Looking for something else?

Not the answer you are looking for? Search for more explanations.

## More answers

Looking for something else?

Not the answer you are looking for? Search for more explanations.

- anonymous

H5P2 ... THIRD QUESTION
wat does this question want ?? i tried with various equations but dint work ??
need discussion !!

At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga.
Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus.
Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this

and **thousands** of other questions.

Get your **free** account and access **expert** answers to this and **thousands** of other questions

- anonymous

- chestercat

See more answers at brainly.com

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this

and **thousands** of other questions

- anonymous

do i have to substitute Vin=Vt initially and then continue solving ??

- anonymous

https://6002x.mitx.mit.edu/wiki/view/HW5solution/

- anonymous

is this the formula from the link (RS*K*(vIN-VT)+1-1sqrt((K*(vIN-VT)*RS+1)^2-K)) ? It's not shown all of it...

Looking for something else?

Not the answer you are looking for? Search for more explanations.

- anonymous

I tried with this - (RS*K*(vIN-VT)+1-sqrt((K*(vIN-VT)*RS+1)^2-K)) but doesn't work

- anonymous

(RS*K*(vIN-VT)+1-sqrt((K*(vIN-VT)*RS+1)^2-K^2*RS^2*(vIN-VT)^2))/(K*RS^2)

- anonymous

ohhh I saw only the half of it :) THX

- anonymous

your welcome im just about to start hw6 and every answer must be submited in a algabreic equation

- anonymous

(RS*K*(vIN-VT)+1-sqrt((K*(vIN-VT)*RS+1)^2-K^2*RS^2*(vIN-VT)^2))/(K*RS^2)

- anonymous

Here the source labeled VDD is the power supply.
Although the source follower has no voltage gain (actually a small loss) it has power gain: it presents a very high resistance to the signal source so it takes no power from the source, but it can drive a low resistance load. Also, because of feedback, which we will learn about later, the source follower is close to linear. In this problem we will investigate the large-signal characteristics of a source follower.
As usual, the MOSFET is set up to operate in the saturated region.
Write an algebraic expression for iDS in terms of K, vIN, vOUT, and VT. Remember, algebraic expressions are case sensitive.

- anonymous

Write an algebraic expression for iDS in terms of K, vIN, vOUT, and VT.

- anonymous

pls some one help me out???

Looking for something else?

Not the answer you are looking for? Search for more explanations.