Quantcast

Got Homework?

Connect with other students for help. It's a free community.

  • across
    MIT Grad Student
    Online now
  • laura*
    Helped 1,000 students
    Online now
  • Hero
    College Math Guru
    Online now

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

burhan101 Group Title

find the equation of this graph (picture included) i have started it off but don't know how to finish it

  • one year ago
  • one year ago

  • This Question is Closed
  1. burhan101 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    • one year ago
    1 Attachment
  2. burhan101 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    \[h(x)=k(x+3)(x-2)(x-3)\]

    • one year ago
  3. burhan101 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    3=k(2+3)(2-2)(2-3)

    • one year ago
  4. burhan101 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    3=k

    • one year ago
  5. CliffSedge Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    Looks alright so far.

    • one year ago
  6. burhan101 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    is there more to or is it all ? :S

    • one year ago
  7. CliffSedge Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    Er., wait, no

    • one year ago
  8. CliffSedge Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    In your solving for k, you need to put in 0 for x if you're using the y-intercept.

    • one year ago
  9. burhan101 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    would that make k zero ?

    • one year ago
  10. CliffSedge Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    No, what you did made 3=0.

    • one year ago
  11. burhan101 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    ohh i see

    • one year ago
  12. CliffSedge Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    "3=k(2+3)(2-2)(2-3)" 3=k(5)(0)(-1) -> 3=0

    • one year ago
  13. burhan101 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    i cancelled out k too :/

    • one year ago
  14. CliffSedge Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    (2,3) is not a solution to the equation, but (0,3) is.

    • one year ago
  15. burhan101 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    is dont see where you're getting (2,3) from

    • one year ago
  16. CliffSedge Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    You plugged in x=2 and set y=3 in your attempt to solve for k.

    • one year ago
  17. CliffSedge Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    So, I don't see where *you* got (2,3) from. ;-)

    • one year ago
  18. burhan101 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    ohhhh ! i'm supposed to set x as 0 right ?

    • one year ago
  19. CliffSedge Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    Yes, because you know the y-intercept is 3.

    • one year ago
  20. burhan101 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    ohh okay i see it now :$

    • one year ago
  21. CliffSedge Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    You could use any other known point, but that one is the most convenient.

    • one year ago
  22. burhan101 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    so k would be 1/6

    • one year ago
  23. burhan101 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    and h(x) = 1/6 (x+3)(x-2)(x-3)

    • one year ago
  24. CliffSedge Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    never mind h(x) = k(x+3)(x-2)(x-3) h(0)=3 3=k(3)(-2)(-3) 3=18k

    • one year ago
  25. CliffSedge Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    Yep, it's all good.

    • one year ago
  26. burhan101 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    Thank-you once again :D

    • one year ago
  27. burhan101 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    if you're not busy, can you help me with one last question

    • one year ago
  28. CliffSedge Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    I think you know what you're doing, just be careful and don't rush through it.

    • one year ago
  29. CliffSedge Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    Oh, sure. I think I can handle one more.

    • one year ago
  30. burhan101 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    thanks :)

    • one year ago
  31. burhan101 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    Find the equation of a cubic polynomial that gives a remainder of 3, when divided by (x+2)

    • one year ago
  32. burhan101 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    how would i approach this problem ?

    • one year ago
  33. CliffSedge Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    Do you remember the remainder theorem?

    • one year ago
  34. burhan101 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    yes, the factor is equal to zero

    • one year ago
  35. CliffSedge Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    Sort of..

    • one year ago
  36. CliffSedge Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    It kind of goes like this. If (x+2) is a factor of the polynomial, then dividing by (x+2) would have a remainder of 0. And, if (x+2) is a factor, then x = -2 is a root of the polynomial. If (x+2) is not a factor, then f(-2) = the remainder.

    • one year ago
  37. burhan101 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    but how would i use this info to make an equation, this is like working backwards from the norm :/

    • one year ago
  38. CliffSedge Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    Yes, a lot of what you're doing here is using concepts to 'unsolve' equations.

    • one year ago
  39. CliffSedge Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    If dividing by (x+2) gives a remainder of 3, then you know (-2,3) is a solution to the equation.

    • one year ago
  40. burhan101 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    yes that's true

    • one year ago
  41. CliffSedge Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    It's a pretty open-ended question; there will be many functions (infinite, really) that you could develop that have that point on it.

    • one year ago
  42. burhan101 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    i still don't really get it, like i understand what it is asking for but i don't knw how to get to it :/

    • one year ago
  43. CliffSedge Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    It wants a cubic function, so what does an equation for one of those look like?

    • one year ago
  44. burhan101 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    like x^3-3x^2-4x-5

    • one year ago
  45. CliffSedge Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    Sure, something like that, so to be more general, start with \[y=ax^3+bx^2+cx+d\]

    • one year ago
  46. CliffSedge Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    You know what x and y are, and three out of those four variables are free parameters, so choose whatever you want for those, then solve for the fourth one.

    • one year ago
  47. CliffSedge Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    You could even set three of them =0 if you wanted to be really lazy about it. (General math tip: be lazy whenever possible)

    • one year ago
  48. burhan101 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    so something like \[y=x^3+x^2+x+d \] ?

    • one year ago
  49. CliffSedge Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    I don't see why not.

    • one year ago
  50. burhan101 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    hmm but "d" has to be a specific number right

    • one year ago
  51. CliffSedge Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    Yep, that's what you're solving for. Me, I went with y=ax^3, then solved for a.

    • one year ago
  52. CliffSedge Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    (but I'm lazy like that)

    • one year ago
  53. burhan101 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    ohh that way a would be -3/8 right

    • one year ago
  54. CliffSedge Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    Uh huh.

    • one year ago
  55. CliffSedge Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    And if you want, you can verify that \[\large\frac{-3}{8}x^3 \div (x+2)\] will give a remainder of 3.

    • one year ago
  56. burhan101 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    \[:. y=\frac{ -3 }{ 8 }x^3\]

    • one year ago
  57. CliffSedge Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    Looks beautiful.

    • one year ago
  58. burhan101 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    thank you so much for your helppp, you're amazing :D

    • one year ago
  59. CliffSedge Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    My pleasure.

    • one year ago
    • Attachments:

See more questions >>>

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.