anonymous
  • anonymous
Need some help with these problems :/ 1. Your club is baking vanilla and chocolate cakes for a bake sale. They need at most 15 cakes. You cannot have more than 11 chocolate cakes. Write and graph a system of inequalities to model this system. Let x = the number of vanilla cakes. Let y = the number of chocolate cakes. 2.Solve the system of inequalities by graphing. https://www.connexus.com/content/media/642225-162012-115732-AM-38496864.png 3. Solve the system of inequalities by graphing. https://www.connexus.com/content/media/642225-162012-115514-AM-349314999.png
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
Help on any one of them would be appreciated :/
anonymous
  • anonymous
Hey Satellite (:
anonymous
  • anonymous
hi

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anonymous
  • anonymous
Hahah yay, Satellite to the rescue.
anonymous
  • anonymous
the second two wont open the first one is going to be \[x+y\leq 15\] \[y\leq 11\]
anonymous
  • anonymous
Hm thats odd :/ One sec I'll copy em down by hand.
anonymous
  • anonymous
picture looks like this http://www.wolframalpha.com/input/?i=x%2By%3C%3D15%2Cy%3C%3D11
anonymous
  • anonymous
Thanks for that ^-^
anonymous
  • anonymous
yw
anonymous
  • anonymous
y is Less than or equal to -4x-2 , y > 3x-2 Is the first problem.
anonymous
  • anonymous
and y is greater than or equal to 3 , y> lx+1l Was the 2nd one, haha those are absolute value signs sorta btw x.x
anonymous
  • anonymous
|dw:1349639449107:dw|
anonymous
  • anonymous
LOL XD
anonymous
  • anonymous
that's so helpful..
anonymous
  • anonymous
These questions are junk :P
anonymous
  • anonymous
here is a better picture the idea is to graph the two lines and then shade in the appropriate region http://www.wolframalpha.com/input/?i=y%3C+-4x-2+%2C+y+%3E+3x-2
anonymous
  • anonymous
I hate solving junk by graphing so much x.x I'd rather like chop off a finger Dx
anonymous
  • anonymous
you have to graph \(y=-4x-2\)a line with slope \(-4\) and \(y\) intercept \(-2\) then graph \(y=3x-2\) a line with slope 3 and y intercept also \(-2\)
anonymous
  • anonymous
Yeah I get that I just suck at actually figuring it out :/
anonymous
  • anonymous
what region to graph, or how to graph the lines?
anonymous
  • anonymous
well haha I'll give em my best educated guess x)
anonymous
  • anonymous
How to graph them :P
anonymous
  • anonymous
i sent you a link with the graph of the second one
anonymous
  • anonymous
oh get some graph paper and plot two points for each line for example, for \(y=-4x-2\)you know it crosses the \(y\) axis at \((0,-2)\) and if \(x=2\) you get \(-10\) so \((2,-10)\) is on the graph, or, go over one, down 4 connect the dots la la la la la repeat for second line it is tedious but you can do it
anonymous
  • anonymous
or type them in to wolfram and let the machine do it there is really no shortcut, you just have to graph the lines
anonymous
  • anonymous
lol yeah ! that's true, I think I'll be alright on the test on it. but I do need to find my pesky graph paper :/ Keeps hiding on me.
anonymous
  • anonymous
I'm probly gonna start using that site more too haha
anonymous
  • anonymous
as for \(y=|x+1|\) it looks like a V sitting at \((-1,0)\)
anonymous
  • anonymous
|dw:1349640010650:dw|
anonymous
  • anonymous
Thanks again Satellite! I gotta get going sadly x.x
anonymous
  • anonymous
Thanks so much (:
anonymous
  • anonymous
shad in the stuff above, because it says \(y>|x+1|\)
anonymous
  • anonymous
later

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