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A curve passes through the origin of coordinates and its gradient is 2x  x^2/3 at the point whose abscissa is x .Find the ordinate of the curve when x = 2
 one year ago
 one year ago
A curve passes through the origin of coordinates and its gradient is 2x  x^2/3 at the point whose abscissa is x .Find the ordinate of the curve when x = 2
 one year ago
 one year ago

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TuringTestBest ResponseYou've already chosen the best response.1
the gradient is\[y'=2xx^{2/3}\]correct?
 one year ago

TuringTestBest ResponseYou've already chosen the best response.1
integrate to find the formula for y, then plug in x=2
 one year ago

woleraymondBest ResponseYou've already chosen the best response.0
if i integrate i will still have + c
 one year ago

TuringTestBest ResponseYou've already chosen the best response.1
use the fact that the origin is on the curve this implies that when x=0, y=0 plug that in to you formula after integration and you can solve for C
 one year ago

woleraymondBest ResponseYou've already chosen the best response.0
which means c is 0
 one year ago

woleraymondBest ResponseYou've already chosen the best response.0
thanks i got the way forward..
 one year ago
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