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woleraymond

A curve passes through the origin of co-ordinates and its gradient is 2x - x^2/3 at the point whose abscissa is x .Find the ordinate of the curve when x = 2

  • one year ago
  • one year ago

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  1. TuringTest
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    the gradient is\[y'=2x-x^{2/3}\]correct?

    • one year ago
  2. woleraymond
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    @TuringTest yep

    • one year ago
  3. TuringTest
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    integrate to find the formula for y, then plug in x=2

    • one year ago
  4. woleraymond
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    if i integrate i will still have + c

    • one year ago
  5. TuringTest
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    use the fact that the origin is on the curve this implies that when x=0, y=0 plug that in to you formula after integration and you can solve for C

    • one year ago
  6. woleraymond
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    which means c is 0

    • one year ago
  7. TuringTest
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    correct

    • one year ago
  8. woleraymond
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    thanks i got the way forward..

    • one year ago
  9. TuringTest
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    welcome

    • one year ago
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