A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 3 years ago
find the equation of this graph (picture included) i have started it off but don't know how to finish it
anonymous
 3 years ago
find the equation of this graph (picture included) i have started it off but don't know how to finish it

This Question is Closed

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[h(x)=k(x+3)(x2)(x3)\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Looks alright so far.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0is there more to or is it all ? :S

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0In your solving for k, you need to put in 0 for x if you're using the yintercept.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0would that make k zero ?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0No, what you did made 3=0.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0"3=k(2+3)(22)(23)" 3=k(5)(0)(1) > 3=0

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i cancelled out k too :/

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0(2,3) is not a solution to the equation, but (0,3) is.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0is dont see where you're getting (2,3) from

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0You plugged in x=2 and set y=3 in your attempt to solve for k.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0So, I don't see where *you* got (2,3) from. ;)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0ohhhh ! i'm supposed to set x as 0 right ?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Yes, because you know the yintercept is 3.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0ohh okay i see it now :$

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0You could use any other known point, but that one is the most convenient.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0and h(x) = 1/6 (x+3)(x2)(x3)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0never mind h(x) = k(x+3)(x2)(x3) h(0)=3 3=k(3)(2)(3) 3=18k

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Thankyou once again :D

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0if you're not busy, can you help me with one last question

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I think you know what you're doing, just be careful and don't rush through it.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Oh, sure. I think I can handle one more.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Find the equation of a cubic polynomial that gives a remainder of 3, when divided by (x+2)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0how would i approach this problem ?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Do you remember the remainder theorem?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0yes, the factor is equal to zero

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0It kind of goes like this. If (x+2) is a factor of the polynomial, then dividing by (x+2) would have a remainder of 0. And, if (x+2) is a factor, then x = 2 is a root of the polynomial. If (x+2) is not a factor, then f(2) = the remainder.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0but how would i use this info to make an equation, this is like working backwards from the norm :/

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Yes, a lot of what you're doing here is using concepts to 'unsolve' equations.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0If dividing by (x+2) gives a remainder of 3, then you know (2,3) is a solution to the equation.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0It's a pretty openended question; there will be many functions (infinite, really) that you could develop that have that point on it.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i still don't really get it, like i understand what it is asking for but i don't knw how to get to it :/

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0It wants a cubic function, so what does an equation for one of those look like?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Sure, something like that, so to be more general, start with \[y=ax^3+bx^2+cx+d\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0You know what x and y are, and three out of those four variables are free parameters, so choose whatever you want for those, then solve for the fourth one.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0You could even set three of them =0 if you wanted to be really lazy about it. (General math tip: be lazy whenever possible)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0so something like \[y=x^3+x^2+x+d \] ?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0hmm but "d" has to be a specific number right

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Yep, that's what you're solving for. Me, I went with y=ax^3, then solved for a.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0(but I'm lazy like that)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0ohh that way a would be 3/8 right

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0And if you want, you can verify that \[\large\frac{3}{8}x^3 \div (x+2)\] will give a remainder of 3.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[:. y=\frac{ 3 }{ 8 }x^3\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0thank you so much for your helppp, you're amazing :D
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.