anonymous
  • anonymous
State the horizontal asymptote of the rational function. f(x) = x^2+6x-8/x-8
Mathematics
  • Stacey Warren - Expert brainly.com
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katieb
  • katieb
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anonymous
  • anonymous
Can you find the derivative of this function first?
anonymous
  • anonymous
Set the derivative equal to zero
anonymous
  • anonymous
i normally pluged it into the graph

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anonymous
  • anonymous
https://www.google.com/search?q=x%5E2%2B6x-8%2Fx-8&rlz=1C1CHFX_enUS470US470&oq=x%5E2%2B6x-8%2Fx-8&sugexp=chrome,mod=11&sourceid=chrome&ie=UTF-8#hl=en&safe=off&rlz=1C1CHFX_enUS470US470&sclient=psy-ab&q=(x%5E2%2B6x-8)%2F(x-8)&oq=(x%5E2%2B6x-8)%2F(x-8)&gs_l=serp.3...2141.18850.1.19323.8.8.0.0.0.0.120.792.5j3.8.0.les%3B..0.0...1c.1.Q4G1o6RnZBs&psj=1&bav=on.2,or.r_gc.r_pw.r_cp.r_qf.&fp=35197abecd6f379b&biw=1422&bih=776
anonymous
  • anonymous
All right, I'll assume you can't do that now. Is this the equation:\[x ^{2}+\frac{ 6x-8 }{ x-8 }\]
anonymous
  • anonymous
i see what u posted @timo86m but idk what the horrizontal is
anonymous
  • anonymous
@L.T. ok what would i do
anonymous
  • anonymous
there is a slant retricemptote.. not a horizontal =/
anonymous
  • anonymous
lol asymptote... lame chat =]
anonymous
  • anonymous
the degree of the top is greater than the degree of the bottom therefore no horizontal asymptote no calc needed, that is all
anonymous
  • anonymous
If what I wrote was the equation, then you find the derivative of each term in the equation, using the quotient rule on the second term.
anonymous
  • anonymous
reall no horizontal ?
anonymous
  • anonymous
if the degree of the bottom was greater, then the horizontal asymptote would be \(y=0\) if the degree of the top is greater no horizontal asymptote
anonymous
  • anonymous
yes there is a slant use long division
anonymous
  • anonymous
if you ned to find the slant asymptote
anonymous
  • anonymous
if the degrees are the same, it is the ration of the leading coefficients that is it
anonymous
  • anonymous
so the anserw is no horizontal asymptote
anonymous
  • anonymous
that is correct. there is none
anonymous
  • anonymous
it has a slanted asymptote with a slope of 1045/1058
anonymous
  • anonymous
ok thank you so much
anonymous
  • anonymous
how'd you find that @timo86m
anonymous
  • anonymous
take derivitive of (x^2+6x-8)/(x-8) \[{\frac {2\,x+6}{x-8}}-{\frac {{x}^{2}+6\,x-8}{ \left( x-8 \right) ^{2} }} \] then just plug in a very high or very low value for x It has roughly a V asymptote of 8.5
anonymous
  • anonymous
My bad; must have misread the question :(

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