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babydoll332
Group Title
A projectile is thrown upward so that its distance above the ground after t seconds is h =  16t2 + 440t.
After how many seconds does it reach its maximum height?
 2 years ago
 2 years ago
babydoll332 Group Title
A projectile is thrown upward so that its distance above the ground after t seconds is h =  16t2 + 440t. After how many seconds does it reach its maximum height?
 2 years ago
 2 years ago

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Outkast3r09 Group TitleBest ResponseYou've already chosen the best response.1
few ways to solve this
 2 years ago

completeidiot Group TitleBest ResponseYou've already chosen the best response.0
are you familiar with derivatives?
 2 years ago

babydoll332 Group TitleBest ResponseYou've already chosen the best response.0
with a graph correct?
 2 years ago

Outkast3r09 Group TitleBest ResponseYou've already chosen the best response.1
Without Calculus ydw:1349657074734:dwou know that this graph will look like this
 2 years ago

Outkast3r09 Group TitleBest ResponseYou've already chosen the best response.1
so you know it hits its maximum height at its' vertex. you know how to find the x for the vertex by \[x=\frac{b}{2a}\]
 2 years ago

Outkast3r09 Group TitleBest ResponseYou've already chosen the best response.1
x so happens to be time in our case =P
 2 years ago

Outkast3r09 Group TitleBest ResponseYou've already chosen the best response.1
dw:1349657191197:dw
 2 years ago

babydoll332 Group TitleBest ResponseYou've already chosen the best response.0
21 seconds
 2 years ago

Outkast3r09 Group TitleBest ResponseYou've already chosen the best response.1
with calculus \[y=16t^2+440t\] \[y'=32t+440=velocity\] we know that the velocity of y is 0 at the point of max height so \[0=32t+440\] \[440=32t\] \[\frac{440}{32}=t\] 13.75 seconds
 2 years ago

Outkast3r09 Group TitleBest ResponseYou've already chosen the best response.1
without calculus \[ax^2+bx+c\] in our case \[ax^2+bx\] \[x=\frac{b}{2a}\] \[\frac{440}{32}\] 13.75 seconds
 2 years ago

babydoll332 Group TitleBest ResponseYou've already chosen the best response.0
oh wow i was completly of thanks alot !!!
 2 years ago
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