Here's the question you clicked on:
v.s
Find the derivative of the function using the definition of derivative. g(x) = sqroot8 − x g'(x) =
|dw:1349647355572:dw| Were you able to get the limit set up correctly? :)
\[\left(\begin{matrix}-2x \\ \sqrt{8-(x+h)}+\sqrt{8-x}\end{matrix}\right)\]
dont you have to cancel out the h
yes from this step you can cancel the h's, since it's the only term in the top. I'm not sure how you did it in your problem as you had it before though, You would've had to divide an h out of the -2x, and you didn't have one in there. D:
couldn't i put -1 on the top
|dw:1349648375393:dw| Yes, good :)