anonymous
  • anonymous
A curve passes through the origin of co-ordinates and its gradient is 2x - x^2/3 at the point whose abscissa is x .Find the ordinate of the curve when x = 2
Mathematics
chestercat
  • chestercat
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TuringTest
  • TuringTest
the gradient is\[y'=2x-x^{2/3}\]correct?
anonymous
  • anonymous
TuringTest
  • TuringTest
integrate to find the formula for y, then plug in x=2

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anonymous
  • anonymous
if i integrate i will still have + c
TuringTest
  • TuringTest
use the fact that the origin is on the curve this implies that when x=0, y=0 plug that in to you formula after integration and you can solve for C
anonymous
  • anonymous
which means c is 0
TuringTest
  • TuringTest
correct
anonymous
  • anonymous
thanks i got the way forward..
TuringTest
  • TuringTest
welcome

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