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Find the limit, if it exists. (If an answer does not exist, enter DNE.)
lim sqroot t+ t^2/6t − t^2
t→inf
 one year ago
 one year ago
Find the limit, if it exists. (If an answer does not exist, enter DNE.) lim sqroot t+ t^2/6t − t^2 t→inf
 one year ago
 one year ago

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TuringTestBest ResponseYou've already chosen the best response.0
\[\lim_{t\to\infty}\frac{\sqrt{t+t^2}}{6tt^2}\]is this right?
 one year ago

v.sBest ResponseYou've already chosen the best response.0
the sqaure root is on for the t
 one year ago

TuringTestBest ResponseYou've already chosen the best response.0
\[\lim_{t\to\infty}\frac{\sqrt t+t^2}{6tt^2}\]
 one year ago

TuringTestBest ResponseYou've already chosen the best response.0
divide top and bottom by t^2
 one year ago

v.sBest ResponseYou've already chosen the best response.0
\[\frac{ \sqrt{t} }{ 6t }\]
 one year ago

TuringTestBest ResponseYou've already chosen the best response.0
divide each term by t^2
 one year ago

v.sBest ResponseYou've already chosen the best response.0
i'm oo confused can you show me
 one year ago

TuringTestBest ResponseYou've already chosen the best response.0
\[\lim_{t\to\infty}\frac{\frac1{t^2}(\sqrt t+t^2)}{\frac1{t^2}(6tt^2)}\]
 one year ago

TuringTestBest ResponseYou've already chosen the best response.0
this site is about teaching, not handing out answers can you not simplify the numerator and denominator? this is algebra, you should know this.
 one year ago

TuringTestBest ResponseYou've already chosen the best response.0
what about the t^2's on the right?
 one year ago

TuringTestBest ResponseYou've already chosen the best response.0
what is\[\frac1{t^2}(\sqrt t+t^2)\]?
 one year ago

v.sBest ResponseYou've already chosen the best response.0
doesn't the t^2/t^2 cancels out
 one year ago

TuringTestBest ResponseYou've already chosen the best response.0
yes, but you never wrote the 1
 one year ago

v.sBest ResponseYou've already chosen the best response.0
(sqroot (t)+1)/t^2/(6t1)/t^2
 one year ago

TuringTestBest ResponseYou've already chosen the best response.0
those 1's should not be over t^2, they cancel like you said
 one year ago

TuringTestBest ResponseYou've already chosen the best response.0
just do the top\[\frac1{t^2}(\sqrt t+t^2)\]
 one year ago

v.sBest ResponseYou've already chosen the best response.0
sqroot (t)/t^2 +1/ 6t/t^2 +1
 one year ago

TuringTestBest ResponseYou've already chosen the best response.0
yes, and what is sqrt(t)/t^2 simplified?
 one year ago

TuringTestBest ResponseYou've already chosen the best response.0
\[\sqrt[b]{x^a}=x^{a/b}\]so\[\sqrt t=t^{1/2}\]and\[\frac{t^a}{t^b}=t^{ab}\]use those two rules together
 one year ago
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