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anonymous
 3 years ago
Need some help with these problems :/ 1. Your club is baking vanilla and chocolate cakes for a bake sale. They need at most 15 cakes. You cannot have more than 11 chocolate cakes. Write and graph a system of inequalities to model this system. Let x = the number of vanilla cakes. Let y = the number of chocolate cakes. 2.Solve the system of inequalities by graphing.
https://www.connexus.com/content/media/642225162012115732AM38496864.png
3. Solve the system of inequalities by graphing.
https://www.connexus.com/content/media/642225162012115514AM349314999.png
anonymous
 3 years ago
Need some help with these problems :/ 1. Your club is baking vanilla and chocolate cakes for a bake sale. They need at most 15 cakes. You cannot have more than 11 chocolate cakes. Write and graph a system of inequalities to model this system. Let x = the number of vanilla cakes. Let y = the number of chocolate cakes. 2.Solve the system of inequalities by graphing. https://www.connexus.com/content/media/642225162012115732AM38496864.png 3. Solve the system of inequalities by graphing. https://www.connexus.com/content/media/642225162012115514AM349314999.png

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Help on any one of them would be appreciated :/

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Hahah yay, Satellite to the rescue.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0the second two wont open the first one is going to be \[x+y\leq 15\] \[y\leq 11\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Hm thats odd :/ One sec I'll copy em down by hand.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0picture looks like this http://www.wolframalpha.com/input/?i=x%2By%3C%3D15%2Cy%3C%3D11

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0y is Less than or equal to 4x2 , y > 3x2 Is the first problem.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0and y is greater than or equal to 3 , y> lx+1l Was the 2nd one, haha those are absolute value signs sorta btw x.x

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1349639449107:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0These questions are junk :P

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0here is a better picture the idea is to graph the two lines and then shade in the appropriate region http://www.wolframalpha.com/input/?i=y%3C+4x2+%2C+y+%3E+3x2

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I hate solving junk by graphing so much x.x I'd rather like chop off a finger Dx

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0you have to graph \(y=4x2\)a line with slope \(4\) and \(y\) intercept \(2\) then graph \(y=3x2\) a line with slope 3 and y intercept also \(2\)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Yeah I get that I just suck at actually figuring it out :/

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0what region to graph, or how to graph the lines?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0well haha I'll give em my best educated guess x)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i sent you a link with the graph of the second one

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0oh get some graph paper and plot two points for each line for example, for \(y=4x2\)you know it crosses the \(y\) axis at \((0,2)\) and if \(x=2\) you get \(10\) so \((2,10)\) is on the graph, or, go over one, down 4 connect the dots la la la la la repeat for second line it is tedious but you can do it

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0or type them in to wolfram and let the machine do it there is really no shortcut, you just have to graph the lines

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0lol yeah ! that's true, I think I'll be alright on the test on it. but I do need to find my pesky graph paper :/ Keeps hiding on me.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I'm probly gonna start using that site more too haha

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0as for \(y=x+1\) it looks like a V sitting at \((1,0)\)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1349640010650:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Thanks again Satellite! I gotta get going sadly x.x

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0shad in the stuff above, because it says \(y>x+1\)
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