Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing
morpheous87
Group Title
In H5 the parser don't "like" my formulas. What's wrong with them:
vin*(11/sqrt(1+2K*RS*(VINVT))))
and:
(vINVT)/RS + (1/K*RS^2)*(1sqrt(1+2K*RS*(vINVT)))
 2 years ago
 2 years ago
morpheous87 Group Title
In H5 the parser don't "like" my formulas. What's wrong with them: vin*(11/sqrt(1+2K*RS*(VINVT)))) and: (vINVT)/RS + (1/K*RS^2)*(1sqrt(1+2K*RS*(vINVT)))
 2 years ago
 2 years ago

This Question is Open

morpheous87 Group TitleBest ResponseYou've already chosen the best response.0
Worked, only one left :)
 2 years ago

morpheous87 Group TitleBest ResponseYou've already chosen the best response.0
This one left  (vINVT)/RS + (1/K*RS^2)*(1sqrt(1+2K*RS*(vINVT))), now there isn't a problem with parsing, but seem the formula isn't correct.
 2 years ago

hejå Group TitleBest ResponseYou've already chosen the best response.0
\[(vin*(11/\sqrt(1+2*K*RS*(VINVT))))\] does not work and i cannot see why
 2 years ago

hejå Group TitleBest ResponseYou've already chosen the best response.0
that is the th equation i wrote
 2 years ago

morpheous87 Group TitleBest ResponseYou've already chosen the best response.0
These formulas are for H5P3 and it's correct. I need another one: Q3 for H5P2 SOURCE FOLLOWER LARGE SIGNAL
 2 years ago

Srikanth_Gangula Group TitleBest ResponseYou've already chosen the best response.0
I got it!!! Actually in finding valid Operating ranges \[V0 = [1 + \sqrt{1+2*K*RL*Vs} ] \div KRL\] In the above formula Vs= applied voltage across RL and Drain to Source( i.e Vds).. \[Vs=ids∗RL+Vds(or)Vs=ids∗RL+V0\] But in given problem , by applying KVL to output loop we get \[Vds+idsRL=Vs+(−Vs−)\] \[Vds+ids∗RL=1−(−1)=2\] So in finding V0 substitute\[Vs=2 \] (NOT 1) And we know Valid maximum input range is \[Vgs = V0 + Vthershold\] Applying KVL to input loop \[Vin=Vgs+Vs−\] Substitue the value ...You will get it !!!!!! Cheers!!!!
 2 years ago

benzo Group TitleBest ResponseYou've already chosen the best response.0
help please h5p2 question# 7....What is the minimum value of VDD (in Volts) that we must supply to keep the transistor in the region of saturated operation?
 2 years ago

Srikanth_Gangula Group TitleBest ResponseYou've already chosen the best response.0
Conditions for Saturation region Opereation are.... \[VGS \ge VT\]\[VDS \ge VGSVT\]For the given Circuit \[VDS = VDDVOUT\]\[VGS=VINVOUT\] By using all conditions we get final Condition ....\[VDD \ge VINVT\]Here Substitue Maximum Possible \[VIN\] (As given in your problem.i.e maximum positive swing) Now you have \[VIN\] and \[VT\] So subtitue in the Final Condition for \[VDD \] ,You will get the Solution... Cheers!!!!
 2 years ago

benzo Group TitleBest ResponseYou've already chosen the best response.0
help please h5p2 question# 7....What is the minimum value of VDD (in Volts) that we must supply to keep the transistor in the region of saturated operation?
 2 years ago

Srikanth_Gangula Group TitleBest ResponseYou've already chosen the best response.0
@benzo I gave an clear explanation above to find VDD ....are you interested in knowing answer or the process of getting answer ?... Anyway for the numbers given in my problem set Max \[VIN=7.1\] and Minimun \[VIN=5.7\] So I got Minimum Possible \[VDD=5.1\]
 2 years ago

benzo Group TitleBest ResponseYou've already chosen the best response.0
Srikanth_Gangula i got it thanks lab and home work 100%
 2 years ago

Srikanth_Gangula Group TitleBest ResponseYou've already chosen the best response.0
You are Welcome Benzo!!!!
 2 years ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.