woleraymond
A curve passes through the origin of co-ordinates and its gradient is 2x - x^2/3 at the point whose abscissa is x .Find the ordinate of the curve when x = 2
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TuringTest
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the gradient is\[y'=2x-x^{2/3}\]correct?
woleraymond
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@TuringTest yep
TuringTest
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integrate to find the formula for y, then plug in x=2
woleraymond
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if i integrate i will still have + c
TuringTest
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use the fact that the origin is on the curve
this implies that when x=0, y=0
plug that in to you formula after integration and you can solve for C
woleraymond
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which means c is 0
TuringTest
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correct
woleraymond
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thanks i got the way forward..
TuringTest
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welcome