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 2 years ago
A curve passes through the origin of coordinates and its gradient is 2x  x^2/3 at the point whose abscissa is x .Find the ordinate of the curve when x = 2
 2 years ago
A curve passes through the origin of coordinates and its gradient is 2x  x^2/3 at the point whose abscissa is x .Find the ordinate of the curve when x = 2

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TuringTest
 2 years ago
Best ResponseYou've already chosen the best response.1the gradient is\[y'=2xx^{2/3}\]correct?

TuringTest
 2 years ago
Best ResponseYou've already chosen the best response.1integrate to find the formula for y, then plug in x=2

woleraymond
 2 years ago
Best ResponseYou've already chosen the best response.0if i integrate i will still have + c

TuringTest
 2 years ago
Best ResponseYou've already chosen the best response.1use the fact that the origin is on the curve this implies that when x=0, y=0 plug that in to you formula after integration and you can solve for C

woleraymond
 2 years ago
Best ResponseYou've already chosen the best response.0thanks i got the way forward..
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