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anonymous
 4 years ago
Find the lim of tan(2x)/(3x+sinx) as x approaches 0
anonymous
 4 years ago
Find the lim of tan(2x)/(3x+sinx) as x approaches 0

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NoelGreco
 4 years ago
Best ResponseYou've already chosen the best response.0I don't see any quick way without l'Hopital.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0l'Hopitals has taken me back to the start

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0If l'Hopital doesn't work the first time but gives you the condition for it again, you can repeat it. You might have better luck the second time around.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0One way is to use l'Hopital, but a faster way is to use the linear approximations for sine and tangent. The answer is 1/2.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0THE DIFFERENTIAL IS SEC^2(X)/3+COS(x).numerator is 1 and denominator is 4 answer is 1/4 how did you get 1/2??????

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0pasta! skywalker94 is right! Using l'Hopital, we'll get 1/2. \[\lim_{x \rightarrow 0}(\tan2x/(3x+sinx))=\lim_{x \rightarrow 0}[2(1+\tan^{2}2x)/(3+cosx)]=1/2\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0use expansion method it is the fastest.... tanx = x + x^3/3............sinx = x  x^3/3!

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0and from that the ans is 1/2 Math Physics and skywalker ur right..!!!!
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