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v.s
 3 years ago
Find the limit, if it exists. (If an answer does not exist, enter DNE.)
lim sqroot t+ t^2/6t − t^2
t→inf
v.s
 3 years ago
Find the limit, if it exists. (If an answer does not exist, enter DNE.) lim sqroot t+ t^2/6t − t^2 t→inf

This Question is Closed

TuringTest
 3 years ago
Best ResponseYou've already chosen the best response.0\[\lim_{t\to\infty}\frac{\sqrt{t+t^2}}{6tt^2}\]is this right?

v.s
 3 years ago
Best ResponseYou've already chosen the best response.0the sqaure root is on for the t

TuringTest
 3 years ago
Best ResponseYou've already chosen the best response.0\[\lim_{t\to\infty}\frac{\sqrt t+t^2}{6tt^2}\]

TuringTest
 3 years ago
Best ResponseYou've already chosen the best response.0divide top and bottom by t^2

v.s
 3 years ago
Best ResponseYou've already chosen the best response.0\[\frac{ \sqrt{t} }{ 6t }\]

TuringTest
 3 years ago
Best ResponseYou've already chosen the best response.0divide each term by t^2

v.s
 3 years ago
Best ResponseYou've already chosen the best response.0i'm oo confused can you show me

TuringTest
 3 years ago
Best ResponseYou've already chosen the best response.0\[\lim_{t\to\infty}\frac{\frac1{t^2}(\sqrt t+t^2)}{\frac1{t^2}(6tt^2)}\]

TuringTest
 3 years ago
Best ResponseYou've already chosen the best response.0this site is about teaching, not handing out answers can you not simplify the numerator and denominator? this is algebra, you should know this.

TuringTest
 3 years ago
Best ResponseYou've already chosen the best response.0what about the t^2's on the right?

TuringTest
 3 years ago
Best ResponseYou've already chosen the best response.0what is\[\frac1{t^2}(\sqrt t+t^2)\]?

v.s
 3 years ago
Best ResponseYou've already chosen the best response.0doesn't the t^2/t^2 cancels out

TuringTest
 3 years ago
Best ResponseYou've already chosen the best response.0yes, but you never wrote the 1

v.s
 3 years ago
Best ResponseYou've already chosen the best response.0(sqroot (t)+1)/t^2/(6t1)/t^2

TuringTest
 3 years ago
Best ResponseYou've already chosen the best response.0those 1's should not be over t^2, they cancel like you said

TuringTest
 3 years ago
Best ResponseYou've already chosen the best response.0just do the top\[\frac1{t^2}(\sqrt t+t^2)\]

v.s
 3 years ago
Best ResponseYou've already chosen the best response.0sqroot (t)/t^2 +1/ 6t/t^2 +1

TuringTest
 3 years ago
Best ResponseYou've already chosen the best response.0yes, and what is sqrt(t)/t^2 simplified?

TuringTest
 3 years ago
Best ResponseYou've already chosen the best response.0\[\sqrt[b]{x^a}=x^{a/b}\]so\[\sqrt t=t^{1/2}\]and\[\frac{t^a}{t^b}=t^{ab}\]use those two rules together
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