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moongazer
Group Title
Find the value of x and y that will satisfy the system
 2 years ago
 2 years ago
moongazer Group Title
Find the value of x and y that will satisfy the system
 2 years ago
 2 years ago

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moongazer Group TitleBest ResponseYou've already chosen the best response.1
e^x  y = 2 e^x + y = 1
 2 years ago

Matrix65 Group TitleBest ResponseYou've already chosen the best response.0
is xy and x+y both exponents
 2 years ago

sauravshakya Group TitleBest ResponseYou've already chosen the best response.0
dw:1349690570593:dw
 2 years ago

sauravshakya Group TitleBest ResponseYou've already chosen the best response.0
Is that the question?
 2 years ago

Matrix65 Group TitleBest ResponseYou've already chosen the best response.0
introduce In both sides
 2 years ago

sauravshakya Group TitleBest ResponseYou've already chosen the best response.0
If that is the question then it has no real roots.
 2 years ago

moongazer Group TitleBest ResponseYou've already chosen the best response.1
how do I solve it?
 2 years ago

moongazer Group TitleBest ResponseYou've already chosen the best response.1
(e^x)  y = 2 (e^x) + y = 1
 2 years ago

moongazer Group TitleBest ResponseYou've already chosen the best response.1
sorry for the late reply
 2 years ago

sauravshakya Group TitleBest ResponseYou've already chosen the best response.0
Then Add equation one and two ........
 2 years ago

prawal Group TitleBest ResponseYou've already chosen the best response.0
i think no real solution... u might get5 imaginary....
 2 years ago

hartnn Group TitleBest ResponseYou've already chosen the best response.0
still e^x = 1/2 has no real solution for x
 2 years ago

sauravshakya Group TitleBest ResponseYou've already chosen the best response.0
Yes still no real solution
 2 years ago

hartnn Group TitleBest ResponseYou've already chosen the best response.0
y comes out to be 3/2
 2 years ago

hartnn Group TitleBest ResponseYou've already chosen the best response.0
u have choices/options ?
 2 years ago

sauravshakya Group TitleBest ResponseYou've already chosen the best response.0
But that will not be true.
 2 years ago

moongazer Group TitleBest ResponseYou've already chosen the best response.1
I don't have
 2 years ago

FaisalAyaz Group TitleBest ResponseYou've already chosen the best response.0
imaginary solution is how?
 2 years ago

sauravshakya Group TitleBest ResponseYou've already chosen the best response.0
dw:1349691346340:dw
 2 years ago

sauravshakya Group TitleBest ResponseYou've already chosen the best response.0
dw:1349691384296:dw
 2 years ago

moongazer Group TitleBest ResponseYou've already chosen the best response.1
that's also what I got
 2 years ago

hartnn Group TitleBest ResponseYou've already chosen the best response.0
http://www.wolframalpha.com/input/?i=e%5Ex+%3D+1%2F2
 2 years ago

moongazer Group TitleBest ResponseYou've already chosen the best response.1
Isn't it that e^(ln 1/2) =1/2 ?
 2 years ago

moongazer Group TitleBest ResponseYou've already chosen the best response.1
@hartnn @sauravshakya
 2 years ago

hartnn Group TitleBest ResponseYou've already chosen the best response.0
yes, thats correct but y did u caculate that ?
 2 years ago

hartnn Group TitleBest ResponseYou've already chosen the best response.0
i meant yes, thats correct but why did u caculate that ?
 2 years ago

prawal Group TitleBest ResponseYou've already chosen the best response.0
e^(ln 1/2) =1/2 this is hell wrong... !! the equation is not defined...
 2 years ago

moongazer Group TitleBest ResponseYou've already chosen the best response.1
to find y
 2 years ago

moongazer Group TitleBest ResponseYou've already chosen the best response.1
I got y=3/2
 2 years ago

hartnn Group TitleBest ResponseYou've already chosen the best response.0
yes, there are no real solutions to this.....
 2 years ago

prawal Group TitleBest ResponseYou've already chosen the best response.0
impossible man..
 2 years ago

moongazer Group TitleBest ResponseYou've already chosen the best response.1
What should I write on my paper?
 2 years ago

hartnn Group TitleBest ResponseYou've already chosen the best response.0
i think u just write e^x=1/2, y =3/2 and leave it
 2 years ago

prawal Group TitleBest ResponseYou've already chosen the best response.0
u can do the above thing or write no real solution...
 2 years ago

hartnn Group TitleBest ResponseYou've already chosen the best response.0
*and write no real solution
 2 years ago

moongazer Group TitleBest ResponseYou've already chosen the best response.1
I think I got the answer
 2 years ago

jhonyy9 Group TitleBest ResponseYou've already chosen the best response.1
ln of a negativ number  how it is possible ?  little up check it please !!!
 2 years ago

jhonyy9 Group TitleBest ResponseYou've already chosen the best response.1
@hartnn ,@sauravshakya
 2 years ago

moongazer Group TitleBest ResponseYou've already chosen the best response.1
I got x = ln 1 and y = 1
 2 years ago

jhonyy9 Group TitleBest ResponseYou've already chosen the best response.1
@sauravshakya
 2 years ago

moongazer Group TitleBest ResponseYou've already chosen the best response.1
I think that is the answer
 2 years ago

jhonyy9 Group TitleBest ResponseYou've already chosen the best response.1
check where is defined the logarithm funvtion please
 2 years ago

jhonyy9 Group TitleBest ResponseYou've already chosen the best response.1
function  sorry
 2 years ago

moongazer Group TitleBest ResponseYou've already chosen the best response.1
I forgot to add e^x
 2 years ago

jhonyy9 Group TitleBest ResponseYou've already chosen the best response.1
e^x  y = 2 e^x + y = 1
 2 years ago

hartnn Group TitleBest ResponseYou've already chosen the best response.0
ln(1), 1 does not satisfy 2nd equation ln(1) is imaginary = i\(\pi\)
 2 years ago

jhonyy9 Group TitleBest ResponseYou've already chosen the best response.1
ln(1) how do you mean this ?
 2 years ago

moongazer Group TitleBest ResponseYou've already chosen the best response.1
it should be ln 1/2 =x and 3/2=y
 2 years ago

jhonyy9 Group TitleBest ResponseYou've already chosen the best response.1
when by definition logb X so x need being allways positiv
 2 years ago

hartnn Group TitleBest ResponseYou've already chosen the best response.0
\(e^{i\pi}=1\) by euler's relation
 2 years ago

jhonyy9 Group TitleBest ResponseYou've already chosen the best response.1
e^x  y = 2 e^x + y = 1 so and for these equations ?
 2 years ago

hartnn Group TitleBest ResponseYou've already chosen the best response.0
but if x is imaginary, y must be imaginary also, right ?
 2 years ago

jhonyy9 Group TitleBest ResponseYou've already chosen the best response.1
but in this case i think that is very simple us ln to both sides for every two equations and will get the right answers
 2 years ago

moongazer Group TitleBest ResponseYou've already chosen the best response.1
when you substitute x with ln 1/2 it will be e^(ln 1/2)  y = 2 then 1/2y=2 y=3/2
 2 years ago

moongazer Group TitleBest ResponseYou've already chosen the best response.1
I think my teacher doesn't need to know the decimal value of x.
 2 years ago

hartnn Group TitleBest ResponseYou've already chosen the best response.0
ok, then write that....
 2 years ago

moongazer Group TitleBest ResponseYou've already chosen the best response.1
ok, thanks for the answers :)
 2 years ago

moongazer Group TitleBest ResponseYou've already chosen the best response.1
why is it ln (negative number) is undefined?
 2 years ago

jhonyy9 Group TitleBest ResponseYou've already chosen the best response.1
by domain definition of logarithms
 2 years ago

jhonyy9 Group TitleBest ResponseYou've already chosen the best response.1
you have learned it sure  i think ,yes ?
 2 years ago

moongazer Group TitleBest ResponseYou've already chosen the best response.1
because of the graph
 2 years ago

jhonyy9 Group TitleBest ResponseYou've already chosen the best response.1
good so than all is understood it right good luck bye
 2 years ago

moongazer Group TitleBest ResponseYou've already chosen the best response.1
Thanks :) do you know how to decompose a function?
 2 years ago

jhonyy9 Group TitleBest ResponseYou've already chosen the best response.1
how do you think it ?
 2 years ago

moongazer Group TitleBest ResponseYou've already chosen the best response.1
partial fractions the one with cases. I got an odd looking expression
 2 years ago

moongazer Group TitleBest ResponseYou've already chosen the best response.1
i'll post it
 2 years ago
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