## kvdop Group Title Find the lim of tan(2x)/(3x+sinx) as x approaches 0 one year ago one year ago

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1. NoelGreco Group Title

I don't see any quick way without l'Hopital.

2. pasta Group Title

l'Hopitals has taken me back to the start

3. 2le Group Title

If l'Hopital doesn't work the first time but gives you the condition for it again, you can repeat it. You might have better luck the second time around.

4. pasta Group Title

1/4

5. skywalker94 Group Title

One way is to use l'Hopital, but a faster way is to use the linear approximations for sine and tangent. The answer is 1/2.

6. pasta Group Title

THE DIFFERENTIAL IS SEC^2(X)/3+COS(x).numerator is 1 and denominator is 4 answer is 1/4 how did you get 1/2??????

7. MathPhysics Group Title

pasta! skywalker94 is right! Using l'Hopital, we'll get 1/2. $\lim_{x \rightarrow 0}(\tan2x/(3x+sinx))=\lim_{x \rightarrow 0}[2(1+\tan^{2}2x)/(3+cosx)]=1/2$