## pottersheep How do I find the invariant points of these two equations? Something about y = +- 1? y= (x^2 - 3x -10) and y = (x^2 - 3x -10)^-1 one year ago one year ago

1. andriod09

anything that is a radical of 1 is always it's self, and if $y=\pm-1$ then wouldn't y be one of the following? $(y_1=-1)(y_2=+1)$