Open study

is now brainly

With Brainly you can:

  • Get homework help from millions of students and moderators
  • Learn how to solve problems with step-by-step explanations
  • Share your knowledge and earn points by helping other students
  • Learn anywhere, anytime with the Brainly app!

A community for students.

One cell phone plan costs $39.95 per month. The first 500 minutes of usage are free. Each minute thereafter costs $.35. Write a rule that describes the total monthly cost as a function of the number of minutes of usage (over 500 minutes). Then find the number of minutes of usage over 500 minutes for a bill of $69.70?

Mathematics
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Join Brainly to access

this expert answer

SEE EXPERT ANSWER

To see the expert answer you'll need to create a free account at Brainly

Let c=cost and m=minutes of usage(over 500 minutes) c=.35m+39.95
So to find the number of minutes over 500 for a bill of $69.70, substitute 69.70 into the equation for c and solve for m
c = $39.95 + $0.35 e Now to find the number of minutes over 500 in a bill of $69.7 $69.7 = $39.95 + $0.35 e $29.75 = $0.35e $29.75 / $0.35 = e 85 min = e The person talked an extra 85 min over 500 min, or a total of 585 minutes used.

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

Yep

Not the answer you are looking for?

Search for more explanations.

Ask your own question