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woleraymond

  • 2 years ago

A curve passes through the origin of co-ordinates and its gradient is 2x - x^2/3 at the point whose abscissa is x .Find the ordinate of the curve when x = 2

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  1. TuringTest
    • 2 years ago
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    the gradient is\[y'=2x-x^{2/3}\]correct?

  2. woleraymond
    • 2 years ago
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    @TuringTest yep

  3. TuringTest
    • 2 years ago
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    integrate to find the formula for y, then plug in x=2

  4. woleraymond
    • 2 years ago
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    if i integrate i will still have + c

  5. TuringTest
    • 2 years ago
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    use the fact that the origin is on the curve this implies that when x=0, y=0 plug that in to you formula after integration and you can solve for C

  6. woleraymond
    • 2 years ago
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    which means c is 0

  7. TuringTest
    • 2 years ago
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    correct

  8. woleraymond
    • 2 years ago
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    thanks i got the way forward..

  9. TuringTest
    • 2 years ago
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    welcome

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