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 2 years ago
A food store makes a 11–pound mixture of peanuts, almonds, and raisins. The cost of peanuts is $1.50 per pound, almonds cost $3.00 per pound, and raisins cost $1.50 per pound. The mixture calls for twice as many peanuts as almonds. The total cost of the mixture is $21.00. How much of each ingredient did the store use?
 2 years ago
A food store makes a 11–pound mixture of peanuts, almonds, and raisins. The cost of peanuts is $1.50 per pound, almonds cost $3.00 per pound, and raisins cost $1.50 per pound. The mixture calls for twice as many peanuts as almonds. The total cost of the mixture is $21.00. How much of each ingredient did the store use?

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mskyeg
 2 years ago
Best ResponseYou've already chosen the best response.1Possible answers: 3 lbs peanuts, 6 lbs almonds, 2 lbs raisins 8 lbs peanuts, 1 lb almonds, 2 lbs raisins 6 lbs peanuts, 3 lbs almonds, 2 lbs raisins 8 lbs peanuts, 2 lbs almonds, 1 lb raisins

HyperChemist
 2 years ago
Best ResponseYou've already chosen the best response.1In our school we had the exact same situation, ill give it a short try however, dont expect any explanations. btw I got it wrong. this is how I think I would solve it though.

HyperChemist
 2 years ago
Best ResponseYou've already chosen the best response.111x=p1.50+a3.00+r1.50,

HyperChemist
 2 years ago
Best ResponseYou've already chosen the best response.121$=p1.50+a3.00+r1.50

mskyeg
 2 years ago
Best ResponseYou've already chosen the best response.1wait if u got it wrong how do u know it won't be wrong this time?

HyperChemist
 2 years ago
Best ResponseYou've already chosen the best response.1I dont im just trying.

HyperChemist
 2 years ago
Best ResponseYou've already chosen the best response.121$=p1.50+a3.00+r1.50 11p, ,6,3,3

HyperChemist
 2 years ago
Best ResponseYou've already chosen the best response.1whenver I try to multiply it, it gives me a bigger number, therefoe this means that the amound of almonds is smaller then the amount of raisins, therfore giving a bigger value, however I do not know how to find what value would make this work... I trie,d and thanks for wating...

mskyeg
 2 years ago
Best ResponseYou've already chosen the best response.1I really appreciate you taking the time to try and solve this so thanx:)
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