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Brent0423
 3 years ago
Find the inverse function of
f(x)= (2x^3)^5
Brent0423
 3 years ago
Find the inverse function of f(x)= (2x^3)^5

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RadEn
 3 years ago
Best ResponseYou've already chosen the best response.1@Coolsector f(x)^(1/5) = 2x^3 > x^3 = 2 f(x)^(1/5) :)

Coolsector
 3 years ago
Best ResponseYou've already chosen the best response.1oops! you are right f(x)^(1/5) = 2x^3 x^3 =2  f(x)^(1/5) ill call f1(x) the inverse of f(x) so : f1(x) = (2  x^(1/5) )^(1/3)

Brent0423
 3 years ago
Best ResponseYou've already chosen the best response.0im confused after f(x)^(1/5)+2=x^3

Denebel
 3 years ago
Best ResponseYou've already chosen the best response.01. first you want to switch x and y (and since f(x) can also be written as y) for example: y = (2x^3)^5 (eqn. 1) will become x = (2y^3)^5 (eqn. 2) Then you want to isolate y from eqn. 2. using algebra

Brent0423
 3 years ago
Best ResponseYou've already chosen the best response.0take the 5th root of both sides

Denebel
 3 years ago
Best ResponseYou've already chosen the best response.0Yes.. so then you'll have \[\sqrt[5]{x} = (2y ^{3})\] so what will you do?
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