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burhan101
Group Title
find the equation of this graph (picture included) i have started it off but don't know how to finish it
 2 years ago
 2 years ago
burhan101 Group Title
find the equation of this graph (picture included) i have started it off but don't know how to finish it
 2 years ago
 2 years ago

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burhan101 Group TitleBest ResponseYou've already chosen the best response.1
\[h(x)=k(x+3)(x2)(x3)\]
 2 years ago

burhan101 Group TitleBest ResponseYou've already chosen the best response.1
3=k(2+3)(22)(23)
 2 years ago

CliffSedge Group TitleBest ResponseYou've already chosen the best response.1
Looks alright so far.
 2 years ago

burhan101 Group TitleBest ResponseYou've already chosen the best response.1
is there more to or is it all ? :S
 2 years ago

CliffSedge Group TitleBest ResponseYou've already chosen the best response.1
Er., wait, no
 2 years ago

CliffSedge Group TitleBest ResponseYou've already chosen the best response.1
In your solving for k, you need to put in 0 for x if you're using the yintercept.
 2 years ago

burhan101 Group TitleBest ResponseYou've already chosen the best response.1
would that make k zero ?
 2 years ago

CliffSedge Group TitleBest ResponseYou've already chosen the best response.1
No, what you did made 3=0.
 2 years ago

burhan101 Group TitleBest ResponseYou've already chosen the best response.1
ohh i see
 2 years ago

CliffSedge Group TitleBest ResponseYou've already chosen the best response.1
"3=k(2+3)(22)(23)" 3=k(5)(0)(1) > 3=0
 2 years ago

burhan101 Group TitleBest ResponseYou've already chosen the best response.1
i cancelled out k too :/
 2 years ago

CliffSedge Group TitleBest ResponseYou've already chosen the best response.1
(2,3) is not a solution to the equation, but (0,3) is.
 2 years ago

burhan101 Group TitleBest ResponseYou've already chosen the best response.1
is dont see where you're getting (2,3) from
 2 years ago

CliffSedge Group TitleBest ResponseYou've already chosen the best response.1
You plugged in x=2 and set y=3 in your attempt to solve for k.
 2 years ago

CliffSedge Group TitleBest ResponseYou've already chosen the best response.1
So, I don't see where *you* got (2,3) from. ;)
 2 years ago

burhan101 Group TitleBest ResponseYou've already chosen the best response.1
ohhhh ! i'm supposed to set x as 0 right ?
 2 years ago

CliffSedge Group TitleBest ResponseYou've already chosen the best response.1
Yes, because you know the yintercept is 3.
 2 years ago

burhan101 Group TitleBest ResponseYou've already chosen the best response.1
ohh okay i see it now :$
 2 years ago

CliffSedge Group TitleBest ResponseYou've already chosen the best response.1
You could use any other known point, but that one is the most convenient.
 2 years ago

burhan101 Group TitleBest ResponseYou've already chosen the best response.1
so k would be 1/6
 2 years ago

burhan101 Group TitleBest ResponseYou've already chosen the best response.1
and h(x) = 1/6 (x+3)(x2)(x3)
 2 years ago

CliffSedge Group TitleBest ResponseYou've already chosen the best response.1
never mind h(x) = k(x+3)(x2)(x3) h(0)=3 3=k(3)(2)(3) 3=18k
 2 years ago

CliffSedge Group TitleBest ResponseYou've already chosen the best response.1
Yep, it's all good.
 2 years ago

burhan101 Group TitleBest ResponseYou've already chosen the best response.1
Thankyou once again :D
 2 years ago

burhan101 Group TitleBest ResponseYou've already chosen the best response.1
if you're not busy, can you help me with one last question
 2 years ago

CliffSedge Group TitleBest ResponseYou've already chosen the best response.1
I think you know what you're doing, just be careful and don't rush through it.
 2 years ago

CliffSedge Group TitleBest ResponseYou've already chosen the best response.1
Oh, sure. I think I can handle one more.
 2 years ago

burhan101 Group TitleBest ResponseYou've already chosen the best response.1
thanks :)
 2 years ago

burhan101 Group TitleBest ResponseYou've already chosen the best response.1
Find the equation of a cubic polynomial that gives a remainder of 3, when divided by (x+2)
 2 years ago

burhan101 Group TitleBest ResponseYou've already chosen the best response.1
how would i approach this problem ?
 2 years ago

CliffSedge Group TitleBest ResponseYou've already chosen the best response.1
Do you remember the remainder theorem?
 2 years ago

burhan101 Group TitleBest ResponseYou've already chosen the best response.1
yes, the factor is equal to zero
 2 years ago

CliffSedge Group TitleBest ResponseYou've already chosen the best response.1
Sort of..
 2 years ago

CliffSedge Group TitleBest ResponseYou've already chosen the best response.1
It kind of goes like this. If (x+2) is a factor of the polynomial, then dividing by (x+2) would have a remainder of 0. And, if (x+2) is a factor, then x = 2 is a root of the polynomial. If (x+2) is not a factor, then f(2) = the remainder.
 2 years ago

burhan101 Group TitleBest ResponseYou've already chosen the best response.1
but how would i use this info to make an equation, this is like working backwards from the norm :/
 2 years ago

CliffSedge Group TitleBest ResponseYou've already chosen the best response.1
Yes, a lot of what you're doing here is using concepts to 'unsolve' equations.
 2 years ago

CliffSedge Group TitleBest ResponseYou've already chosen the best response.1
If dividing by (x+2) gives a remainder of 3, then you know (2,3) is a solution to the equation.
 2 years ago

burhan101 Group TitleBest ResponseYou've already chosen the best response.1
yes that's true
 2 years ago

CliffSedge Group TitleBest ResponseYou've already chosen the best response.1
It's a pretty openended question; there will be many functions (infinite, really) that you could develop that have that point on it.
 2 years ago

burhan101 Group TitleBest ResponseYou've already chosen the best response.1
i still don't really get it, like i understand what it is asking for but i don't knw how to get to it :/
 2 years ago

CliffSedge Group TitleBest ResponseYou've already chosen the best response.1
It wants a cubic function, so what does an equation for one of those look like?
 2 years ago

burhan101 Group TitleBest ResponseYou've already chosen the best response.1
like x^33x^24x5
 2 years ago

CliffSedge Group TitleBest ResponseYou've already chosen the best response.1
Sure, something like that, so to be more general, start with \[y=ax^3+bx^2+cx+d\]
 2 years ago

CliffSedge Group TitleBest ResponseYou've already chosen the best response.1
You know what x and y are, and three out of those four variables are free parameters, so choose whatever you want for those, then solve for the fourth one.
 2 years ago

CliffSedge Group TitleBest ResponseYou've already chosen the best response.1
You could even set three of them =0 if you wanted to be really lazy about it. (General math tip: be lazy whenever possible)
 2 years ago

burhan101 Group TitleBest ResponseYou've already chosen the best response.1
so something like \[y=x^3+x^2+x+d \] ?
 2 years ago

CliffSedge Group TitleBest ResponseYou've already chosen the best response.1
I don't see why not.
 2 years ago

burhan101 Group TitleBest ResponseYou've already chosen the best response.1
hmm but "d" has to be a specific number right
 2 years ago

CliffSedge Group TitleBest ResponseYou've already chosen the best response.1
Yep, that's what you're solving for. Me, I went with y=ax^3, then solved for a.
 2 years ago

CliffSedge Group TitleBest ResponseYou've already chosen the best response.1
(but I'm lazy like that)
 2 years ago

burhan101 Group TitleBest ResponseYou've already chosen the best response.1
ohh that way a would be 3/8 right
 2 years ago

CliffSedge Group TitleBest ResponseYou've already chosen the best response.1
And if you want, you can verify that \[\large\frac{3}{8}x^3 \div (x+2)\] will give a remainder of 3.
 2 years ago

burhan101 Group TitleBest ResponseYou've already chosen the best response.1
\[:. y=\frac{ 3 }{ 8 }x^3\]
 2 years ago

CliffSedge Group TitleBest ResponseYou've already chosen the best response.1
Looks beautiful.
 2 years ago

burhan101 Group TitleBest ResponseYou've already chosen the best response.1
thank you so much for your helppp, you're amazing :D
 2 years ago

CliffSedge Group TitleBest ResponseYou've already chosen the best response.1
My pleasure.
 2 years ago
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