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Brent0423

  • 3 years ago

Find the inverse function of f(x)= (2-x^3)^5

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  1. RadEn
    • 3 years ago
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    @Coolsector f(x)^(1/5) = 2-x^3 ---> x^3 = 2- f(x)^(1/5) :)

  2. Coolsector
    • 3 years ago
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    oops! you are right f(x)^(1/5) = 2-x^3 x^3 =2 - f(x)^(1/5) ill call f-1(x) the inverse of f(x) so : f-1(x) = (2 - x^(1/5) )^(1/3)

  3. Brent0423
    • 3 years ago
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    im confused after -f(x)^(1/5)+2=x^3

  4. Coolsector
    • 3 years ago
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    where?

  5. Brent0423
    • 3 years ago
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    what is my next step

  6. Denebel
    • 3 years ago
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    1. first you want to switch x and y (and since f(x) can also be written as y) for example: y = (2-x^3)^5 (eqn. 1) will become x = (2-y^3)^5 (eqn. 2) Then you want to isolate y from eqn. 2. using algebra

  7. Brent0423
    • 3 years ago
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    take the 5th root of both sides

  8. Denebel
    • 3 years ago
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    Yes.. so then you'll have \[\sqrt[5]{x} = (2-y ^{3})\] so what will you do?

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