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Silent_Sorrow Group TitleBest ResponseYou've already chosen the best response.0
A constant is simply a variable (with a nonzero coefficient) raised to the power of zero, so when you integrate say, 2 (which is the same as 2x^0) you'll get (2x^1)/1 Also when you differentiate a linear equation you get a constant (y=2x, dy/dx=2) which is just the reverse process of integration.
 one year ago

pasta Group TitleBest ResponseYou've already chosen the best response.0
Adding on SIlentSorrow's answer.if x is the problem the you can use another letter like c .ie int{1}dc.then u will still get c.
 one year ago

jamescarie Group TitleBest ResponseYou've already chosen the best response.0
Integration is simply a Summation over sum range. when u add sum constant in give range that will varry acording to range of integration.so it is variable,we can assume it as x.
 one year ago

adi171 Group TitleBest ResponseYou've already chosen the best response.0
see actually u look to this question as this...... as integration is caleed as reverse process of of differentiation or simply the inverse function.... so when we find the derivative of a function x....we get 1........so what happens when we integrate 1.....???? js go the reverse process... i.e. 1=x(integration)
 one year ago

Jow Group TitleBest ResponseYou've already chosen the best response.0
First of all, when doing integrals, it's alway good to do th ereverse process: the derivatives. Imagine the following integral: \[\int\limits_{}^{}Cdx \rightarrow X\] Now let's derive the function f(x) = x dw:1350329860251:dw This is why. For definite integrals, you just take the difference between the upper and the lower limit, as follows: \[\int\limits_{5}^{7}Cdx \rightarrow X\] Now evaluate this integral between 7 and 5: 7  5 = 2. That's it.
 one year ago
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