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anonymous
 4 years ago
find the equation of this graph (picture included) i have started it off but don't know how to finish it
anonymous
 4 years ago
find the equation of this graph (picture included) i have started it off but don't know how to finish it

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[h(x)=k(x+3)(x2)(x3)\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Looks alright so far.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0is there more to or is it all ? :S

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0In your solving for k, you need to put in 0 for x if you're using the yintercept.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0would that make k zero ?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0No, what you did made 3=0.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0"3=k(2+3)(22)(23)" 3=k(5)(0)(1) > 3=0

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i cancelled out k too :/

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0(2,3) is not a solution to the equation, but (0,3) is.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0is dont see where you're getting (2,3) from

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0You plugged in x=2 and set y=3 in your attempt to solve for k.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0So, I don't see where *you* got (2,3) from. ;)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ohhhh ! i'm supposed to set x as 0 right ?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Yes, because you know the yintercept is 3.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ohh okay i see it now :$

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0You could use any other known point, but that one is the most convenient.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0and h(x) = 1/6 (x+3)(x2)(x3)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0never mind h(x) = k(x+3)(x2)(x3) h(0)=3 3=k(3)(2)(3) 3=18k

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Thankyou once again :D

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0if you're not busy, can you help me with one last question

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I think you know what you're doing, just be careful and don't rush through it.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Oh, sure. I think I can handle one more.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Find the equation of a cubic polynomial that gives a remainder of 3, when divided by (x+2)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0how would i approach this problem ?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Do you remember the remainder theorem?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yes, the factor is equal to zero

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0It kind of goes like this. If (x+2) is a factor of the polynomial, then dividing by (x+2) would have a remainder of 0. And, if (x+2) is a factor, then x = 2 is a root of the polynomial. If (x+2) is not a factor, then f(2) = the remainder.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0but how would i use this info to make an equation, this is like working backwards from the norm :/

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Yes, a lot of what you're doing here is using concepts to 'unsolve' equations.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0If dividing by (x+2) gives a remainder of 3, then you know (2,3) is a solution to the equation.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0It's a pretty openended question; there will be many functions (infinite, really) that you could develop that have that point on it.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i still don't really get it, like i understand what it is asking for but i don't knw how to get to it :/

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0It wants a cubic function, so what does an equation for one of those look like?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Sure, something like that, so to be more general, start with \[y=ax^3+bx^2+cx+d\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0You know what x and y are, and three out of those four variables are free parameters, so choose whatever you want for those, then solve for the fourth one.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0You could even set three of them =0 if you wanted to be really lazy about it. (General math tip: be lazy whenever possible)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so something like \[y=x^3+x^2+x+d \] ?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0hmm but "d" has to be a specific number right

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Yep, that's what you're solving for. Me, I went with y=ax^3, then solved for a.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0(but I'm lazy like that)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ohh that way a would be 3/8 right

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0And if you want, you can verify that \[\large\frac{3}{8}x^3 \div (x+2)\] will give a remainder of 3.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[:. y=\frac{ 3 }{ 8 }x^3\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0thank you so much for your helppp, you're amazing :D
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