and graph a system of inequalities to model this system. Let x = the number of vanilla cakes. Let y = the number of chocolate cakes. 2.Solve the system of inequalities by graphing. https://www.connexus.com/content/media/642225-162012-115732-AM-38496864.png 3. Solve the system of inequalities by graphing. https://www.connexus.com/content/media/642225-162012-115514-AM-349314999.png

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  1. MeganDarling
    • 2 years ago
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    Help on any one of them would be appreciated :/

  2. MeganDarling
    • 2 years ago
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    Hey Satellite (:

  3. satellite73
    • 2 years ago
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    hi

  4. MeganDarling
    • 2 years ago
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    Hahah yay, Satellite to the rescue.

  5. satellite73
    • 2 years ago
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    the second two wont open the first one is going to be \[x+y\leq 15\] \[y\leq 11\]

  6. MeganDarling
    • 2 years ago
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    Hm thats odd :/ One sec I'll copy em down by hand.

  7. satellite73
    • 2 years ago
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    picture looks like this http://www.wolframalpha.com/input/?i=x%2By%3C%3D15%2Cy%3C%3D11

  8. MeganDarling
    • 2 years ago
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    Thanks for that ^-^

  9. satellite73
    • 2 years ago
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    yw

  10. MeganDarling
    • 2 years ago
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    y is Less than or equal to -4x-2 , y > 3x-2 Is the first problem.

  11. MeganDarling
    • 2 years ago
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    and y is greater than or equal to 3 , y> lx+1l Was the 2nd one, haha those are absolute value signs sorta btw x.x

  12. satellite73
    • 2 years ago
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    |dw:1349639449107:dw|

  13. MeganDarling
    • 2 years ago
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    LOL XD

  14. MeganDarling
    • 2 years ago
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    that's so helpful..

  15. MeganDarling
    • 2 years ago
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    These questions are junk :P

  16. satellite73
    • 2 years ago
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    here is a better picture the idea is to graph the two lines and then shade in the appropriate region http://www.wolframalpha.com/input/?i=y%3C+-4x-2+%2C+y+%3E+3x-2

  17. MeganDarling
    • 2 years ago
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    I hate solving junk by graphing so much x.x I'd rather like chop off a finger Dx

  18. satellite73
    • 2 years ago
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    you have to graph \(y=-4x-2\)a line with slope \(-4\) and \(y\) intercept \(-2\) then graph \(y=3x-2\) a line with slope 3 and y intercept also \(-2\)

  19. MeganDarling
    • 2 years ago
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    Yeah I get that I just suck at actually figuring it out :/

  20. satellite73
    • 2 years ago
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    what region to graph, or how to graph the lines?

  21. MeganDarling
    • 2 years ago
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    well haha I'll give em my best educated guess x)

  22. MeganDarling
    • 2 years ago
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    How to graph them :P

  23. satellite73
    • 2 years ago
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    i sent you a link with the graph of the second one

  24. satellite73
    • 2 years ago
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    oh get some graph paper and plot two points for each line for example, for \(y=-4x-2\)you know it crosses the \(y\) axis at \((0,-2)\) and if \(x=2\) you get \(-10\) so \((2,-10)\) is on the graph, or, go over one, down 4 connect the dots la la la la la repeat for second line it is tedious but you can do it

  25. satellite73
    • 2 years ago
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    or type them in to wolfram and let the machine do it there is really no shortcut, you just have to graph the lines

  26. MeganDarling
    • 2 years ago
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    lol yeah ! that's true, I think I'll be alright on the test on it. but I do need to find my pesky graph paper :/ Keeps hiding on me.

  27. MeganDarling
    • 2 years ago
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    I'm probly gonna start using that site more too haha

  28. satellite73
    • 2 years ago
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    as for \(y=|x+1|\) it looks like a V sitting at \((-1,0)\)

  29. satellite73
    • 2 years ago
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    |dw:1349640010650:dw|

  30. MeganDarling
    • 2 years ago
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    Thanks again Satellite! I gotta get going sadly x.x

  31. MeganDarling
    • 2 years ago
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    Thanks so much (:

  32. satellite73
    • 2 years ago
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    shad in the stuff above, because it says \(y>|x+1|\)

  33. satellite73
    • 2 years ago
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    later

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