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A food store makes a 11–pound mixture of peanuts, almonds, and raisins. The cost of peanuts is $1.50 per pound, almonds cost $3.00 per pound, and raisins cost $1.50 per pound. The mixture calls for twice as many peanuts as almonds. The total cost of the mixture is $21.00. How much of each ingredient did the store use?
 one year ago
 one year ago
A food store makes a 11–pound mixture of peanuts, almonds, and raisins. The cost of peanuts is $1.50 per pound, almonds cost $3.00 per pound, and raisins cost $1.50 per pound. The mixture calls for twice as many peanuts as almonds. The total cost of the mixture is $21.00. How much of each ingredient did the store use?
 one year ago
 one year ago

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mskyegBest ResponseYou've already chosen the best response.1
Possible answers: 3 lbs peanuts, 6 lbs almonds, 2 lbs raisins 8 lbs peanuts, 1 lb almonds, 2 lbs raisins 6 lbs peanuts, 3 lbs almonds, 2 lbs raisins 8 lbs peanuts, 2 lbs almonds, 1 lb raisins
 one year ago

HyperChemistBest ResponseYou've already chosen the best response.1
In our school we had the exact same situation, ill give it a short try however, dont expect any explanations. btw I got it wrong. this is how I think I would solve it though.
 one year ago

HyperChemistBest ResponseYou've already chosen the best response.1
11x=p1.50+a3.00+r1.50,
 one year ago

HyperChemistBest ResponseYou've already chosen the best response.1
21$=p1.50+a3.00+r1.50
 one year ago

mskyegBest ResponseYou've already chosen the best response.1
wait if u got it wrong how do u know it won't be wrong this time?
 one year ago

HyperChemistBest ResponseYou've already chosen the best response.1
I dont im just trying.
 one year ago

HyperChemistBest ResponseYou've already chosen the best response.1
21$=p1.50+a3.00+r1.50 11p, ,6,3,3
 one year ago

HyperChemistBest ResponseYou've already chosen the best response.1
whenver I try to multiply it, it gives me a bigger number, therefoe this means that the amound of almonds is smaller then the amount of raisins, therfore giving a bigger value, however I do not know how to find what value would make this work... I trie,d and thanks for wating...
 one year ago

mskyegBest ResponseYou've already chosen the best response.1
I really appreciate you taking the time to try and solve this so thanx:)
 one year ago
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