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PedroSoccer Group Title

What type of quadratic equation is represented in the graph below? Not enough information Non-factorable Trinomial Perfect Square Trinomial Difference of Two Squares http://learn.flvs.net/webdav/assessment_images/educator_algebra1_v10/09_02_08.jpg

  • one year ago
  • one year ago

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  1. PedroSoccer Group Title
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    The graph is in the link. Please help? Thanks! :)

    • one year ago
  2. Barcasucks123 Group Title
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    no

    • one year ago
  3. ipm1988 Group Title
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    cannot see the graph

    • one year ago
  4. PedroSoccer Group Title
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    That was not necessary @Barcasucks123.

    • one year ago
  5. PedroSoccer Group Title
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    @ipm1988 I'll work on it :)

    • one year ago
  6. PedroSoccer Group Title
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    hmm. I'm not sure why it wouldn't show up... :$

    • one year ago
  7. PedroSoccer Group Title
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    @ipm1988 does it still not show up?

    • one year ago
  8. ipm1988 Group Title
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    nope just use print screen and post a picture

    • one year ago
  9. PedroSoccer Group Title
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    hmm my computer won't let me. I used control + p and everything

    • one year ago
  10. PedroSoccer Group Title
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    If I click on the link, it shows up for me. maybe my computer is having problems or something. Thanks though! :)

    • one year ago
  11. PedroSoccer Group Title
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    Can you try copying the link and opening it in a new tab though? Just to try?

    • one year ago
  12. AccessDenied Group Title
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    The issue is probably that we don't have accounts / are not logged into a system there like you are. :P "The system is unable to access the cookie that was assigned to your computer upon login. The most likely cause of this problem is an improper access to the course via a bookmark, browser window that was left open, or an improper exit from the system.

    • one year ago
  13. PedroSoccer Group Title
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    Oh, that might be it. Thanks! :)

    • one year ago
  14. AccessDenied Group Title
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    If possible, you could try drawing what the graph looks like here, including any details like intercepts. :)

    • one year ago
  15. PedroSoccer Group Title
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    Okay, I'll give it a shot :)

    • one year ago
  16. PedroSoccer Group Title
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    |dw:1349652754929:dw|

    • one year ago
  17. PedroSoccer Group Title
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    Does that give enough info?

    • one year ago
  18. AccessDenied Group Title
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    Hmm... so those intercepts are (-2, 0), (2, 0), and (0, -4)?

    • one year ago
  19. PedroSoccer Group Title
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    Yes :)

    • one year ago
  20. AccessDenied Group Title
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    Well, with the x-intercepts / our zeros of the graph, we can tell that x = 2 and x = -2 are solutions. That means in terms of a quadratic equation, we have k(x - a)(x - b) = 0: with 'a =2' and 'b = -2' (The extra k is because we could have an extra constant multiplied on there). y = k(x - 2)(x + 2) = 0 y = k(x^2 - 4) Then for the extra 'k', we just have to use (0, -4): -4 = k(0^2 - 4) -4 = k(-4) 1 = k So, plug that in, we simply get: y = x^2 - 4 Looks a lot like a difference of two squares, right? :)

    • one year ago
  21. PedroSoccer Group Title
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    Yes! Thanks so much! :)

    • one year ago
  22. AccessDenied Group Title
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    You're welcome!

    • one year ago
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