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moongazerBest ResponseYou've already chosen the best response.1
e^x  y = 2 e^x + y = 1
 one year ago

Matrix65Best ResponseYou've already chosen the best response.0
is xy and x+y both exponents
 one year ago

sauravshakyaBest ResponseYou've already chosen the best response.0
dw:1349690570593:dw
 one year ago

sauravshakyaBest ResponseYou've already chosen the best response.0
Is that the question?
 one year ago

Matrix65Best ResponseYou've already chosen the best response.0
introduce In both sides
 one year ago

sauravshakyaBest ResponseYou've already chosen the best response.0
If that is the question then it has no real roots.
 one year ago

moongazerBest ResponseYou've already chosen the best response.1
(e^x)  y = 2 (e^x) + y = 1
 one year ago

moongazerBest ResponseYou've already chosen the best response.1
sorry for the late reply
 one year ago

sauravshakyaBest ResponseYou've already chosen the best response.0
Then Add equation one and two ........
 one year ago

prawalBest ResponseYou've already chosen the best response.0
i think no real solution... u might get5 imaginary....
 one year ago

hartnnBest ResponseYou've already chosen the best response.0
still e^x = 1/2 has no real solution for x
 one year ago

sauravshakyaBest ResponseYou've already chosen the best response.0
Yes still no real solution
 one year ago

hartnnBest ResponseYou've already chosen the best response.0
u have choices/options ?
 one year ago

sauravshakyaBest ResponseYou've already chosen the best response.0
But that will not be true.
 one year ago

FaisalAyazBest ResponseYou've already chosen the best response.0
imaginary solution is how?
 one year ago

sauravshakyaBest ResponseYou've already chosen the best response.0
dw:1349691346340:dw
 one year ago

sauravshakyaBest ResponseYou've already chosen the best response.0
dw:1349691384296:dw
 one year ago

moongazerBest ResponseYou've already chosen the best response.1
that's also what I got
 one year ago

hartnnBest ResponseYou've already chosen the best response.0
http://www.wolframalpha.com/input/?i=e%5Ex+%3D+1%2F2
 one year ago

moongazerBest ResponseYou've already chosen the best response.1
Isn't it that e^(ln 1/2) =1/2 ?
 one year ago

moongazerBest ResponseYou've already chosen the best response.1
@hartnn @sauravshakya
 one year ago

hartnnBest ResponseYou've already chosen the best response.0
yes, thats correct but y did u caculate that ?
 one year ago

hartnnBest ResponseYou've already chosen the best response.0
i meant yes, thats correct but why did u caculate that ?
 one year ago

prawalBest ResponseYou've already chosen the best response.0
e^(ln 1/2) =1/2 this is hell wrong... !! the equation is not defined...
 one year ago

hartnnBest ResponseYou've already chosen the best response.0
yes, there are no real solutions to this.....
 one year ago

moongazerBest ResponseYou've already chosen the best response.1
What should I write on my paper?
 one year ago

hartnnBest ResponseYou've already chosen the best response.0
i think u just write e^x=1/2, y =3/2 and leave it
 one year ago

prawalBest ResponseYou've already chosen the best response.0
u can do the above thing or write no real solution...
 one year ago

hartnnBest ResponseYou've already chosen the best response.0
*and write no real solution
 one year ago

moongazerBest ResponseYou've already chosen the best response.1
I think I got the answer
 one year ago

jhonyy9Best ResponseYou've already chosen the best response.1
ln of a negativ number  how it is possible ?  little up check it please !!!
 one year ago

jhonyy9Best ResponseYou've already chosen the best response.1
@hartnn ,@sauravshakya
 one year ago

moongazerBest ResponseYou've already chosen the best response.1
I got x = ln 1 and y = 1
 one year ago

moongazerBest ResponseYou've already chosen the best response.1
I think that is the answer
 one year ago

jhonyy9Best ResponseYou've already chosen the best response.1
check where is defined the logarithm funvtion please
 one year ago

jhonyy9Best ResponseYou've already chosen the best response.1
e^x  y = 2 e^x + y = 1
 one year ago

hartnnBest ResponseYou've already chosen the best response.0
ln(1), 1 does not satisfy 2nd equation ln(1) is imaginary = i\(\pi\)
 one year ago

jhonyy9Best ResponseYou've already chosen the best response.1
ln(1) how do you mean this ?
 one year ago

moongazerBest ResponseYou've already chosen the best response.1
it should be ln 1/2 =x and 3/2=y
 one year ago

jhonyy9Best ResponseYou've already chosen the best response.1
when by definition logb X so x need being allways positiv
 one year ago

hartnnBest ResponseYou've already chosen the best response.0
\(e^{i\pi}=1\) by euler's relation
 one year ago

jhonyy9Best ResponseYou've already chosen the best response.1
e^x  y = 2 e^x + y = 1 so and for these equations ?
 one year ago

hartnnBest ResponseYou've already chosen the best response.0
but if x is imaginary, y must be imaginary also, right ?
 one year ago

jhonyy9Best ResponseYou've already chosen the best response.1
but in this case i think that is very simple us ln to both sides for every two equations and will get the right answers
 one year ago

moongazerBest ResponseYou've already chosen the best response.1
when you substitute x with ln 1/2 it will be e^(ln 1/2)  y = 2 then 1/2y=2 y=3/2
 one year ago

moongazerBest ResponseYou've already chosen the best response.1
I think my teacher doesn't need to know the decimal value of x.
 one year ago

hartnnBest ResponseYou've already chosen the best response.0
ok, then write that....
 one year ago

moongazerBest ResponseYou've already chosen the best response.1
ok, thanks for the answers :)
 one year ago

moongazerBest ResponseYou've already chosen the best response.1
why is it ln (negative number) is undefined?
 one year ago

jhonyy9Best ResponseYou've already chosen the best response.1
by domain definition of logarithms
 one year ago

jhonyy9Best ResponseYou've already chosen the best response.1
you have learned it sure  i think ,yes ?
 one year ago

moongazerBest ResponseYou've already chosen the best response.1
because of the graph
 one year ago

jhonyy9Best ResponseYou've already chosen the best response.1
good so than all is understood it right good luck bye
 one year ago

moongazerBest ResponseYou've already chosen the best response.1
Thanks :) do you know how to decompose a function?
 one year ago

moongazerBest ResponseYou've already chosen the best response.1
partial fractions the one with cases. I got an odd looking expression
 one year ago
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