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zhiyuan3yu5
Group Title
The problem states:
A function f(x,y) is defined on the disc Q: x^2+y^2<=1 and equals 1 on it. The domain of f is D(f)=Q and f(x,y)=1 on Q.
The graph of the function is made of steel and hangs in the air. There is a flower at the origin and a few bees are in the air. There current positions are listed below.
Hint: If the bee is at the height z>1, where should is be in order not to see the flower?
Which of these bees can see the flower?
a) (4,5,6)
b) (2,3,4)
c) (6,6,9)
d) (0,1,2)
e) (2,1,3)
f) (1/3,1/3,1/3)
 one year ago
 one year ago
zhiyuan3yu5 Group Title
The problem states: A function f(x,y) is defined on the disc Q: x^2+y^2<=1 and equals 1 on it. The domain of f is D(f)=Q and f(x,y)=1 on Q. The graph of the function is made of steel and hangs in the air. There is a flower at the origin and a few bees are in the air. There current positions are listed below. Hint: If the bee is at the height z>1, where should is be in order not to see the flower? Which of these bees can see the flower? a) (4,5,6) b) (2,3,4) c) (6,6,9) d) (0,1,2) e) (2,1,3) f) (1/3,1/3,1/3)
 one year ago
 one year ago

This Question is Closed

Coolsector Group TitleBest ResponseYou've already chosen the best response.1
dw:1349639764374:dw
 one year ago

Coolsector Group TitleBest ResponseYou've already chosen the best response.1
this is how i see it ..
 one year ago

Coolsector Group TitleBest ResponseYou've already chosen the best response.1
can you do it now ?
 one year ago

Coolsector Group TitleBest ResponseYou've already chosen the best response.1
hey!:) the bees who can see the flower are the bees under the disc or above the disc but not right above it
 one year ago

Coolsector Group TitleBest ResponseYou've already chosen the best response.1
for example here its fine as well: dw:1349724030045:dw
 one year ago

zhiyuan3yu5 Group TitleBest ResponseYou've already chosen the best response.0
thank you!
 one year ago
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