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There would be a straight line of x=0, not dotted since it's inclusive...and shade the whole graph under that line...so quadrants 2 and 3 would be shaded in with a solid line at x=0
I get y > 2x + 1.. but how do you do it like when theres no slope .... like that...
ohhh I though 0 had to be on one side I guess it can be on the line too!
Same thing :] Just graph whatever the graph would look like. In this case, the line would have no slope, or just be a vertical line at x=0. Then you shade the appropriate regions depending on whether it's greater than or less than
Yup! :D I think you got it!
You can plug in different values into your variable and check to see if it satisfies your inequality. If it does, then that "side" of the graph/line is usually shaded, but if not, try another value on the other side.
I DONT GET IT I flutterING HATE MATH
Ok, so first you want to graph the equation as if the inquality weren't there and it was just an equal sign. In this case, x=0. Then with the "greater than/less than" requirements, you plug in random x values on different sides of the line. So...you could try x=-1 and x=1. With the original inequality of x<0, see if it's true when you plug in the two values for x
If it's true, shade it in, but if not, then don't
Dude help me out
I get how its horizontal on the x line but how do you know where to shade
can you you show me instead of writing
NUMBER LINES?!?! WTF?!?!
do you have skype or something
Because every value of x less than zero is on that side