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Silent_Sorrow
 2 years ago
Best ResponseYou've already chosen the best response.0A constant is simply a variable (with a nonzero coefficient) raised to the power of zero, so when you integrate say, 2 (which is the same as 2x^0) you'll get (2x^1)/1 Also when you differentiate a linear equation you get a constant (y=2x, dy/dx=2) which is just the reverse process of integration.

pasta
 2 years ago
Best ResponseYou've already chosen the best response.0Adding on SIlentSorrow's answer.if x is the problem the you can use another letter like c .ie int{1}dc.then u will still get c.

jamescarie
 2 years ago
Best ResponseYou've already chosen the best response.0Integration is simply a Summation over sum range. when u add sum constant in give range that will varry acording to range of integration.so it is variable,we can assume it as x.

adi171
 2 years ago
Best ResponseYou've already chosen the best response.0see actually u look to this question as this...... as integration is caleed as reverse process of of differentiation or simply the inverse function.... so when we find the derivative of a function x....we get 1........so what happens when we integrate 1.....???? js go the reverse process... i.e. 1=x(integration)

Jow
 2 years ago
Best ResponseYou've already chosen the best response.0First of all, when doing integrals, it's alway good to do th ereverse process: the derivatives. Imagine the following integral: \[\int\limits_{}^{}Cdx \rightarrow X\] Now let's derive the function f(x) = x dw:1350329860251:dw This is why. For definite integrals, you just take the difference between the upper and the lower limit, as follows: \[\int\limits_{5}^{7}Cdx \rightarrow X\] Now evaluate this integral between 7 and 5: 7  5 = 2. That's it.
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