Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing

This Question is Closed

Isaacisbeast123Best ResponseYou've already chosen the best response.1
do you need the whole process??
 one year ago

Isaacisbeast123Best ResponseYou've already chosen the best response.1
Either use this short equation (arra[mid]!=num) //NOTE THE EXTRA flush AT END. //FYI endl = flush + "\n" (so that can also be used) cout<<"\nnot found" << flush ; else if (arra[mid]==num) cout<<"location is\t"<<mid; getch(); }
 one year ago

Isaacisbeast123Best ResponseYou've already chosen the best response.1
Or if your looking for advanced use/// #include<iostream.h> #include<conio.h> #define siz 10 void main() { int arra[siz]={0}; int mid,beg=1,end=siz,loca=0,num; clrscr(); cout<<"Please Enter The Elements Of Array\n"; for(loca=0;loca<siz;loca++) { cin>>arra[loca]; } cout<<"Please enter the required number"; cin>>num; mid=(loca)/2; while(beg<end&&arra[mid]!=num) { if(num<arra[mid]) end=mid1; else beg=mid+1; mid=(beg+end)/2; } if (arra[mid]!=num) cout<<"\nnot found"; else if (arra[mid]==num) cout<<"location is\t"<<mid; getch(); }
 one year ago

krithikaBest ResponseYou've already chosen the best response.0
Try this too if you want #include<iostream.h> #include<conio.h> void main() { int a[20],n,i,top,bottom,mid,f,s; clrscr(); cout<<"Enter the value of n:"; cin>>n; cout<<"\nEnter the values:\n"; for(i=0;i<n;i++) { cin>>a[i]; } cout<<"Enter the element to be searched:"; cin>>s; top=0; bottom=n1; f=0; while(top<=bottom && f==0) { mid=(top+bottom)/2; if(s>a[mid]) { top=mid+1; } else if(s<a[mid]) { bottom=mid1; } else f=1; } if(f==1) cout<<"Element found"; else cout<<"Element not found."; getch(); }
 one year ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.